Masteries · Jason GlowneyArithmoí Book 1

Masteries

1.6.3 Matrix-Based Infinite Integration and Differentiation

The pre­vi­ous sec­tion was an an­a­lyt­ic treat­ment of in­fi­nite in­te­gra­tion and in­fi­nite dif­fer­en­ti­a­tion, and in this sec­tion, we apply in­te­gra­tion and dif­fer­en­ti­a­tion op­er­a­tors to demon­strate these in­fi­nite func­tions in matrix-based forms. Start­ing with the in­fi­nite in­te­gra­tion

fℂ−∞(𝒸θrm)=limk→∞⁡(D(θrm)−k[𝒸θrm]) {𝒸=ln⁡(e), ∀ θrm∈ℂm }=eθrm,\begin{array}{r} f_{\mathbb{C}}^{- \infty}\left( \mathcal{c}\theta_{r}^{m} \right) = \lim_{k \rightarrow \infty}\left( D_{\left( \theta_{r}^{m} \right)}^{- k}\left\lbrack \mathcal{c}\theta_{r}^{m} \right\rbrack \right)\ \left\{ \mathcal{c} =\ln(e),\ \forall\ \theta_{r}^{m} \in \mathbb{C}^{m}\ \right\} = e^{\theta_{r}^{m}}, \end{array}
(1.6.44)

we define the in­te­gra­tion op­er­a­tor ψ(θr(m,X1))−n{\psi\left( \theta_{r}^{\left( m,X_{1} \right)} \right)}^{- n}, for the iX1{iX}_{1}- type matrix, as

ψ(θr(m,X1))−n=(iθ1n0000iθ2n0iθ3n0),\begin{array}{r} {\psi\left( \theta_{r}^{\left( m,X_{1} \right)} \right)}^{- n} = \begin{pmatrix} \frac{{i\theta}_{1}}{n} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{n} \\ 0 & \frac{{i\theta}_{3}}{n} & 0 \end{pmatrix}, \end{array}
(1.6.45)

where the en­tries of the matrix will act by way of a prod­uct with an­oth­er matrix to per­form the in­te­gra­tion op­er­a­tion with re­spect to θj\theta_{j}. We denote the iX1iX_{1} matrix, as

iX1=(iθ10000iθ20iθ30)=𝔰𝔲(θ1(3,X1))1,\begin{array}{r} {iX}_{1} = \begin{pmatrix} i\theta_{1} & 0 & 0 \\ 0 & 0 & {i\theta}_{2} \\ 0 & {i\theta}_{3} & 0 \end{pmatrix}= \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{1}, \end{array}
(1.6.46)

for 𝔰𝔲(θ1(3,X1))1\mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{1}, a Lie al­ge­bra el­e­ment of unit radial mag­ni­tude, r=1r = 1, with the su­per­script (3,X1)\left( 3,X_{1} \right), in­di­cat­ing the ℂ3\mathbb{C}^{3} di­men­sion­al space, and an X1X_{1}-type matrix. So, it should be noted that θrm\theta_{r}^{m} is de­fined ∈ℂ\in \mathbb{C}, but in this case we have a unit radial mag­ni­tude, which means that we are work­ing with com­plex num­bers that lie on the com­plex unit sphere, and specif­i­cal­ly, θ1m=eiθ\theta_{1}^{m} = e^{i\theta}.

Now, we can ex­press the in­fi­nite in­te­gra­tion func­tion in a matrix-based form, as

fℂ−n(θ1(3,X1))=ϵ+∑n=1∞ψ(θ1(3,X1))−n×𝔰𝔲(θ1(3,X1))n−1=eiθ1(3,X1)f_{\mathbb{C}}^{- n}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right) = \epsilon + \sum_{n = 1}^{\infty}{\psi\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)}^{- n}\times \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{n - 1} = e^{{i\theta}_{1}^{\left( 3,X_{1} \right)}}
=ϵ+∑n=1∞[(iθ1n0000iθ2n0iθ3n0)×(iθ10000iθ20iθ30)n−1],\begin{array}{r} = \epsilon + \sum_{n = 1}^{\infty}\left\lbrack \begin{pmatrix} \frac{{i\theta}_{1}}{n} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{n} \\ 0 & \frac{i\theta_{3}}{n} & 0 \end{pmatrix} \times \begin{pmatrix} {i\theta}_{1} & 0 & 0 \\ 0 & 0 & {i\theta}_{2} \\ 0 & {i\theta}_{3} & 0 \end{pmatrix}^{n - 1} \right\rbrack, \end{array}
(1.6.47)

where the ex­po­nent value nn, for the op­er­a­tor ψ(θ1(3,X1))−n{\psi\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)}^{- n}, de­ter­mines the in­te­gra­tion order and the de­nom­i­na­tor's value in the matrix, and ϵ\epsilon is the iden­ti­ty matrix

𝔰𝔲(θ1(3,X1))0=(100010001).\begin{array}{r} \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{0} = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{pmatrix}. \end{array}
(1.6.48)

Con­tin­u­ing the in­te­gra­tion process, the first-order in­te­gral yields the 𝔰𝔲(θ1(3,X1))1\mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{1} in­te­gra­tion matrix of el­e­ments

ψ(θ1(3,X1))−1×𝔰𝔲(θ1(3,X1))0=(iθ110000iθ210iθ310)×𝔰𝔲(θ1(3,X1))0=(iθ10000iθ20iθ30)=𝔰𝔲(θ1(3,X1))1.\begin{array}{r} {\psi\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)}^{- 1}\times \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{0} = \begin{pmatrix} \frac{{i\theta}_{1}}{1} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{1} \\ 0 & \frac{{i\theta}_{3}}{1} & 0 \end{pmatrix}\times \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{0} = \begin{pmatrix} {i\theta}_{1} & 0 & 0 \\ 0 & 0 & {i\theta}_{2} \\ 0 & {i\theta}_{3} & 0 \end{pmatrix}= \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{1}. \end{array}
(1.6.49)

and for the evolv­ing process, we find the next three Lie al­ge­bras for 𝔰𝔲(θ1(3,X1))n\mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{n}:

ψ(θ1(3,X1))−2×𝔰𝔲(θ1(3,X1))1=(iθ120000iθ220iθ320)×𝔰𝔲(θ1(3,X1))1=(−θ122000−θ2θ32000−θ2θ32)=𝔰𝔲(θ1(3,X1))2,\begin{array}{r} {\psi\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)}^{- 2}\times \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{1} = \begin{pmatrix} \frac{{i\theta}_{1}}{2} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{2} \\ 0 & \frac{{i\theta}_{3}}{2} & 0 \end{pmatrix}\times \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{1} = \begin{pmatrix} - \frac{\theta_{1}^{2}}{2} & 0 & 0 \\ 0 & - \frac{\theta_{2}\theta_{3}}{2} & 0 \\ 0 & 0 & - \frac{\theta_{2}\theta_{3}}{2} \end{pmatrix}= \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{2}, \end{array}
(1.6.50)
ψ(θ1(3,X1))−3×𝔰𝔲(θ1(3,X1))2=(iθ130000iθ230iθ330)×𝔰𝔲(θ1(3,X1))2=(−iθ133!0000−iθ22θ33!0−iθ2θ323!0)=𝔰𝔲(θ1(3,X1))3,\begin{array}{r} {\psi\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)}^{- 3}\times \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{2} = \begin{pmatrix} \frac{{i\theta}_{1}}{3} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{3} \\ 0 & \frac{{i\theta}_{3}}{3} & 0 \end{pmatrix}\times \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{2} = \begin{pmatrix} - \frac{i\theta_{1}^{3}}{3!} & 0 & 0 \\ 0 & 0 & - \frac{i\theta_{2}^{2}\theta_{3}}{3!} \\ 0 & - \frac{i\theta_{2}\theta_{3}^{2}}{3!} & 0 \end{pmatrix}= \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{3}, \end{array}
(1.6.51)
ψ(θ1(3,X1))−4×𝔰𝔲(θ1(3,X1))3=(iθ140000iθ240iθ340)×𝔰𝔲(θ1(3,X1))3=(θ144!000θ22θ324!000θ22θ324!)=𝔰𝔲(θ1(3,X1))4.\begin{array}{r} {\psi\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)}^{- 4}\times \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{3} = \begin{pmatrix} \frac{{i\theta}_{1}}{4} & 0 & 0 \\ 0 & 0 & \frac{i\theta_{2}}{4} \\ 0 & \frac{{i\theta}_{3}}{4} & 0 \end{pmatrix}\times \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{3} = \begin{pmatrix} \frac{\theta_{1}^{4}}{4!} & 0 & 0 \\ 0 & \frac{\theta_{2}^{2}\theta_{3}^{2}}{4!} & 0 \\ 0 & 0 & \frac{\theta_{2}^{2}\theta_{3}^{2}}{4!} \end{pmatrix}= \mathfrak{su}\left( \theta_{1}^{\left( 3,X_{1} \right)} \right)^{4}. \end{array}
(1.6.52)

For the ex­pres­sions above, notice that al­ter­nat­ing in­te­gra­tions occur for the θ2,θ3\theta_{2}{,\theta}_{3} vari­ables, which is re­lat­ed to whether we have an even or odd ex­po­nent for the op­er­a­tor's nn. Odd in­te­gra­tion op­er­a­tors will yield el­e­ments of the odd trigono­met­ric func­tions, and even in­te­gra­tion op­er­a­tors will yield el­e­ments of the even trigono­met­ric func­tions. So, this fash­ion of in­fi­nite in­te­gra­tion fits nicely into the con­text of finite group theory, as we are using a mul­ti­pli­ca­tion op­er­a­tion with Lie al­ge­bras to cal­cu­late the matrix ex­po­nen­tial map­ping, for each 𝔰𝔲(θrm)n\mathfrak{su}\left( \theta_{r}^{m} \right)^{n}, re­cur­sive­ly re­lat­ed to its 𝔰𝔲(θrm)n−1\mathfrak{su}\left( \theta_{r}^{m} \right)^{n - 1} pre­de­ces­sor.

Re­gard­ing the in­fi­nite in­te­gra­tion sum­ma­tion of Lie al­ge­bra el­e­ments, de­not­ed as 𝔖𝔘(θrm)n\mathfrak{SU}\left( \theta_{r}^{m} \right)^{n}, we define the fol­low­ing:

De­f­i­n­i­tion (1.6.53) – 𝔖𝔘(𝛉𝐫(𝐦))𝐧\mathfrak{SU}\left( \mathbf{\theta}_{\mathbf{r}}^{\left( \mathbf{m} \right)} \right)^{\mathbf{n}} is the sum­ma­tion of Lie al­ge­bra el­e­ments 𝔰𝔲(θrm)n∈𝔤\mathfrak{su}\left( \theta_{r}^{m} \right)^{n}\in \mathfrak{g}, to order-nn, form­ing the el­e­ments of the in­fi­nite series of in­te­gra­tion/matrix ex­po­nen­ti­a­tion,

𝔖𝔘(θrm)n=∑k=0n 𝔰𝔲(θrm)k.\mathfrak{SU}\left( \theta_{r}^{m} \right)^{n} = \sum_{k = 0}^{n}{\ \mathfrak{su}\left( \theta_{r}^{m} \right)^{k}.}

Given in the op­er­a­tor de­f­i­n­i­tion of ψ(θrm)−n{\psi\left( \theta_{r}^{m} \right)}^{- n}, the neg­a­tive ex­po­nent −n- n, de­notes in­te­gra­tion, and now we con­sid­er anal­o­gous no­ta­tion for in­te­gra­tions of the Lie al­ge­bra el­e­ments 𝔰𝔲(θrm)n,\mathfrak{su}\left( \theta_{r}^{m} \right)^{n},in the de­f­i­n­i­tion that fol­lows.

De­f­i­n­i­tion (1.6.54) – 𝛙(𝛉𝐫𝐦)−𝔫{\mathbf{\psi}\left( \mathbf{\theta}_{\mathbf{r}}^{\mathbf{m}} \right)}^{- \mathfrak{n}} is the in­fi­nite fac­to­r­i­al in­te­gra­tion op­er­a­tor de­fined, as

ψ(θrm)−𝔫=(iθ1𝔫0000iθ2𝔫0iθ3𝔫0),{\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} = \begin{pmatrix} \frac{{i\theta}_{1}}{\mathfrak{n}} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{\mathfrak{n}} \\ 0 & \frac{{i\theta}_{3}}{\mathfrak{n}} & 0 \end{pmatrix},

which forms prod­ucts with Lie al­ge­bra el­e­ments 𝔰𝔲(θrm)n∈𝔤\ \mathfrak{su}\left( \theta_{r}^{m} \right)^{n}\in \mathfrak{g}, with the rec­i­p­ro­cal fac­to­r­i­al el­e­ments 𝔫𝐤\mathfrak{n}^{\mathbf{k}}, de­fined by

(𝔫𝐤)=𝐤!=Γ(k+1).\left( \mathfrak{n}^{\mathbf{k}} \right)= \mathbf{k}! = \Gamma(k + 1)\mathbf{.}

De­f­i­n­i­tion (1.6.55) – 𝔖𝔘(𝛉𝐫𝐦)−𝔫𝐤\mathfrak{SU}\left( \mathbf{\theta}_{\mathbf{r}}^{\mathbf{m}} \right)^{\mathbf{-}\mathfrak{n}^{\mathbf{k}}} is the sum­ma­tion of the Lie al­ge­bra el­e­ments 𝔰𝔲(θrm)−𝔫𝐣∈𝔤\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{j}}}\in \mathfrak{g}, to fac­to­r­i­al and ex­po­nent order-k, that form the el­e­ments of the in­fi­nite series of in­te­gra­tion/matrix ex­po­nen­ti­a­tion

𝔖𝔘(A)−𝔫𝐤=∑𝐣=0𝐤 𝔰𝔲(A)−𝔫𝐣.\mathfrak{SU}(A)^{- \mathfrak{n}^{\mathbf{k}}} = \sum_{\mathbf{j} = 0}^{\mathbf{k}}{\ \mathfrak{su}(A)^{- \mathfrak{n}^{\mathbf{j}}}.}

Using the in­fi­nite fac­to­r­i­al in­te­gra­tion op­er­a­tor, we can ex­press the Lie al­ge­bra el­e­ments 𝔰𝔲(θrm)n\mathfrak{su}\left( \theta_{r}^{m} \right)^{n}, as fol­lows:

ψ(θrm)−𝔫×𝔰𝔲(θrm)𝔫𝟎=(iθ1𝔫𝟏0000iθ2𝔫𝟏0iθ3𝔫𝟏0)(1𝔫𝟎0001𝔫𝟎0001𝔫𝟎)=(iθ1𝔫𝟏0000iθ2𝔫𝟏0iθ3𝔫𝟏0)=𝔰𝔲(θrm)−𝔫𝟏,\begin{array}{r} {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{\mathfrak{n}^{\mathbf{0}}} = \begin{pmatrix} \frac{{i\theta}_{1}}{\mathfrak{n}^{\mathbf{1}}} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{\mathfrak{n}^{\mathbf{1}}} \\ 0 & \frac{{i\theta}_{3}}{\mathfrak{n}^{\mathbf{1}}} & 0 \end{pmatrix}\begin{pmatrix} \frac{1}{\mathfrak{n}^{\mathbf{0}}} & 0 & 0 \\ 0 & \frac{1}{\mathfrak{n}^{\mathbf{0}}} & 0 \\ 0 & 0 & \frac{1}{\mathfrak{n}^{\mathbf{0}}} \end{pmatrix} = \begin{pmatrix} \frac{{i\theta}_{1}}{\mathfrak{n}^{\mathbf{1}}} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{\mathfrak{n}^{\mathbf{1}}} \\ 0 & \frac{i\theta_{3}}{\mathfrak{n}^{\mathbf{1}}} & 0 \end{pmatrix}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{1}}}, \end{array}
(1.6.56)
ψ(θrm)−𝔫×𝔰𝔲(θrm)−𝔫𝟏=(iθ1𝔫𝟏0000iθ2𝔫𝟏0iθ3𝔫𝟏0)(iθ1𝔫𝟏0000iθ2𝔫𝟏0iθ3𝔫𝟏0)=(−θ12𝔫𝟐000−θ2θ3𝔫𝟐000−θ2θ3𝔫𝟐)=𝔰𝔲(θrm)−𝔫𝟐 ,\begin{array}{r} {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{1}}} = \begin{pmatrix} \frac{{i\theta}_{1}}{\mathfrak{n}^{\mathbf{1}}} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{\mathfrak{n}^{\mathbf{1}}} \\ 0 & \frac{{i\theta}_{3}}{\mathfrak{n}^{\mathbf{1}}} & 0 \end{pmatrix}\begin{pmatrix} \frac{{i\theta}_{1}}{\mathfrak{n}^{\mathbf{1}}} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{\mathfrak{n}^{\mathbf{1}}} \\ 0 & \frac{{i\theta}_{3}}{\mathfrak{n}^{\mathbf{1}}} & 0 \end{pmatrix} = \begin{pmatrix} - \frac{\theta_{1}^{2}}{\mathfrak{n}^{\mathbf{2}}} & 0 & 0 \\ 0 & - \frac{\theta_{2}\theta_{3}}{\mathfrak{n}^{\mathbf{2}}} & 0 \\ 0 & 0 & - \frac{\theta_{2}\theta_{3}}{\mathfrak{n}^{\mathbf{2}}} \end{pmatrix}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}}}\ , \end{array}
(1.6.57)
ψ(θrm)−𝔫×𝔰𝔲(θrm)−𝔫𝟐=(iθ1𝔫𝟏0000iθ2𝔫𝟏0iθ3𝔫𝟏0)(−θ12𝔫𝟐000−θ2θ3𝔫𝟐000−θ2θ3𝔫𝟐)=(−iθ13𝔫𝟑0000−iθ22θ3𝔫𝟑0−iθ2θ32𝔫𝟑0)=𝔰𝔲(θrm)−𝔫𝟑,\begin{array}{r} {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}}} = \begin{pmatrix} \frac{{i\theta}_{1}}{\mathfrak{n}^{\mathbf{1}}} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{\mathfrak{n}^{\mathbf{1}}} \\ 0 & \frac{{i\theta}_{3}}{\mathfrak{n}^{\mathbf{1}}} & 0 \end{pmatrix}\begin{pmatrix} - \frac{\theta_{1}^{2}}{\mathfrak{n}^{\mathbf{2}}} & 0 & 0 \\ 0 & - \frac{\theta_{2}\theta_{3}}{\mathfrak{n}^{\mathbf{2}}} & 0 \\ 0 & 0 & - \frac{\theta_{2}\theta_{3}}{\mathfrak{n}^{\mathbf{2}}} \end{pmatrix} = \begin{pmatrix} - \frac{{i\theta}_{1}^{3}}{\mathfrak{n}^{\mathbf{3}}} & 0 & 0 \\ 0 & 0 & - \frac{{i\theta}_{2}^{2}\theta_{3}}{\mathfrak{n}^{\mathbf{3}}} \\ 0 & - \frac{{i\theta}_{2}\theta_{3}^{2}}{\mathfrak{n}^{\mathbf{3}}} & 0 \end{pmatrix}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{3}}}, \end{array}
(1.6.58)
ψ(θrm)−𝔫×𝔰𝔲(θrm)−𝔫𝟑=(iθ1𝔫𝟏0000iθ2𝔫𝟏0iθ3𝔫𝟏0)(−iθ13𝔫𝟑0000−iθ22θ3𝔫𝟑0−iθ2θ32𝔫𝟑0)=(θ14𝔫𝟒000θ22θ32𝔫𝟒000θ22θ32𝔫𝟒)=𝔰𝔲(θrm)−𝔫𝟒,\begin{array}{r} {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{3}}} = \begin{pmatrix} \frac{{i\theta}_{1}}{\mathfrak{n}^{\mathbf{1}}} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{\mathfrak{n}^{\mathbf{1}}} \\ 0 & \frac{{i\theta}_{3}}{\mathfrak{n}^{\mathbf{1}}} & 0 \end{pmatrix}\begin{pmatrix} - \frac{{i\theta}_{1}^{3}}{\mathfrak{n}^{\mathbf{3}}} & 0 & 0 \\ 0 & 0 & - \frac{{i\theta}_{2}^{2}\theta_{3}}{\mathfrak{n}^{\mathbf{3}}} \\ 0 & - \frac{{i\theta}_{2}\theta_{3}^{2}}{\mathfrak{n}^{\mathbf{3}}} & 0 \end{pmatrix} = \begin{pmatrix} \frac{\theta_{1}^{4}}{\mathfrak{n}^{\mathbf{4}}} & 0 & 0 \\ 0 & \frac{\theta_{2}^{2}\theta_{3}^{2}}{\mathfrak{n}^{\mathbf{4}}} & 0 \\ 0 & 0 & \frac{\theta_{2}^{2}\theta_{3}^{2}}{\mathfrak{n}^{\mathbf{4}}} \end{pmatrix}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{4}}}, \end{array}
(1.6.59)

re­call­ing that the (𝔫𝐤)−𝟏=𝟏k!\left( \mathfrak{n}^{\mathbf{k}} \right)^{- \mathbf{1}}\mathbf{=}\frac{\mathbf{1}}{k\mathbf{!}} in the ex­pres­sions above, shows the equiv­a­lence re­la­tion­ship 𝔰𝔲(θrm)−𝔫𝐤=𝔰𝔲(θrm)k.\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{k}.

With the fac­to­r­i­al in­te­gra­tion op­er­a­tor de­fined, we can now con­sid­er an it­er­a­tive means to cal­cu­late any series of Lie al­ge­bra el­e­ments 𝔖𝔘(θrm)−𝔫𝐤\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}, by using in­duc­tion and the static fac­to­r­i­al in­te­gra­tion op­er­a­tor ψ(θrm)−𝔫{\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}, de­scribed in Lemma (1.6.60) and The­o­rem (1.6.61).

Lemma (1.6.60) – The fol­low­ing re­cur­sive re­la­tion­ship holds

𝔰𝔲(θrm)−𝔫𝟐𝐤+𝟏=ψ(θrm)−𝔫×𝔰𝔲(θrm)−𝔫𝟐𝐤.\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}} = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k}}}.

Proof – We start by taking the in­verse of ψ(θrm)−𝔫{\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}, then mul­ti­ply it to both sides

𝔰𝔲(θrm)−𝔫𝟐𝐤+𝟏=ψ(θrm)−𝔫×𝔰𝔲(θrm)−𝔫𝟐𝐤→\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}} = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k}}} \rightarrow
(ψ(θrm)−𝔫)−1× 𝔰𝔲(θrm)−𝔫𝟐𝐤+𝟏=(ψ(θrm)−𝔫)−1×ψ(θrm)−𝔫 ×𝔰𝔲(θrm)−𝔫𝟐𝐤→\left( {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} \right)^{- 1}\times \ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}} = \left( {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} \right)^{- 1} \times {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\ \times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k}}} \rightarrow
(ψ(θrm)−𝔫)−1× 𝔰𝔲(θrm)−𝔫𝟐𝐤+𝟏=𝔰𝔲(θrm)−𝔫𝟐𝐤,\left( {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} \right)^{- 1}\times \ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k}}},

and

(ψ(θxm)−𝔫)−1=(𝔫iθ10000𝔫iθ30𝔫iθ20).\begin{array}{r} \left( {\psi\left( \theta_{x}^{m} \right)}^{- \mathfrak{n}} \right)^{- 1} = \begin{pmatrix} \frac{\mathfrak{n}}{{i\theta}_{1}} & 0 & 0 \\ 0 & 0 & \frac{\mathfrak{n}}{{i\theta}_{3}} \\ 0 & \frac{\mathfrak{n}}{{i\theta}_{2}} & 0 \end{pmatrix}. \end{array}
□\square

Lemma (1.6.61) – The fol­low­ing re­cur­sive re­la­tion­ship holds

𝔰𝔲(θrm)−𝔫𝐤+𝟏=ψ(θrm)−𝔫×𝔰𝔲(θrm)−𝔫𝐤.\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}.

Proof – We start by taking the in­verse of ψ(θrm)−𝔫{\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}, and mul­ti­ply it to both sides

𝔰𝔲(θrm)−𝔫𝐤+𝟏=ψ(θrm)−𝔫×𝔰𝔲(θrm)−𝔫𝐤→\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} \rightarrow
(ψ(θrm)−𝔫)−1× 𝔰𝔲(θrm)−𝔫𝐤+𝟏=(ψ(θrm)−𝔫)−1×ψ(θrm)−𝔫 ×𝔰𝔲(θrm)−𝔫𝐤→\left( {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} \right)^{- 1}\times \ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} = \left( {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} \right)^{- 1} \times {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\ \times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} \rightarrow
(ψ(θrm)−𝔫)−1× 𝔰𝔲(θrm)−𝔫𝐤+𝟏=𝔰𝔲(θrm)−𝔫𝐤,\left( {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} \right)^{- 1}\times \ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}},

and

(ψ(θxm)−𝔫)−1=(𝔫iθ10000𝔫iθ30𝔫iθ20).\left( {\psi\left( \theta_{x}^{m} \right)}^{- \mathfrak{n}} \right)^{- 1} = \begin{pmatrix} \frac{\mathfrak{n}}{{i\theta}_{1}} & 0 & 0 \\ 0 & 0 & \frac{\mathfrak{n}}{{i\theta}_{3}} \\ 0 & \frac{\mathfrak{n}}{{i\theta}_{2}} & 0 \end{pmatrix}.

All 𝔰𝔲(θrm)−𝔫𝟐𝓀+𝟏\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathcal{k} +\mathbf{1}}} are odd, and have the form

((iθ1)2k+1𝔫𝟐𝐤+𝟏0000(iθ2)k+1(iθ3)k𝔫𝟐𝐤+𝟏0(iθ2)k(iθ3)k+1𝔫𝟐𝐤+𝟏0),\begin{pmatrix} \frac{\left( i\theta_{1} \right)^{2k + 1}}{\mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}} & 0 & 0 \\ 0 & 0 & \frac{\left( i\theta_{2} \right)^{k + 1}\left( i\theta_{3} \right)^{k}}{\mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}} \\ 0 & \frac{\left( i\theta_{2} \right)^{k}\left( i\theta_{3} \right)^{k + 1}}{\mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}} & 0 \end{pmatrix},

where­as all 𝔰𝔲(θrm)−𝔫𝟐𝓀\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathcal{k}}} are even, having the form

((iθ1)2k𝔫𝟐𝐤000(iθ2)k(iθ3)k𝔫𝟐𝐤000(iθ2)k(iθ3)k𝔫𝟐𝐤).\begin{pmatrix} \frac{\left( i\theta_{1} \right)^{2k}}{\mathfrak{n}^{\mathbf{2}\mathbf{k}}} & 0 & 0 \\ 0 & \frac{\left( i\theta_{2} \right)^{k}\left( i\theta_{3} \right)^{k}}{\mathfrak{n}^{\mathbf{2}\mathbf{k}}} & 0 \\ 0 & 0 & \frac{\left( i\theta_{2} \right)^{k}\left( i\theta_{3} \right)^{k}}{\mathfrak{n}^{\mathbf{2}\mathbf{k}}} \end{pmatrix}.

The fol­low­ing holds for all odd 𝔰𝔲(θrm)−𝔫𝟐𝓀+𝟏\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathcal{k} +\mathbf{1}}}, and even 𝔰𝔲(θrm)−𝔫𝟐𝓀\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathcal{k}}}

(ψ(θrm)−𝔫)−1×𝔰𝔲(θrm)−𝔫𝟐𝓀+𝟏=\left( {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} \right)^{- 1}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathcal{k} +\mathbf{1}}} =
(𝔫iθ10000𝔫iθ30𝔫iθ20)(θ1𝟐𝐤+𝟏𝔫𝟐𝐤+𝟏0000(θ2𝐤+𝟏θ3𝐤)𝔫𝟐𝐤+𝟏0(θ2𝐤θ3𝐤+𝟏)𝔫𝟐𝐤+𝟏0)=(θ1𝟐𝐤𝔫𝟐𝐤000(θ2𝐤θ3𝐤)𝔫𝟐𝐤000(θ2𝐤θ3𝐤)𝔫𝟐𝐤)=𝔰𝔲(θrm)−𝔫𝟐𝓀(even),\begin{pmatrix} \frac{\mathfrak{n}}{{i\theta}_{1}} & 0 & 0 \\ 0 & 0 & \frac{\mathfrak{n}}{{i\theta}_{3}} \\ 0 & \frac{\mathfrak{n}}{{i\theta}_{2}} & 0 \end{pmatrix}\begin{pmatrix} \frac{\theta_{1}^{\mathbf{2}\mathbf{k} + \mathbf{1}}}{\mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}} & 0 & 0 \\ 0 & 0 & \frac{\left( \theta_{2}^{\mathbf{k} + \mathbf{1}}\theta_{3}^{\mathbf{k}} \right)}{\mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}} \\ 0 & \frac{\left( \theta_{2}^{\mathbf{k}}\theta_{3}^{\mathbf{k} + \mathbf{1}} \right)}{\mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}} & 0 \end{pmatrix} = \begin{pmatrix} \frac{\theta_{1}^{\mathbf{2}\mathbf{k}}}{\mathfrak{n}^{\mathbf{2}\mathbf{k}}} & 0 & 0 \\ 0 & \frac{\left( \theta_{2}^{\mathbf{k}}\theta_{3}^{\mathbf{k}} \right)}{\mathfrak{n}^{\mathbf{2}\mathbf{k}}} & 0 \\ 0 & 0 & \frac{\left( \theta_{2}^{\mathbf{k}}\theta_{3}^{\mathbf{k}} \right)}{\mathfrak{n}^{\mathbf{2}\mathbf{k}}} \end{pmatrix}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathcal{k}}}(even),
(ψ(θrm)−𝔫)−1×𝔰𝔲(θrm)−𝔫𝟐𝓀=\left( {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} \right)^{- 1}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathcal{k}}} =
(𝔫iθ10000𝔫iθ30𝔫iθ20)(θ1𝟐𝐤𝔫𝟐𝐤000(θ2𝐤θ3𝐤)𝔫𝟐𝐤000(θ2𝐤θ3𝐤)𝔫𝟐𝐤)=(θ1𝟐𝐤−𝟏𝔫𝟐𝐤−𝟏0000(θ2𝐤θ3𝐤−𝟏)𝔫𝟐𝐤−𝟏0(θ3𝐤−𝟏θ2𝐤)𝔫𝟐𝐤−𝟏0)=𝔰𝔲(θrm)−𝔫𝟐𝓀−𝟏(odd).\begin{pmatrix} \frac{\mathfrak{n}}{{i\theta}_{1}} & 0 & 0 \\ 0 & 0 & \frac{\mathfrak{n}}{{i\theta}_{3}} \\ 0 & \frac{\mathfrak{n}}{{i\theta}_{2}} & 0 \end{pmatrix}\begin{pmatrix} \frac{\theta_{1}^{\mathbf{2}\mathbf{k}}}{\mathfrak{n}^{\mathbf{2}\mathbf{k}}} & 0 & 0 \\ 0 & \frac{\left( \theta_{2}^{\mathbf{k}}\theta_{3}^{\mathbf{k}} \right)}{\mathfrak{n}^{\mathbf{2}\mathbf{k}}} & 0 \\ 0 & 0 & \frac{\left( \theta_{2}^{\mathbf{k}}\theta_{3}^{\mathbf{k}} \right)}{\mathfrak{n}^{\mathbf{2}\mathbf{k}}} \end{pmatrix} = \begin{pmatrix} \frac{\theta_{1}^{\mathbf{2}\mathbf{k} - \mathbf{1}}}{\mathfrak{n}^{\mathbf{2}\mathbf{k} - \mathbf{1}}} & 0 & 0 \\ 0 & 0 & \frac{\left( \theta_{2}^{\mathbf{k}}\theta_{3}^{\mathbf{k} - \mathbf{1}} \right)}{\mathfrak{n}^{\mathbf{2}\mathbf{k} - \mathbf{1}}} \\ 0 & \frac{\left( \theta_{3}^{\mathbf{k} - \mathbf{1}}\theta_{2}^{\mathbf{k}} \right)}{\mathfrak{n}^{\mathbf{2}\mathbf{k} - \mathbf{1}}} & 0 \end{pmatrix}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathcal{k} -\mathbf{1}}}(odd).
□\square

The­o­rem (1.6.62) – The sum­ma­tion of the Lie al­ge­bra el­e­ments 𝔖𝔘(θrm)−𝔫𝐤+𝟏\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}}to the (k+1)th(k + 1)^{th} order that form the el­e­ments of the in­fi­nite series of in­te­gra­tion/matrix ex­po­nen­ti­a­tion, is re­cur­sive­ly re­lat­ed as a prod­uct of the in­fi­nite in­te­gra­tion op­er­a­tor ψ(θrm)−𝔫×{\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} \times 𝔖𝔘(θrm)−𝔫\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}}, and the iden­ti­ty el­e­ment ϵ\epsilon, as

𝔖𝔘(θrm)−𝔫𝐤+𝟏=ψ(θrm)−𝔫×𝔖𝔘(θrm)−𝔫𝐤+ϵ.\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} + \epsilon.

Proof – We first show that this holds for 𝔖𝔘(θrm)−𝔫𝟐,\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}}}, where­by de­f­i­n­i­tion we have

𝔖𝔘(A)−𝔫𝟏=∑𝐣=0𝟏 𝔰𝔲(A)−𝔫𝐣,\mathfrak{SU}(A)^{- \mathfrak{n}^{\mathbf{1}}} = \sum_{\mathbf{j} = 0}^{\mathbf{1}}{\ \mathfrak{su}(A)^{- \mathfrak{n}^{\mathbf{j}}},}

there­fore,

𝔖𝔘(θrm)−𝔫𝟐=ψ(θrm)−𝔫×𝔖𝔘(θrm)−𝔫𝟏+ϵ=ψ(θrm)−𝔫(∑𝐣=0𝟏 𝔰𝔲(θrm)−𝔫𝐣)+ϵ\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}}} = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{1}}} + \epsilon = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\left( \sum_{\mathbf{j} = 0}^{\mathbf{1}}{\ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{j}}}} \right) + \epsilon
=(iθ1𝔫𝟏0000iθ2𝔫𝟏0iθ3𝔫𝟏0)(iθ1𝔫𝟏+1𝔫𝟎0001𝔫𝟎iθ2𝔫𝟏0iθ3𝔫𝟏1𝔫𝟎)+(1𝔫𝟎0001𝔫𝟎0001𝔫𝟎)=(−θ12𝔫𝟐+iθ1𝔫𝟏+1𝔫𝟎000−θ2θ3𝔫𝟐+1𝔫𝟎iθ2𝔫𝟏0iθ3𝔫𝟏−θ2θ3𝔫𝟐+1𝔫𝟎).= \begin{pmatrix} \frac{{i\theta}_{1}}{\mathfrak{n}^{\mathbf{1}}} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{\mathfrak{n}^{\mathbf{1}}} \\ 0 & \frac{{i\theta}_{3}}{\mathfrak{n}^{\mathbf{1}}} & 0 \end{pmatrix}\begin{pmatrix} \frac{{i\theta}_{1}}{\mathfrak{n}^{\mathbf{1}}} + \frac{1}{\mathfrak{n}^{\mathbf{0}}} & 0 & 0 \\ 0 & \frac{1}{\mathfrak{n}^{\mathbf{0}}} & \frac{{i\theta}_{2}}{\mathfrak{n}^{\mathbf{1}}} \\ 0 & \frac{{i\theta}_{3}}{\mathfrak{n}^{\mathbf{1}}} & \frac{1}{\mathfrak{n}^{\mathbf{0}}} \end{pmatrix} + \begin{pmatrix} \frac{1}{\mathfrak{n}^{\mathbf{0}}} & 0 & 0 \\ 0 & \frac{1}{\mathfrak{n}^{\mathbf{0}}} & 0 \\ 0 & 0 & \frac{1}{\mathfrak{n}^{\mathbf{0}}} \end{pmatrix} = \begin{pmatrix} - \frac{\theta_{1}^{2}}{\mathfrak{n}^{\mathbf{2}}} + \frac{{i\theta}_{1}}{\mathfrak{n}^{\mathbf{1}}} + \frac{1}{\mathfrak{n}^{\mathbf{0}}} & 0 & 0 \\ 0 & - \frac{\theta_{2}\theta_{3}}{\mathfrak{n}^{\mathbf{2}}} + \frac{1}{\mathfrak{n}^{\mathbf{0}}} & \frac{{i\theta}_{2}}{\mathfrak{n}^{\mathbf{1}}} \\ 0 & \frac{i\theta_{3}}{\mathfrak{n}^{\mathbf{1}}} & - \frac{\theta_{2}\theta_{3}}{\mathfrak{n}^{\mathbf{2}}} + \frac{1}{\mathfrak{n}^{\mathbf{0}}} \end{pmatrix}.

Now, by in­duc­tion

𝔖𝔘(θrm)−𝔫𝐤+𝟏=ψ(θrm)−𝔫×𝔖𝔘(θrm)−𝔫𝐤+ϵ=ψ(θrm)−𝔫(∑𝐣=0𝐤 𝔰𝔲(θrm)−𝔫𝐣)+ϵ,\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} + \epsilon = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\left( \sum_{\mathbf{j} = 0}^{\mathbf{k}}{\ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{j}}}} \right) + \epsilon,

ex­pand­ing the sum­ma­tion, (∑𝐣=0𝐤 𝔰𝔲(θrm)−𝔫𝐣)\left( \sum_{\mathbf{j} = 0}^{\mathbf{k}}{\ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{j}}}} \right),

𝔖𝔘(θrm)−𝔫𝐤+𝟏=ψ(θrm)−𝔫(𝔰𝔲(θrm)−𝔫𝐤+𝔰𝔲(θrm)−𝔫𝐤−𝟏+…+𝔰𝔲(θrm)𝔫𝟎)+ϵ,\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\left( \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}+ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} - \mathbf{1}}}+ \ldots + \mathfrak{su}\left( \theta_{r}^{m} \right)^{\mathfrak{n}^{\mathbf{0}}} \right) + \epsilon,

and know­ing the re­cur­sive re­la­tion­ship, 𝔰𝔲(θrm)−𝔫𝐤+𝟏=ψ(θrm)−𝔫×𝔰𝔲(θrm)−𝔫𝐤\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}, and ϵ=𝔰𝔲(θrm)−𝔫𝟎\epsilon = \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{0}}}, the ex­pres­sion be­comes

𝔖𝔘(θrm)−𝔫𝐤+𝟏=𝔰𝔲(θrm)−𝔫𝐤+𝟏+𝔰𝔲(θrm)−𝔫𝐤+…+𝔰𝔲(θrm)−𝔫𝟏+𝔰𝔲(θrm)−𝔫𝟎.\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}}+ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}+ \ldots + \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{1}}}+ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{0}}}.

By De­f­i­n­i­tion (1.6.55),

𝔖𝔘(A)−𝔫𝐤=∑𝐣=0𝐤 𝔰𝔲(A)−𝔫𝐣,\mathfrak{SU}(A)^{- \mathfrak{n}^{\mathbf{k}}} = \sum_{\mathbf{j} = 0}^{\mathbf{k}}{\ \mathfrak{su}(A)^{- \mathfrak{n}^{\mathbf{j}}},}

and there­fore, it holds that

𝔖𝔘(θrm)−𝔫𝐤+𝟏=ψ(θrm)−𝔫×𝔖𝔘(θrm)−𝔫𝐤+ϵ.\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} + \epsilon.
□\square

Dif­fer­en­ti­a­tion is de­fined as the in­verse of in­te­gra­tion, which leads us to define the in­fi­nite dif­fer­en­ti­a­tion op­er­a­tor ψ(θrm)𝔫{\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}}, as the in­verse of the in­fi­nite in­te­gra­tion op­er­a­tor ψ(θrm)−n{\psi\left( \theta_{r}^{m} \right)}^{- n}.

De­f­i­n­i­tion (1.6.63) – 𝛙(𝛉𝐫𝐦)𝔫{\mathbf{\psi}\left( \mathbf{\theta}_{\mathbf{r}}^{\mathbf{m}} \right)}^{\mathfrak{n}} is the in­fi­nite fac­to­r­i­al dif­fer­en­tial op­er­a­tor, for a pos­i­tive-valued ex­po­nent 𝔫\mathfrak{n}, and is de­fined as the in­verse of the in­fi­nite fac­to­r­i­al in­te­gra­tion op­er­a­tor

ψ(θrm)𝔫=(𝔫iθ10000𝔫iθ30𝔫iθ20),{\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}} = \begin{pmatrix} \frac{\mathfrak{n}}{{i\theta}_{1}} & 0 & 0 \\ 0 & 0 & \frac{\mathfrak{n}}{{i\theta}_{3}} \\ 0 & \frac{\mathfrak{n}}{{i\theta}_{2}} & 0 \end{pmatrix},

for this in­verse re­la­tion­ship, de­fined as

(ψ(θrm)−𝔫)−1=(iθ1𝔫0000iθ2𝔫0iθ3𝔫0)−1=(𝔫iθ10000𝔫iθ30𝔫iθ20).\left( {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} \right)^{- 1} = \begin{pmatrix} \frac{{i\theta}_{1}}{\mathfrak{n}} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{\mathfrak{n}} \\ 0 & \frac{{i\theta}_{3}}{\mathfrak{n}} & 0 \end{pmatrix}^{- 1} = \begin{pmatrix} \frac{\mathfrak{n}}{{i\theta}_{1}} & 0 & 0 \\ 0 & 0 & \frac{\mathfrak{n}}{{i\theta}_{3}} \\ 0 & \frac{\mathfrak{n}}{{i\theta}_{2}} & 0 \end{pmatrix}.

Lemma (1.6.64) – The fol­low­ing re­cur­sive re­la­tion­ship holds for dif­fer­en­ti­a­tion

𝔰𝔲(θrm)−𝔫𝟐𝐤=ψ(θrm)𝔫×𝔰𝔲(θrm)−𝔫𝟐𝐤+𝟏.\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k}}} = {\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}}.

Proof – As de­fined, ψ(θrm)𝔫\mathbf{\ }{\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}} is the in­verse of ψ(θrm)−𝔫,{\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}},and we can mul­ti­ply both sides by ψ(θrm)−𝔫{\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}

ψ(θrm)−𝔫×𝔰𝔲(θrm)−𝔫𝟐𝐤=𝔰𝔲(θrm)−𝔫𝟐𝐤+𝟏,{\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k}}}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}},

*and this is equiv­a­lent to Lemma (1.6.54), which proved the in­te­gra­tion re­cur­sive re­la­tion­ship that*

𝔰𝔲(θrm)−𝔫𝟐𝐤+𝟏=ψ(θrm)−𝔫×𝔰𝔲(θrm)−𝔫𝟐𝐤.\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k} + \mathbf{1}}} = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}\mathbf{k}}}.
□\square

Con­sid­er­ing in­fi­nite dif­fer­en­ti­a­tion's in­verse re­la­tion­ship to in­fi­nite in­te­gra­tion, we state and prove the the­o­rem:

The­o­rem (1.6.65) – The sum­ma­tion of the Lie al­ge­bra el­e­ments 𝔖𝔘(θrm)𝔫𝐤\mathfrak{SU}\left( \theta_{r}^{m} \right)^{\mathfrak{n}^{\mathbf{k}}}, to order-𝐤\mathbf{k}, form­ing the el­e­ments of the in­fi­nite dif­fer­en­tial series, is in­verse­ly re­lat­ed to in­fi­nite in­te­gra­tion func­tion

𝔖𝔘(θrm)−𝔫𝐤=ψ(θrm)𝔫×(𝔖𝔘(θrm)−𝔫𝐤+𝟏−ϵ).\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} = {\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}} \times \left( \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} - \epsilon \right).

Proof – We first show that this holds for 𝔖𝔘(θrm)−𝔫𝟐,\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}}}, where­by the de­f­i­n­i­tion, we have that

𝔖𝔘(A)−𝔫3=∑𝐣=0𝟑 𝔰𝔲(A)−𝔫𝐣,\mathfrak{SU}(A)^{- \mathfrak{n}^{3}} = \sum_{\mathbf{j} = 0}^{\mathbf{3}}{\ \mathfrak{su}(A)^{- \mathfrak{n}^{\mathbf{j}}},}

there­fore,

𝔖𝔘(θrm)−𝔫𝟐=ψ(θrm)𝔫×(𝔖𝔘(θrm)−𝔫𝟑−ϵ)=ψ(θrm)𝔫(∑𝐣=0𝟑 𝔰𝔲(θrm)−𝔫𝐣−ϵ)\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{2}}} = {\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}} \times \left( \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{3}}} - \epsilon \right) = {\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}}\left( \sum_{\mathbf{j} = 0}^{\mathbf{3}}{\ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{j}}}} - \epsilon \right)
=(𝔫iθ10000𝔫iθ30𝔫iθ20)((−iθ13𝔫𝟑−θ12𝔫𝟐+iθ1𝔫𝟏+1𝔫𝟎000−θ2θ3𝔫𝟐+1𝔫𝟎−iθ22θ3𝔫𝟑+iθ2𝔫𝟏0−iθ2θ32𝔫𝟑+iθ3𝔫𝟏−θ2θ3𝔫𝟐+1𝔫𝟎)−(1𝔫𝟎0001𝔫𝟎0001𝔫𝟎))=(−θ12𝔫𝟐+iθ1𝔫𝟏+1𝔫𝟎000−θ2θ3𝔫𝟐+1𝔫𝟎iθ2𝔫𝟏0iθ3𝔫𝟏−θ2θ3𝔫𝟐+1𝔫𝟎).= \begin{pmatrix} \frac{\mathfrak{n}}{{i\theta}_{1}} & 0 & 0 \\ 0 & 0 & \frac{\mathfrak{n}}{{i\theta}_{3}} \\ 0 & \frac{\mathfrak{n}}{{i\theta}_{2}} & 0 \end{pmatrix}\left( \begin{pmatrix} - \frac{i\theta_{1}^{3}}{\mathfrak{n}^{\mathbf{3}}} - \frac{\theta_{1}^{2}}{\mathfrak{n}^{\mathbf{2}}} + \frac{{i\theta}_{1}}{\mathfrak{n}^{\mathbf{1}}} + \frac{1}{\mathfrak{n}^{\mathbf{0}}} & 0 & 0 \\ 0 & - \frac{\theta_{2}\theta_{3}}{\mathfrak{n}^{\mathbf{2}}} + \frac{1}{\mathfrak{n}^{\mathbf{0}}} & - \frac{i\theta_{2}^{2}\theta_{3}}{\mathfrak{n}^{\mathbf{3}}} + \frac{{i\theta}_{2}}{\mathfrak{n}^{\mathbf{1}}} \\ 0 & - \frac{i{\theta_{2}\theta}_{3}^{2}}{\mathfrak{n}^{\mathbf{3}}} + \frac{{i\theta}_{3}}{\mathfrak{n}^{\mathbf{1}}} & - \frac{\theta_{2}\theta_{3}}{\mathfrak{n}^{\mathbf{2}}} + \frac{1}{\mathfrak{n}^{\mathbf{0}}} \end{pmatrix} - \begin{pmatrix} \frac{1}{\mathfrak{n}^{\mathbf{0}}} & 0 & 0 \\ 0 & \frac{1}{\mathfrak{n}^{\mathbf{0}}} & 0 \\ 0 & 0 & \frac{1}{\mathfrak{n}^{\mathbf{0}}} \end{pmatrix} \right) = \begin{pmatrix} - \frac{\theta_{1}^{2}}{\mathfrak{n}^{\mathbf{2}}} + \frac{{i\theta}_{1}}{\mathfrak{n}^{\mathbf{1}}} + \frac{1}{\mathfrak{n}^{\mathbf{0}}} & 0 & 0 \\ 0 & - \frac{\theta_{2}\theta_{3}}{\mathfrak{n}^{\mathbf{2}}} + \frac{1}{\mathfrak{n}^{\mathbf{0}}} & \frac{{i\theta}_{2}}{\mathfrak{n}^{\mathbf{1}}} \\ 0 & \frac{i\theta_{3}}{\mathfrak{n}^{\mathbf{1}}} & - \frac{\theta_{2}\theta_{3}}{\mathfrak{n}^{\mathbf{2}}} + \frac{1}{\mathfrak{n}^{\mathbf{0}}} \end{pmatrix}.

By in­duc­tion

𝔖𝔘(θrm)−𝔫𝐤=ψ(θrm)𝔫×(𝔖𝔘(θrm)−𝔫𝐤+𝟏−ϵ)=ψ(θrm)𝔫(∑𝐣=0𝐤+𝟏 𝔰𝔲(θrm)−𝔫𝐣−ϵ),\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} = {\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}} \times \left( \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} - \epsilon \right) = {\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}}\left( \sum_{\mathbf{j} = 0}^{\mathbf{k} + \mathbf{1}}{\ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{j}}}} - \epsilon \right),

ex­pand­ing the sum­ma­tion (∑𝐣=0𝐤+𝟏 𝔰𝔲(θrm)−𝔫𝐣),\left( \sum_{\mathbf{j} = 0}^{\mathbf{k} + \mathbf{1}}{\ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{j}}}} \right), yields

𝔖𝔘(θrm)−𝔫𝐤=ψ(θrm)𝔫×(𝔰𝔲(θrm)−𝔫𝐤+𝟏+𝔰𝔲(θrm)−𝔫𝐤+…𝔰𝔲(θrm)−𝔫𝟎−ϵ),\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} = {\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}} \times \left( \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}}+ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}+ \ldots \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{0}}} - \epsilon \right),

where know­ing the re­cur­sive re­la­tion­ship, 𝔰𝔲(θrm)−𝔫𝐤+𝟏=ψ(θrm)−𝔫×𝔰𝔲(θrm)−𝔫𝐤\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} = {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}, and that the in­fi­nite dif­fer­en­tial op­er­a­tor is the in­verse of ψ(θrm)−𝔫{\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}}, we have that

ψ(θrm)𝔫×𝔰𝔲(θrm)−𝔫𝐤+𝟏=(ψ(θrm)𝔫×ψ(θrm)−𝔫)×𝔰𝔲(θrm)−𝔫𝐤.{\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} = \left( {\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}} \times {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} \right)\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}.

Since (ψ(θrm)𝔫×ψ(θrm)−𝔫)=ϵ\left( {\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}} \times {\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}} \right) = \epsilon,

ψ(θrm)𝔫×𝔰𝔲(θrm)−𝔫𝐤+𝟏=𝔰𝔲(θrm)−𝔫𝐤.{\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}.

As 𝔰𝔲(θrm)−𝔫𝟎=ϵ\mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{0}}} = \epsilon, the sum­ma­tion be­comes

𝔖𝔘(θrm)−𝔫𝐤=ψ(θrm)𝔫×(𝔰𝔲(θrm)−𝔫𝐤+𝟏+𝔰𝔲(θrm)−𝔫𝐤+…𝔰𝔲(θrm)−𝔫𝟏),\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} = {\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}} \times \left( \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}}+ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}+ \ldots \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{1}}} \right),

and by the in­verse re­la­tion­ship ψ(θrm)𝔫×𝔰𝔲(θrm)−𝔫𝐤+𝟏=𝔰𝔲(θrm)−𝔫𝐤,{\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}}\times \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}}= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}, we have

ψ(θrm)𝔫×(𝔰𝔲(θrm)−𝔫𝐤+𝟏+𝔰𝔲(θrm)−𝔫𝐤+…𝔰𝔲(θrm)−𝔫𝟏)=𝔰𝔲(θrm)−𝔫𝐤+𝔰𝔲(θrm)−𝔫𝐤−𝟏+…𝔰𝔲(θrm)−𝔫𝟎,{\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}} \times \left( \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}}+ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}+ \ldots \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{1}}} \right)= \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}+ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} - \mathbf{1}}}+ \ldots \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{0}}},

which is the same as De­f­i­n­i­tion (1.6.55)

𝔖𝔘(A)−𝔫𝐤=∑𝐣=0𝐤 𝔰𝔲(A)−𝔫𝐣,\mathfrak{SU}(A)^{- \mathfrak{n}^{\mathbf{k}}} = \sum_{\mathbf{j} = 0}^{\mathbf{k}}{\ \mathfrak{su}(A)^{- \mathfrak{n}^{\mathbf{j}}},}

which proves that

𝔖𝔘(θrm)−𝔫𝐤=ψ(θrm)𝔫×(𝔖𝔘(θrm)−𝔫𝐤+𝟏−ϵ).\mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} = {\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}} \times \left( \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}} - \epsilon \right).
□\square

The ad­van­tage of using the op­er­a­tor no­ta­tion, with pos­i­tive and neg­a­tive ex­po­nents, as 𝔫\mathfrak{n}, is when using prod­ucts of op­er­a­tors and ma­tri­ces, the ex­po­nents are simply a prod­uct of the ex­po­nents, as seen in the ex­am­ples

ψ(θrm)𝔫𝟏×𝔖𝔘(θrm)−𝔫𝐤+𝟏=𝔖𝔘(θrm)−𝔫𝐤,{\psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}^{\mathbf{1}}}\times \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}}= \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}},

given that, 𝔫𝟏(𝟏𝔫𝐤+𝟏)=𝟏/𝔫𝐤\mathfrak{n}^{\mathbf{1}}\left( \frac{\mathbf{1}}{\mathfrak{n}^{\mathbf{k} + \mathbf{1}}} \right)\mathbf{=}{\mathbf{1}/\mathfrak{n}}^{\mathbf{k}}, and

ψ(θrm)−𝔫𝟏×𝔖𝔘(θrm)−𝔫𝐤=𝔖𝔘(θrm)−𝔫𝐤+𝟏,{\psi\left( \theta_{r}^{m} \right)}^{- \mathfrak{n}^{\mathbf{1}}}\times \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}= \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k} + \mathbf{1}}},

as, (𝟏𝔫𝟏)(𝟏𝔫𝐤)=𝟏𝔫𝐤+𝟏.\left( \frac{\mathbf{1}}{\mathfrak{n}^{\mathbf{1}}} \right)\left( \frac{\mathbf{1}}{\mathfrak{n}^{\mathbf{k}}} \right)\mathbf{=}\frac{\mathbf{1}}{\mathfrak{n}^{\mathbf{k} + \mathbf{1}}}\mathbf{.}

For the other iXj{iX}_{j}-type Lie al­ge­bras, it is straight­for­ward to define in­fi­nite fac­to­r­i­al in­te­gra­tion and dif­fer­en­tial op­er­a­tors as fol­lows:

ψ(θ13,Xj)−𝔫={(iθ1𝔫0000iθ2𝔫0iθ3𝔫0),   (00iθ1𝔫0iθ2𝔫0iθ3𝔫00),   (0iθ1𝔫0iθ2𝔫0000iθ3𝔫)},\begin{array}{r} {\psi\left( \theta_{1}^{3,X_{j}} \right)}^{- \mathfrak{n}} = \left\{ \begin{pmatrix} \frac{{i\theta}_{1}}{\mathfrak{n}} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{2}}{\mathfrak{n}} \\ 0 & \frac{{i\theta}_{3}}{\mathfrak{n}} & 0 \end{pmatrix},\ \ \ \begin{pmatrix} 0 & 0 & \frac{i\theta_{1}}{\mathfrak{n}} \\ 0 & \frac{{i\theta}_{2}}{\mathfrak{n}} & 0 \\ \frac{{i\theta}_{3}}{\mathfrak{n}} & 0 & 0 \end{pmatrix},\ \ \ \begin{pmatrix} 0 & \frac{{i\theta}_{1}}{\mathfrak{n}} & 0 \\ \frac{{i\theta}_{2}}{\mathfrak{n}} & 0 & 0 \\ 0 & 0 & \frac{{i\theta}_{3}}{\mathfrak{n}} \end{pmatrix} \right\}, \end{array}
(1.6.66)
ψ(θ13,Xj)𝔫={(𝔫iθ10000𝔫iθ30𝔫iθ20),   (00𝔫iθ30𝔫iθ20𝔫iθ100),   (0𝔫iθ20𝔫iθ10000𝔫iθ3)}.\begin{array}{r} {\psi\left( \theta_{1}^{3,X_{j}} \right)}^{\mathfrak{n}} = \left\{ \begin{pmatrix} \frac{\mathfrak{n}}{{i\theta}_{1}} & 0 & 0 \\ 0 & 0 & \frac{\mathfrak{n}}{{i\theta}_{3}} \\ 0 & \frac{\mathfrak{n}}{{i\theta}_{2}} & 0 \end{pmatrix},\ \ \ \begin{pmatrix} 0 & 0 & \frac{\mathfrak{n}}{{i\theta}_{3}} \\ 0 & \frac{\mathfrak{n}}{{i\theta}_{2}} & 0 \\ \frac{\mathfrak{n}}{{i\theta}_{1}} & 0 & 0 \end{pmatrix},\ \ \ \begin{pmatrix} 0 & \frac{\mathfrak{n}}{{i\theta}_{2}} & 0 \\ \frac{\mathfrak{n}}{{i\theta}_{1}} & 0 & 0 \\ 0 & 0 & \frac{\mathfrak{n}}{{i\theta}_{3}} \end{pmatrix} \right\}. \end{array}
(1.6.67)

The ex­po­nen­tial map­ping is forth­right in terms of our in­fi­nite in­te­gra­tion se­quence, where

eθrm=𝔖𝔘(θrm)−𝔫∞=∑𝐤=0∞ 𝔰𝔲(θrm)−𝔫𝐤=∑k=0∞ 𝔰𝔲(θrm)−k!,\begin{array}{r} e^{\theta_{r}^{m}}= \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{\infty}}} = \sum_{\mathbf{k} = 0}^{\mathbf{\infty}}{\ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} = \sum_{k = 0}^{\mathbf{\infty}}{\ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- k!}},} \end{array}
(1.6.68)

and using, once again, the iX1{iX}_{1}-type matrix, the above ex­pands to the fol­low­ing matrix series form

∑k=0∞ 𝔰𝔲(θ13)−k!=(∑k=0∞(iθ1)kk!000∑k=0∞(iθ2)k(iθ3)k(2k)!∑k=0∞(iθ2)k+1(iθ3)k(2k+1)!0∑k=0∞(iθ2)k(iθ3)k+1(2k+1)!∑k=0∞(iθ2)k(iθ3)k(2k)!).\begin{array}{r} \sum_{k = 0}^{\mathbf{\infty}}{\ \mathfrak{su}\left( \theta_{1}^{3} \right)^{- k!} = \begin{pmatrix} \sum_{k = 0}^{\infty}\frac{\left( {i\theta}_{1} \right)^{k}}{k!} & 0 & 0 \\ 0 & \sum_{k = 0}^{\infty}\frac{\left( i\theta_{2} \right)^{k}\left( i\theta_{3} \right)^{k}}{(2k)!} & \sum_{k = 0}^{\infty}\frac{\left( i\theta_{2} \right)^{k + 1}\left( i\theta_{3} \right)^{k}}{(2k + 1)!} \\ 0 & \sum_{k = 0}^{\infty}\frac{\left( i\theta_{2} \right)^{k}\left( i\theta_{3} \right)^{k + 1}}{(2k + 1)!} & \sum_{k = 0}^{\infty}\frac{\left( i\theta_{2} \right)^{k}\left( i\theta_{3} \right)^{k}}{(2k)!} \end{pmatrix}}. \end{array}
(1.6.69)

From the ex­po­nen­tial map­ping, we can trans­form back to the Lie al­ge­bra 𝔤\mathfrak{g}, by way of the fol­low­ing re­la­tion

𝔤=𝔖𝔘(θrm)−𝔫∞−(∑𝐤=𝟐∞ 𝔰𝔲(θrm)−𝔫𝐤+ϵ)\mathfrak{g} = \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{\infty}}} - \left( \sum_{\mathbf{k} = \mathbf{2}}^{\infty}{\ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}}} + \epsilon \right)
=𝔖𝔘(θrm)−𝔫∞−(∑k=2∞ 𝔰𝔲(θrm)−k!+ϵ)=𝔰𝔲(θrm)1.\begin{array}{r} = \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{\infty}}} - \left( \sum_{k = 2}^{\mathbf{\infty}}{\ \mathfrak{su}\left( \theta_{r}^{m} \right)^{- k!}} + \epsilon \right)= \mathfrak{su}\left( \theta_{r}^{m} \right)^{1}. \end{array}
(1.6.70)

We can now define the matrix log­a­rithm func­tion in terms of the in­fi­nite dif­fer­en­tial, as the log­a­rithm of the series

ln⁡(eθrm)=ln⁡(𝔖𝔘(θrm)−𝔫∞),\begin{array}{r} \ln\left( e^{\theta_{r}^{m}} \right) = \ln\left( \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{\infty}}} \right), \end{array}
(1.6.71)

which can be ex­pressed in terms of op­er­a­tor notion

ln⁡(eθrm)=ψ(θrm)𝔫 (𝔖𝔘(θrm)−𝔫𝐤−ϵ)|k:∞→2 ,\begin{array}{r} {\ln\left( e^{\theta_{r}^{m}} \right) = \psi\left( \theta_{r}^{m} \right)}^{\mathfrak{n}}\left. \ \left( \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} - \epsilon \right) \right|_{k:\infty \rightarrow 2}\ , \end{array}
(1.6.72)

where suc­ces­sive dif­fer­en­tial it­er­a­tions are taken, start­ing at k=∞k = \infty, pro­ceed­ing all the way to k=2k = 2, for the prod­uct ψ(θrjm)𝔫(𝔖𝔘(θrm)−𝔫𝐤−ϵ){\psi\left( \theta_{r_{j}}^{m} \right)}^{\mathfrak{n}}\left( \mathfrak{SU}\left( \theta_{r}^{m} \right)^{- \mathfrak{n}^{\mathbf{k}}} - \epsilon \right). If the radial com­po­nent is not as­sumed to be uni­tary, we find that the sub­tan­gent form ln⁡(θrm)\ln\left( \theta_{r}^{m} \right), is equal to

ln⁡(θrm)=ln⁡(reiθ)=ln⁡(r)+iθ, \begin{array}{r} \ln\left( \theta_{r}^{m} \right) = \ln{\left( re^{i\theta} \right) = \ln{(r) + i\theta},\ } \end{array}
(1.6.73)

and for ln⁡(r)≠0\ln{(r) \neq 0}, that the matrix en­tries in the in­te­gra­tion and dif­fer­en­ti­a­tion op­er­a­tors take the fol­low­ing forms, re­spec­tive­ly,

ln⁡(rj)+iθj𝔫,   𝔫ln⁡(rj)+iθj.\begin{array}{r} \frac{\ln{\left( r_{j} \right) +}{i\theta}_{j}}{\mathfrak{n}},\ \ \ \frac{\mathfrak{n}}{\ln{\left( r_{j} \right) +}{i\theta}_{j}}. \end{array}
(1.6.74)

Given this, the non-uni­tary in­fi­nite in­te­gra­tion and dif­fer­en­ti­a­tion op­er­a­tors can be rep­re­sent­ed, as

ψ(θrj3,Xj)−𝔫={(ln⁡(r1)+iθ1𝔫0000ln⁡(r2)+iθ2𝔫0ln⁡(r3)+iθ3𝔫0),(00ln⁡(r1)+iθ1𝔫0ln⁡(r2)+iθ2𝔫0ln⁡(r3)+iθ3𝔫00),(0ln⁡(r1)+iθ1𝔫0ln⁡(r2)+iθ2𝔫0000ln⁡(r3)+iθ3𝔫)},\begin{array}{r} {\psi\left( \theta_{r_{j}}^{3,X_{j}} \right)}^{- \mathfrak{n}} = \left\{ \begin{array}{r} \begin{pmatrix} \frac{{\ln{\left( r_{1} \right) +}i\theta}_{1}}{\mathfrak{n}} & 0 & 0 \\ 0 & 0 & \frac{\ln{\left( r_{2} \right) +}{i\theta}_{2}}{\mathfrak{n}} \\ 0 & \frac{\ln{\left( r_{3} \right) +}{i\theta}_{3}}{\mathfrak{n}} & 0 \end{pmatrix},\begin{pmatrix} 0 & 0 & \frac{{\ln{\left( r_{1} \right) +}i\theta}_{1}}{\mathfrak{n}} \\ 0 & \frac{\ln{\left( r_{2} \right) +}{i\theta}_{2}}{\mathfrak{n}} & 0 \\ \frac{\ln{\left( r_{3} \right) +}{i\theta}_{3}}{\mathfrak{n}} & 0 & 0 \end{pmatrix}, \\ \begin{pmatrix} 0 & \frac{{\ln{\left( r_{1} \right) +}i\theta}_{1}}{\mathfrak{n}} & 0 \\ \frac{\ln{\left( r_{2} \right) +}{i\theta}_{2}}{\mathfrak{n}} & 0 & 0 \\ 0 & 0 & \frac{\ln{\left( r_{3} \right) +}{i\theta}_{3}}{\mathfrak{n}} \end{pmatrix} \end{array} \right\}, \end{array}
(1.6.75)
ψ(θrj3,Xj)𝔫={(𝔫ln⁡(r1)+iθ10000𝔫ln⁡(r3)+iθ30𝔫ln⁡(r2)+iθ20),(00𝔫ln⁡(r3)+iθ30𝔫ln⁡(r2)+iθ20𝔫ln⁡(r1)+iθ100),(0𝔫ln⁡(r2)+iθ20𝔫ln⁡(r1)+iθ10000𝔫ln⁡(r3)+iθ3)}.\begin{array}{r} {\psi\left( \theta_{r_{j}}^{3,X_{j}} \right)}^{\mathfrak{n}} = \left\{ \begin{array}{r} \begin{pmatrix} \frac{\mathfrak{n}}{{\ln{\left( r_{1} \right) +}i\theta}_{1}} & 0 & 0 \\ 0 & 0 & \frac{\mathfrak{n}}{\ln{\left( r_{3} \right) +}{i\theta}_{3}} \\ 0 & \frac{\mathfrak{n}}{\ln{\left( r_{2} \right) +}{i\theta}_{2}} & 0 \end{pmatrix},\begin{pmatrix} 0 & 0 & \frac{\mathfrak{n}}{\ln{\left( r_{3} \right) +}{i\theta}_{3}} \\ 0 & \frac{\mathfrak{n}}{\ln{\left( r_{2} \right) +}{i\theta}_{2}} & 0 \\ \frac{\mathfrak{n}}{{\ln{\left( r_{1} \right) +}i\theta}_{1}} & 0 & 0 \end{pmatrix}, \\ \begin{pmatrix} 0 & \frac{\mathfrak{n}}{\ln{\left( r_{2} \right) +}{i\theta}_{2}} & 0 \\ \frac{\mathfrak{n}}{{\ln{\left( r_{1} \right) +}i\theta}_{1}} & 0 & 0 \\ 0 & 0 & \frac{\mathfrak{n}}{\ln{\left( r_{3} \right) +}{i\theta}_{3}} \end{pmatrix} \end{array} \right\}. \end{array}
(1.6.76)