Masteries · Jason GlowneyArithmoí Book 1

Masteries

1.2.3 The Dihedral Differential Forms ∈3ℂ\in 3\mathbb{C}

This sec­tion con­sid­ers the de­riv­a­tives of matrix gen­er­a­tors and the re­la­tion­ship with the re­sult­ing Lie al­ge­bras that un­der­ly the dif­fer­en­tial func­tion. The sub­ject matter is of par­tic­u­lar im­por­tance in math­e­mat­i­cal physics. We start the sec­tion by con­sid­er­ing the el­e­ment-by-el­e­ment de­riv­a­tive of the G(x1X1ℂ)G\left( {x_{1}X}_{1}^{\mathbb{C}} \right) matrix

G′(x1X1ℂ)=ddx1(eix1000cos⁡(x1)isin(x1)0isin(x1)cos⁡(x1))=(ieix1000−sin(x1)icos(x1)0icos(x1)−sin(x1)),\begin{array}{r} G^{'}\left( {x_{1}X}_{1}^{\mathbb{C}} \right) = \frac{d}{dx_{1}}\begin{pmatrix} e^{ix_{1}} & 0 & 0 \\ 0 & \cos\left( x_{1} \right) & isin(x_{1}) \\ 0 & isin(x_{1}) & \cos\left( x_{1} \right) \end{pmatrix} = \begin{pmatrix} {ie}^{ix_{1}} & 0 & 0 \\ 0 & {- sin}\left( x_{1} \right) & icos\left( x_{1} \right) \\ 0 & icos\left( x_{1} \right) & {- sin}\left( x_{1} \right) \end{pmatrix}, \end{array}
(1.2.33)

where the con­tin­u­ous nature of G(x1X1ℂ)G\left( {x_{1}X}_{1}^{\mathbb{C}} \right) en­sures the de­riv­a­tive's ex­is­tence. This dif­fer­en­tial form is anal­o­gous to the ve­loc­i­ty of the G(x1X1ℂ)G\left( {x_{1}X}_{1}^{\mathbb{C}} \right) group. When taken el­e­ment-by-el­e­ment, there are five dis­tinct ve­loc­i­ty vector func­tions in the result, which to­geth­er sit in ℂ3\mathbb{C}^{3} space. The D3ℂD_{3\mathbb{C}} set of matrix el­e­ments AℂA_{\mathbb{C}} is com­posed of the fol­low­ing twelve per­mu­ta­tion el­e­ments

Aℂ={Xj,kℂ,Yj,kℂ}={(e(iπ2+kiπ)0000e(iπ2+kiπ)0e(iπ2+kiπ)0),   (00e(iπ2+kiπ)0e(iπ2+kiπ)0e(iπ2+kiπ)00),   (0e(iπ2+kiπ)0e(iπ2+kiπ)0000e(iπ2+kiπ)),(e(kiπ)000e(kiπ)000e(kiπ)),   (0e(kiπ)000e(kiπ)e(kiπ)00),   (00e(kiπ)e(kiπ)000e(kiπ)0)}\begin{array}{r} A_{\mathbb{C}} = \left\{ X_{j,k}^{\mathbb{C}},Y_{j,k}^{\mathbb{C}} \right\} = \left\{ \begin{array}{r} \begin{pmatrix} e^{\left( \frac{i\pi}{2} + ki\pi \right)} & 0 & 0 \\ 0 & 0 & e^{\left( \frac{i\pi}{2} + ki\pi \right)} \\ 0 & e^{\left( \frac{i\pi}{2} + ki\pi \right)} & 0 \end{pmatrix},\ \ \ \begin{pmatrix} 0 & 0 & e^{\left( \frac{i\pi}{2} + ki\pi \right)} \\ 0 & e^{\left( \frac{i\pi}{2} + ki\pi \right)} & 0 \\ e^{\left( \frac{i\pi}{2} + ki\pi \right)} & 0 & 0 \end{pmatrix},\ \ \ \begin{pmatrix} 0 & e^{\left( \frac{i\pi}{2} + ki\pi \right)} & 0 \\ e^{\left( \frac{i\pi}{2} + ki\pi \right)} & 0 & 0 \\ 0 & 0 & e^{\left( \frac{i\pi}{2} + ki\pi \right)} \end{pmatrix}, \\ \begin{pmatrix} e^{(ki\pi)} & 0 & 0 \\ 0 & e^{(ki\pi)} & 0 \\ 0 & 0 & e^{(ki\pi)} \end{pmatrix},\ \ \ \begin{pmatrix} 0 & e^{(ki\pi)} & 0 \\ 0 & 0 & e^{(ki\pi)} \\ e^{(ki\pi)} & 0 & 0 \end{pmatrix},\ \ \ \begin{pmatrix} 0 & 0 & e^{(ki\pi)} \\ e^{(ki\pi)} & 0 & 0 \\ 0 & e^{(ki\pi)} & 0 \end{pmatrix} \end{array} \right\} \end{array}
(1.2.34)

for which the k={0,1}.k = \left\{ 0,1 \right\}.Pro­ceed­ing, we dif­fer­en­ti­ate G′(x1X1ℂ)G^{'}\left( {x_{1}X}_{1}^{\mathbb{C}} \right) to find the dif­fer­en­tial form anal­o­gous to the ac­cel­er­a­tion of the G(x1X1ℂ)G\left( {x_{1}X}_{1}^{\mathbb{C}} \right) group,

G′′(x1X1ℂ)=ddx1G′(x1X1ℂ)=(−eix1000−cos⁡(x1)−isin(x1)0−isin(x1)−cos(x1)),\begin{array}{r} G^{''}\left( {x_{1}X}_{1}^{\mathbb{C}} \right) = \frac{d}{dx_{1}}G^{'}\left( {x_{1}X}_{1}^{\mathbb{C}} \right) = \begin{pmatrix} {- e}^{ix_{1}} & 0 & 0 \\ 0 & {- \cos}\left( x_{1} \right) & - isin\left( x_{1} \right) \\ 0 & - isin\left( x_{1} \right) & {- cos}\left( x_{1} \right) \end{pmatrix}, \end{array}
(1.2.35)

which is also com­prised of five dis­tinct ac­cel­er­a­tion vector func­tions ∈ℂ3\in \mathbb{C}^{3} space. For G′(x1X1ℂ),G^{'}\left( {x_{1}X}_{1}^{\mathbb{C}} \right),we look to find the Lie al­ge­bra that cap­tures the essence of the group, which we denote (x1X1ℂ)′\left( {x_{1}X}_{1}^{\mathbb{C}} \right)', and then con­sid­er the (x1X1ℂ)′\left( {x_{1}X}_{1}^{\mathbb{C}} \right)^{'} de­riv­a­tive al­ge­bras as a whole ∈(𝔤ℂ)′\in \left( \mathfrak{g}^{\mathbb{C}} \right)^{'}. To do this, we first note a phase shift of the x1x_{1} ar­gu­ment by iπ2\frac{i\pi}{2} ra­di­ans will bring an ini­tial ex­po­nen­tial func­tion cen­tered at the iden­ti­ty e(0)=1e^{(0)} = 1, to the func­tion e(iπ2)=i.e^{\left( \frac{i\pi}{2} \right)} = i.In the frame­work of phase-shift­ing lies the key to how the Lie al­ge­bra changes by the dif­fer­en­ti­a­tion of the co­in­cid­ing Lie group. For in­stance, the de­riv­a­tive of a group G=eiXtG = e^{iXt}

G′=ieiXt,\begin{array}{r} G^{'} = {ie}^{iXt}, \end{array}
(1.2.36)

can be put into a form that is more con­sis­tent with the phase-shift­ing con­cept, as

G′=e(iXt+iπ2),\begin{array}{r} G^{'} = e^{\left( iXt + \frac{i\pi}{2} \right)}, \end{array}
(1.2.37)

where G′G'is phase-shift­ed by iπ2\frac{i\pi}{2} com­pared to G.G.By ap­ply­ing a sim­i­lar phase-shift for the Lie al­ge­bra rep­re­sent­ing G′(x1X1ℂ)G^{'}\left( {x_{1}X}_{1}^{\mathbb{C}} \right), we find

(x1X1ℂ)′  =(i(x1+π2)0000i(x1+π2)0i(x1+π2)0),\begin{array}{r} \left( {x_{1}X}_{1}^{\mathbb{C}} \right)^{'}\ \ = \begin{pmatrix} i\left( x_{1} + \frac{\pi}{2} \right) & 0 & 0 \\ 0 & 0 & i\left( x_{1} + \frac{\pi}{2} \right) \\ 0 & i\left( x_{1} + \frac{\pi}{2} \right) & 0 \end{pmatrix}, \end{array}
(1.2.38)

whose ex­po­nen­tial map­ping is the de­sired group de­riv­a­tive G′(x1X1ℂ)G^{'}\left( {x_{1}X}_{1}^{\mathbb{C}} \right)

exp⁡((x1X1ℂ)′)=G′(x1X1ℂ).\begin{array}{r} \exp\left( \left( {x_{1}X}_{1}^{\mathbb{C}} \right)^{'} \right) = G^{'}\left( {x_{1}X}_{1}^{\mathbb{C}} \right). \end{array}
(1.2.39)

A sim­i­lar phase-shift­ing of the other Lie al­ge­bras of the group, (Xjℂ)′∈(𝔤ℂ)′\left( X_{j}^{\mathbb{C}} \right)^{'} \in \left( \mathfrak{g}^{\mathbb{C}} \right)^{'}, leads to the fol­low­ing dif­fer­en­tial al­ge­bras

(x1X1ℂ)′=±{(i(x1+π2)0000i(x1+π2)0i(x1+π2)0),   (00i(x2+π2)0i(x2+π2)0i(x2+π2)00),(0i(x3+π2)0i(x3+π2)0000i(x3+π2))},\begin{array}{r} \left( {x_{1}X}_{1}^{\mathbb{C}} \right)^{'} = \pm \left\{ \begin{array}{r} \begin{pmatrix} i\left( x_{1} + \frac{\pi}{2} \right) & 0 & 0 \\ 0 & 0 & i\left( x_{1} + \frac{\pi}{2} \right) \\ 0 & i\left( x_{1} + \frac{\pi}{2} \right) & 0 \end{pmatrix},\ \ \ \begin{pmatrix} 0 & 0 & i\left( x_{2} + \frac{\pi}{2} \right) \\ 0 & i\left( x_{2} + \frac{\pi}{2} \right) & 0 \\ i\left( x_{2} + \frac{\pi}{2} \right) & 0 & 0 \end{pmatrix}, \\ \begin{pmatrix} 0 & i\left( x_{3} + \frac{\pi}{2} \right) & 0 \\ i\left( x_{3} + \frac{\pi}{2} \right) & 0 & 0 \\ 0 & 0 & i\left( x_{3} + \frac{\pi}{2} \right) \end{pmatrix} \end{array} \right\}, \end{array}
(1.2.40)

where for brevi­ty, the ±\pm sign is used to rep­re­sent the six al­ge­bras in the sub­group. The link be­tween the phase-shift and the matrix log­a­rithm should be an ob­vi­ous one, and for the (x1X1ℂ)′\left( {x_{1}X}_{1}^{\mathbb{C}} \right)^{'} al­ge­bra, this is seen by cen­ter­ing the vari­able at xk=1x_{k} = 1, then eval­u­at­ing the log­a­rithm of the el­e­ments

ϕ[1]=ln⁡(xk(1)e(iπ2))=ln⁡(1)+ln⁡(e(iπ2))=iπ2,\begin{array}{r} \phi_{\lbrack 1\rbrack} = \ln\left( {x_{k}(1)e}^{\left( \frac{i\pi}{2} \right)} \right) = \ln(1) + \ln\left( e^{\left( \frac{i\pi}{2} \right)} \right) = \frac{i\pi}{2}, \end{array}
(1.2.41)

where ϕ[1]\phi_{\lbrack 1\rbrack} de­notes the amount of phase-shift oc­cur­ring for the first de­riv­a­tive of a par­tic­u­lar el­e­ment ∈(x1X1ℂ)′\in \left( {x_{1}X}_{1}^{\mathbb{C}} \right)^{'}. For higher-order de­riv­a­tives of the G(x1X1ℂ)G\left( {x_{1}X}_{1}^{\mathbb{C}} \right) Lie groups, the phase shifts will equal

ϕ[n]=ln⁡(xk(1)[e(iπ2)]n)=iπn2,\begin{array}{r} \phi_{\lbrack n\rbrack} = \ln\left( x_{k}(1)\left\lbrack e^{\left( \frac{i\pi}{2} \right)} \right\rbrack^{n} \right) = \frac{i\pi n}{2}, \end{array}
(1.2.42)

which are simply mul­ti­ples of the phase shift of the first-order de­riv­a­tive al­ge­bra (x1X1ℂ)′\left( {x_{1}X}_{1}^{\mathbb{C}} \right)^{'}. There­fore, the nthn^{th} de­riv­a­tive of the con­tin­u­ous Lie groups G(x1X1ℂ)G\left( {x_{1}X}_{1}^{\mathbb{C}} \right) will have the de­riv­a­tive al­ge­bra forms

(x1X1ℂ)′[n]={(i(x1+πn2)0000i(x1+πn2)0i(x1+πn2)0),   (00i(x2+πn2)0i(x2+πn2)0i(x2+πn2)00),(0i(x3+πn2)0i(x3+πn2)0000i(x3+πn2))}.\begin{array}{r} \left( {x_{1}X}_{1}^{\mathbb{C}} \right)^{'\lbrack n\rbrack} = \left\{ \begin{array}{r} \begin{pmatrix} i\left( x_{1} + \frac{\pi n}{2} \right) & 0 & 0 \\ 0 & 0 & i\left( x_{1} + \frac{\pi n}{2} \right) \\ 0 & i\left( x_{1} + \frac{\pi n}{2} \right) & 0 \end{pmatrix},\ \ \ \begin{pmatrix} 0 & 0 & i\left( x_{2} + \frac{\pi n}{2} \right) \\ 0 & i\left( x_{2} + \frac{\pi n}{2} \right) & 0 \\ i\left( x_{2} + \frac{\pi n}{2} \right) & 0 & 0 \end{pmatrix}, \\ \begin{pmatrix} 0 & i\left( x_{3} + \frac{\pi n}{2} \right) & 0 \\ i\left( x_{3} + \frac{\pi n}{2} \right) & 0 & 0 \\ 0 & 0 & i\left( x_{3} + \frac{\pi n}{2} \right) \end{pmatrix} \end{array} \right\}. \end{array}
(1.2.43)

We recall the yjYjℂy_{j}Y_{j}^{\mathbb{C}} el­e­ments that form a sub­group ∈𝔤ℂ\in \mathfrak{g}^{\mathbb{C}}

yjYjℂ={(y1000y1000y1),   (0y2000y2y200),   (00y3y3000y30)},\begin{array}{r} {y_{j}Y}_{j}^{\mathbb{C}} = \left\{ \begin{pmatrix} y_{1} & 0 & 0 \\ 0 & y_{1} & 0 \\ 0 & 0 & y_{1} \end{pmatrix},\ \ \ \begin{pmatrix} 0 & y_{2} & 0 \\ 0 & 0 & y_{2} \\ y_{2} & 0 & 0 \end{pmatrix},\ \ \ \begin{pmatrix} 0 & 0 & y_{3} \\ y_{3} & 0 & 0 \\ 0 & y_{3} & 0 \end{pmatrix} \right\}, \end{array}
(1.2.44)

and we con­sid­er de­riv­a­tives of their ex­po­nen­tial map­pings using the di­ag­o­nal­iza­tion tech­nique

yjYjℂ=VjℂDjℂ(Vjℂ)−1.\begin{array}{r} {y_{j}Y}_{j}^{\mathbb{C}} = V_{j}^{\mathbb{C}}D_{j}^{\mathbb{C}}\left( V_{j}^{\mathbb{C}} \right)^{- 1}. \end{array}
(1.2.45)

Taking the Y2ℂY_{2}^{\mathbb{C}} al­ge­bra, this can be ex­pressed as the fol­low­ing prod­uct of nor­mal­ized eigen­vec­tors and di­ag­o­nal matrix of eigen­val­ues

y2Y2ℂ=13(1e(−2iπ3)e(2iπ3)1e(2iπ3)e(−2iπ3)111)(y2e0000y2e(−2iπ3)000y2e(2iπ3))(111e(2iπ3)e(−2iπ3)1e(−2iπ3)e(2iπ3)1),\begin{array}{r} {y_{2}Y}_{2}^{\mathbb{C}} = \frac{1}{3}\begin{pmatrix} 1 & e^{\left( - \frac{2i\pi}{3} \right)} & e^{\left( \frac{2i\pi}{3} \right)} \\ 1 & e^{\left( \frac{2i\pi}{3} \right)} & e^{\left( - \frac{2i\pi}{3} \right)} \\ 1 & 1 & 1 \end{pmatrix}\begin{pmatrix} y_{2}e^{0} & 0 & 0 \\ 0 & y_{2}e^{\left( - \frac{2i\pi}{3} \right)} & 0 \\ 0 & 0 & y_{2}e^{\left( \frac{2i\pi}{3} \right)} \end{pmatrix}\begin{pmatrix} 1 & 1 & 1 \\ e^{\left( \frac{2i\pi}{3} \right)} & e^{\left( - \frac{2i\pi}{3} \right)} & 1 \\ e^{\left( - \frac{2i\pi}{3} \right)} & e^{\left( \frac{2i\pi}{3} \right)} & 1 \end{pmatrix}, \end{array}
(1.2.46)

which sim­pli­fies the abil­i­ty to cal­cu­late the ex­po­nen­tial map­ping of Y2ℂY_{2}^{\mathbb{C}}

G(y2Y2ℂ)=exp⁡(y2Y2ℂ)=V2ℂeD2ℂ(V2ℂ)−1=V2ℂ(ey2000e(y2e(− 2iπ3))000e(y2e(2iπ3)))(V2ℂ)−1,\begin{array}{r} G\left( {y_{2}Y}_{2}^{\mathbb{C}} \right) = \exp\left( {y_{2}Y}_{2}^{\mathbb{C}} \right) = V_{2}^{\mathbb{C}}e^{D_{2}^{\mathbb{C}}}\left( V_{2}^{\mathbb{C}} \right)^{- 1} = V_{2}^{\mathbb{C}}\begin{pmatrix} e^{y_{2}} & 0 & 0 \\ 0 & e^{\left( y_{2}e^{\left( - \ \frac{2i\pi}{3} \right)} \right)} & 0 \\ 0 & 0 & e^{\left( y_{2}e^{\left( \frac{2i\pi}{3} \right)} \right)} \end{pmatrix}\left( V_{2}^{\mathbb{C}} \right)^{- 1}, \end{array}
(1.2.47)

where only the di­ag­o­nal eigen­val­ues need to be ex­po­nen­ti­at­ed. Like what was found in the last sec­tion for exp⁡(−y2Y2ℂ)\exp\left( - {y_{2}Y}_{2}^{\mathbb{C}} \right), the matrix group G(y2Y2ℂ)G\left( {y_{2}Y}_{2}^{\mathbb{C}} \right) is com­posed of a sim­i­lar arrange­ment of cyclic trigono­met­ric func­tions

G(y2Y2ℂ)=(𝔒03𝔒13𝔒23𝔒23𝔒03𝔒13𝔒13𝔒23𝔒03),\begin{array}{r} G\left( {y_{2}Y}_{2}^{\mathbb{C}} \right) = \begin{pmatrix} \mathfrak{O}_{0}^{3} & \mathfrak{O}_{1}^{3} & \mathfrak{O}_{2}^{3} \\ \mathfrak{O}_{2}^{3} & \mathfrak{O}_{0}^{3} & \mathfrak{O}_{1}^{3} \\ \mathfrak{O}_{1}^{3} & \mathfrak{O}_{2}^{3} & \mathfrak{O}_{0}^{3} \end{pmatrix}, \end{array}
(1.2.48)

and using this eigen­vec­tor/eigen­val­ue matrix prod­uct de­com­po­si­tion, more in­tu­itive ex­pres­sions for each come in the form of the ex­po­nen­tial func­tion com­po­si­tions

𝔒03=13(ey2+e(y2e(2iπ3))+e(y2e(−2iπ3))),\begin{array}{r} \mathfrak{O}_{0}^{3} = \frac{1}{3}\left( e^{y_{2}} + e^{\left( y_{2}e^{\left( \frac{2i\pi}{3} \right)} \right)} + e^{\left( y_{2}e^{\left( - \frac{2i\pi}{3} \right)} \right)} \right), \end{array}
(1.2.49)
𝔒23=13(ey2+e(y2e(2iπ3)+2iπ3)+e(y2e(−2iπ3)−2iπ3)),\begin{array}{r} \mathfrak{O}_{2}^{3} = \frac{1}{3}\left( e^{y_{2}} + e^{\left( y_{2}e^{\left( \frac{2i\pi}{3} \right)} + \frac{2i\pi}{3} \right)} + e^{\left( y_{2}e^{\left( - \frac{2i\pi}{3} \right)} - \frac{2i\pi}{3} \right)} \right), \end{array}
(1.2.50)
𝔒13=13(ey2+e(y2e(2iπ3)−2iπ3)+e(y2e(−2iπ3)+2iπ3)).\begin{array}{r} \mathfrak{O}_{1}^{3} = \frac{1}{3}\left( e^{y_{2}} + e^{\left( y_{2}e^{\left( \frac{2i\pi}{3} \right)} - \frac{2i\pi}{3} \right)} + e^{\left( y_{2}e^{\left( - \frac{2i\pi}{3} \right)} + \frac{2i\pi}{3} \right)} \right). \end{array}
(1.2.51)

Above, each func­tion can be seen as a sum of the ex­po­nen­tial map­pings of the eigen­val­ues of y2Y2ℂ{y_{2}Y}_{2}^{\mathbb{C}}, with phase-shifts of −2iπ3- \frac{2i\pi}{3} or 2iπ3\frac{2i\pi}{3} for each func­tion's second two ex­po­nen­tial func­tions. The di­ag­o­nal­iza­tion tech­nique also en­ables us to sim­pli­fy the ap­proach to find­ing matrix-scalar de­riv­a­tives. For the G(y2Y2ℂ)G\left( {y_{2}Y}_{2}^{\mathbb{C}} \right) group, we can eval­u­ate the de­riv­a­tive by way of the dif­fer­en­tial of the di­ag­o­nal­ized por­tion

G′(y2Y2ℂ)=V2ℂ(ddy2[eD2ℂ])(V2ℂ)−1,\begin{array}{r} G^{'}\left( {y_{2}Y}_{2}^{\mathbb{C}} \right) = V_{2}^{\mathbb{C}}\left( \frac{d}{dy_{2}}\left\lbrack e^{D_{2}^{\mathbb{C}}} \right\rbrack \right)\left( V_{2}^{\mathbb{C}} \right)^{- 1}, \end{array}
(1.2.52)

and find for the pos­i­tive­ly-valued y2Y2ℂ{y_{2}Y}_{2}^{\mathbb{C}}

(eD2ℂ)′=ddy2(ey2000e(y2e(−2iπ3))000e(y2e(2iπ3)))=(ey2000e(−2iπ3)e(y2e(−2iπ3))000e(2iπ3)e(y2e(2iπ3))),\begin{array}{r} \left( e^{D_{2}^{\mathbb{C}}} \right)^{'} = \frac{d}{dy_{2}}\begin{pmatrix} e^{y_{2}} & 0 & 0 \\ 0 & e^{\left( y_{2}e^{\left( - \frac{2i\pi}{3} \right)} \right)} & 0 \\ 0 & 0 & e^{\left( y_{2}e^{\left( \frac{2i\pi}{3} \right)} \right)} \end{pmatrix} = \begin{pmatrix} e^{y_{2}} & 0 & 0 \\ 0 & e^{\left( - \frac{2i\pi}{3} \right)}e^{\left( y_{2}e^{\left( - \frac{2i\pi}{3} \right)} \right)} & 0 \\ 0 & 0 & e^{\left( \frac{2i\pi}{3} \right)}e^{\left( y_{2}e^{\left( \frac{2i\pi}{3} \right)} \right)} \end{pmatrix}, \end{array}
(1.2.53)

which, in terms of phase-shift­ing, is

(eD2ℂ)′=(ey2000e(y2e(−2iπ3)−2iπ3)000e(y2e(2iπ3)+2iπ3)).\begin{array}{r} \left( e^{D_{2}^{\mathbb{C}}} \right)^{'} = \begin{pmatrix} e^{y_{2}} & 0 & 0 \\ 0 & e^{\left( y_{2}e^{\left( - \frac{2i\pi}{3} \right)} - \frac{2i\pi}{3} \right)} & 0 \\ 0 & 0 & e^{\left( y_{2}e^{\left( \frac{2i\pi}{3} \right)} + \frac{2i\pi}{3} \right)} \end{pmatrix}. \end{array}
(1.2.54)

Taking the log­a­rithm of a phase-shift­ed di­ag­o­nal matrix is straight­for­ward

ln⁡((eD2ℂ)′)=(ln⁡(ey2)000ln⁡(e(y2e(− 2iπ3)− 2iπ3))000ln⁡(e(y2e(2iπ3)+ 2iπ3)))=(y2000y2e(− 2iπ3)−2iπ3000y2e(2iπ3)+2iπ3),\begin{array}{r} \ln{\left( \left( e^{D_{2}^{\mathbb{C}}} \right)^{'} \right) =}\begin{pmatrix} \ln\left( e^{y_{2}} \right) & 0 & 0 \\ 0 & \ln\left( e^{\left( y_{2}e^{\left( - \ \frac{2i\pi}{3} \right)} - \ \frac{2i\pi}{3} \right)} \right) & 0 \\ 0 & 0 & \ln\left( e^{\left( y_{2}e^{\left( \frac{2i\pi}{3} \right)} + \ \frac{2i\pi}{3} \right)} \right) \end{pmatrix} = \begin{pmatrix} y_{2} & 0 & 0 \\ 0 & y_{2}e^{\left( - \ \frac{2i\pi}{3} \right)} - \frac{2i\pi}{3} & 0 \\ 0 & 0 & y_{2}e^{\left( \frac{2i\pi}{3} \right)} + \frac{2i\pi}{3} \end{pmatrix}, \end{array}
(1.2.55)

and the first-order de­riv­a­tive al­ge­bra (Y2ℂ)′\left( Y_{2}^{\mathbb{C}} \right)^{'} is de­ter­mined to be

(y2Y2ℂ)′=V2ℂ(ln⁡((eD2ℂ)′))(V2ℂ)−1=(0y2+2π3(13)−2π3(13)−2π3(13)0y2+2π3(13)y2+2π3(13)−2π3(13)0),\begin{array}{r} \left( y_{2}Y_{2}^{\mathbb{C}} \right)^{'} = V_{2}^{\mathbb{C}}\left( \ln\left( \left( e^{D_{2}^{\mathbb{C}}} \right)^{'} \right) \right)\left( V_{2}^{\mathbb{C}} \right)^{- 1} = \begin{pmatrix} 0 & y_{2} + \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) & - \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) \\ - \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) & 0 & y_{2} + \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) \\ y_{2} + \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) & - \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) & 0 \end{pmatrix}, \end{array}
(1.2.56)

where the sum of non-vari­able terms equals zero

2π3(13)−2π3(13)=0.\begin{array}{r} \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) - \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) = 0. \end{array}
(1.2.57)

The second de­riv­a­tive for G(y2Y2ℂ)G\left( {y_{2}Y}_{2}^{\mathbb{C}} \right) is de­ter­mined by

G′′(y2Y2ℂ)=V2ℂ(d2dy22[eD2ℂ])(V2ℂ)−1=G((y2Y2ℂ)′′),\begin{array}{r} G^{''}\left( {y_{2}Y}_{2}^{\mathbb{C}} \right) = V_{2}^{\mathbb{C}}\left( \frac{d^{2}}{dy_{2}^{2}}\left\lbrack e^{D_{2}^{\mathbb{C}}} \right\rbrack \right)\left( V_{2}^{\mathbb{C}} \right)^{- 1} = G\left( \left( {y_{2}Y}_{2}^{\mathbb{C}} \right)^{''} \right), \end{array}
(1.2.58)

and is equiv­a­lent to the matrix ex­po­nen­tial map­ping of the second-order de­riv­a­tive al­ge­bra (y2Y2ℂ)′′\left( {y_{2}Y}_{2}^{\mathbb{C}} \right)^{''}. A sim­i­lar process for (y2Y2ℂ)′′\left( {y_{2}Y}_{2}^{\mathbb{C}} \right)^{''} yields

(y2Y2ℂ)′′=(0y2−2π3(13)2π3(13)2π3(13)0y2−2π3(13)y2−2π3(13)2π3(13)0),\begin{array}{r} \left( {y_{2}Y}_{2}^{\mathbb{C}} \right)^{''} = \begin{pmatrix} 0 & y_{2} - \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) & \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) \\ \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) & 0 & y_{2} - \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) \\ y_{2} - \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) & \frac{2\pi}{3}\left( \frac{1}{\sqrt{3}} \right) & 0 \end{pmatrix}, \end{array}
(1.2.59)

and by eval­u­at­ing the third de­riv­a­tive for G(y2Y2ℂ)G\left( {y_{2}Y}_{2}^{\mathbb{C}} \right), we find the Lie al­ge­bra re­turns to the orig­i­nal Y2ℂY_{2}^{\mathbb{C}} form

(y2Y2ℂ)′′′=(0y2000y2y200).\begin{array}{r} \left( {y_{2}Y}_{2}^{\mathbb{C}} \right)^{'''} = \begin{pmatrix} 0 & y_{2} & 0 \\ 0 & 0 & y_{2} \\ y_{2} & 0 & 0 \end{pmatrix}. \end{array}
(1.2.60)

The ex­po­nen­tial map­ping of the y2Y2ℂ{y_{2}Y}_{2}^{\mathbb{C}} and y3Y3ℂ{y_{3}Y}_{3}^{\mathbb{C}} al­ge­bras result in odd splits of the ex­po­nen­tial func­tion for its trigono­met­ric func­tions, and three dis­tinct de­riv­a­tive al­ge­bras in y2Y2ℂ,(y2Y2ℂ)′,(y2Y2ℂ)′′.{y_{2}Y}_{2}^{\mathbb{C}},\left( {y_{2}Y}_{2}^{\mathbb{C}} \right)^{'},\left( {y_{2}Y}_{2}^{\mathbb{C}} \right)^{''}.As a sub­group ∈(𝔤ℂ)′\in \left( \mathfrak{g}^{\mathbb{C}} \right)^{'}, the (yjYjℂ)′\left( {y_{j}Y}_{j}^{\mathbb{C}} \right)^{'} dif­fer­en­tial al­ge­bras are the fol­low­ing, noting that the result can be both pos­i­tive or neg­a­tive as this hap­pens in the com­plex domain,

(yjYjℂ)′={(y1000y1000y1),   (0y2+2π33−2π33−2π330y2+2π33y2+2π33−2π330),   (0y3−2π332π332π330y3−2π33y3−2π332π330)(−y1000−y1000−y1),   (iπ32π33(e2iπ3)−y22π33(eiπ3)2π33(eiπ3)iπ32π33(e2iπ3)−y22π33(e2iπ3)−y22π33(eiπ3)iπ3),(iπ32π33(eiπ3)2π33(e2iπ3)−y32π33(e2iπ3)−y3iπ32π33(eiπ3)2π33(eiπ3)2π33(e2iπ3)−y3iπ3)}.\begin{array}{r} \left( {y_{j}Y}_{j}^{\mathbb{C}} \right)^{'} = \left\{ \begin{array}{r} \begin{pmatrix} y_{1} & 0 & 0 \\ 0 & y_{1} & 0 \\ 0 & 0 & y_{1} \end{pmatrix},\ \ \ \begin{pmatrix} 0 & y_{2} + \frac{2\pi}{3\sqrt{3}} & - \frac{2\pi}{3\sqrt{3}} \\ - \frac{2\pi}{3\sqrt{3}} & 0 & y_{2} + \frac{2\pi}{3\sqrt{3}} \\ y_{2} + \frac{2\pi}{3\sqrt{3}} & - \frac{2\pi}{3\sqrt{3}} & 0 \end{pmatrix},\ \ \ \begin{pmatrix} 0 & y_{3} - \frac{2\pi}{3\sqrt{3}} & \frac{2\pi}{3\sqrt{3}} \\ \frac{2\pi}{3\sqrt{3}} & 0 & y_{3} - \frac{2\pi}{3\sqrt{3}} \\ y_{3} - \frac{2\pi}{3\sqrt{3}} & \frac{2\pi}{3\sqrt{3}} & 0 \end{pmatrix} \\ \begin{pmatrix} - y_{1} & 0 & 0 \\ 0 & {- y}_{1} & 0 \\ 0 & 0 & {- y}_{1} \end{pmatrix},\ \ \ \begin{pmatrix} \frac{i\pi}{3} & \frac{2\pi}{3\sqrt{3}}\left( e^{\frac{2i\pi}{3}} \right) - y_{2} & \frac{2\pi}{3\sqrt{3}}\left( e^{\frac{i\pi}{3}} \right) \\ \frac{2\pi}{3\sqrt{3}}\left( e^{\frac{i\pi}{3}} \right) & \frac{i\pi}{3} & \frac{2\pi}{3\sqrt{3}}\left( e^{\frac{2i\pi}{3}} \right) - y_{2} \\ \frac{2\pi}{3\sqrt{3}}\left( e^{\frac{2i\pi}{3}} \right) - y_{2} & \frac{2\pi}{3\sqrt{3}}\left( e^{\frac{i\pi}{3}} \right) & \frac{i\pi}{3} \end{pmatrix} \\ \begin{array}{r} , \\ \begin{pmatrix} \frac{i\pi}{3} & \frac{2\pi}{3\sqrt{3}}\left( e^{\frac{i\pi}{3}} \right) & \frac{2\pi}{3\sqrt{3}}\left( e^{\frac{2i\pi}{3}} \right) - y_{3} \\ \frac{2\pi}{3\sqrt{3}}\left( e^{\frac{2i\pi}{3}} \right) - y_{3} & \frac{i\pi}{3} & \frac{2\pi}{3\sqrt{3}}\left( e^{\frac{i\pi}{3}} \right) \\ \frac{2\pi}{3\sqrt{3}}\left( e^{\frac{i\pi}{3}} \right) & \frac{2\pi}{3\sqrt{3}}\left( e^{\frac{2i\pi}{3}} \right) - y_{3} & \frac{i\pi}{3} \end{pmatrix} \end{array} \end{array} \right\}. \end{array}
(1.2.61)