Masteries · Jason GlowneyArithmoí Book 1

Masteries

1.1.15 The SymmetricSymmetric Groups

We can now define the sym­met­ric group SnS_{n}, as fol­lows:

De­f­i­n­i­tion (1.1.78) – The Sym­met­ric Group 𝐒𝐧\mathbf{S}_{\mathbf{n}}is a group under com­po­si­tion, with a set of bi­jec­tive per­mu­ta­tion el­e­ments AA

SA={ϕ|ϕ:A→A is a function that is bijective}.S_{A} = \left\{ \phi \middle| \phi:A \rightarrow A\ is\ a\ function\ that\ is\ bijective \right\}.

By com­bi­na­torics, the SAS_{A} group will have A!A!el­e­ments x={1,2,3,…,X}x = \left\{ 1,2,3,\ldots,X \right\}, and if X≥3X \geq 3, then SAS_{A} is non-abelian. We will use S3S_{3} as an ex­am­ple, noting that any per­mu­ta­tion ϕ\phi is both an in­jec­tive and sur­jec­tive func­tion (bi­jec­tive) from the set of three in­te­gers {1,2,3}\{ 1,2,3\}, onto itself. The S3S_{3} sym­me­try group rep­re­sents the ways to per­mute the set of three in­te­gers as men­tioned before, and one way to rep­re­sent its set of 3!=63! = 6 el­e­ments, is as fol­lows

ϵ=(123123),   x=(123132),   y=(123231),\epsilon = \begin{pmatrix} 1 & 2 & 3 \\ 1 & 2 & 3 \end{pmatrix},\ \ \ x = \begin{pmatrix} 1 & 2 & 3 \\ 1 & 3 & 2 \end{pmatrix},\ \ \ y = \begin{pmatrix} 1 & 2 & 3 \\ 2 & 3 & 1 \end{pmatrix},
y2=(123312),   xy=(123321),   xy2=(123213),\begin{array}{r} y^{2} = \begin{pmatrix} 1 & 2 & 3 \\ 3 & 1 & 2 \end{pmatrix},\ \ \ xy = \begin{pmatrix} 1 & 2 & 3 \\ 3 & 2 & 1 \end{pmatrix},\ \ \ xy^{2} = \begin{pmatrix} 1 & 2 & 3 \\ 2 & 1 & 3 \end{pmatrix}, \end{array}
(1.1.79)

where ϵ\epsilon is the iden­ti­ty per­mu­ta­tion, x, xy, xy2x,\ xy,\ xy^{2} rep­re­sent the three two-number swaps, and y,y2y,y^{2} are cyclic per­mu­ta­tions in the left and right di­rec­tions. Keep­ing Cayley's The­o­rem in mind con­cern­ing the sym­met­ric groups, we can see that a proper un­der­stand­ing of them yields a deep un­der­stand­ing of all groups. As we pro­ceed, we will find the basis of the matrix groups dis­cussed are rooted in these sym­met­ric groups.