We are now well versed in the association that integration has with exponentiation and the association that differentiation, the inverse of integration, has with the logarithm. It is important to remember that the infinite number of tangent spaces that reside on the boundary of the infinite sphere of tangent spaces are Lie algebra representations, containing all the information of the whole infinite symmetry group S 3 ℂ ∞ S_{3\mathbb{C}}^{\infty} . The geometric spaces formed by the products of the matrix groups of tangent space elements ∈ 𝔰 3 ℂ ∞ \in \mathfrak{s}_{3\mathbb{C}}^{\infty} , result in the extension of the geometric spaces away from the singularity based on the magnitude of the real-valued portion in the exponential variable e θ r [ m ] e^{\theta_{r}^{\lbrack m\rbrack}} . As θ r [ m ] ∈ ℂ m \theta_{r}^{\lbrack m\rbrack} \in \mathbb{C}^{m} , there is a real portion of the Lie algebra and an imaginary one. We offer the example for θ r [ m ] \theta_{r}^{\lbrack m\rbrack} , with e i θ j ∈ ℂ , | e i θ j | = 1 e^{i\theta_{j}}\in \mathbb{C},\left| e^{i\theta_{j}} \right| = 1 , for an X 1 X_{1} -type element, giving
θ r j [ X 1 ] = ( r 1 e i θ 1 0 0 0 0 r 2 e i θ 2 0 r 3 e i θ 3 0 ) = ( ( a 1 + i b 1 ) 0 0 0 0 ( a 2 + i b 2 ) 0 ( a 3 + i b 3 ) 0 ) = ( z 1 0 0 0 0 z 2 0 z 3 0 ) , \begin{array}{r}
\theta_{r_{j}}^{\left\lbrack X_{1} \right\rbrack} = \begin{pmatrix}
r_{1}e^{i\theta_{1}} & 0 & 0 \\
0 & 0 & r_{2}e^{i\theta_{2}} \\
0 & r_{3}e^{i\theta_{3}} & 0
\end{pmatrix} = \begin{pmatrix}
\left( a_{1} + ib_{1} \right) & 0 & 0 \\
0 & 0 & \left( a_{2} + ib_{2} \right) \\
0 & \left( a_{3} + ib_{3} \right) & 0
\end{pmatrix} = \begin{pmatrix}
z_{1} & 0 & 0 \\
0 & 0 & z_{2} \\
0 & z_{3} & 0
\end{pmatrix},
\end{array} (1.6.251)
for a j , b j ∈ ℝ , z j ∈ ℂ a_{j},b_{j}\in \mathbb{R}\ ,\ z_{j}\in \mathbb{C} . In this section, we will be working with the groups presented in the book and we will use the superscript from θ r j [ m ] \theta_{r_{j}}^{\lbrack m\rbrack} , to insert the dihedral group type and permutation type. Using the X 1 X_{1} permutation type, we can express the Lie algebras of our dihedral groups in terms of their real and imaginary variables
Z j [ R e ( D 3 𝕫 ( X 1 ) ) ] = R e ( z 1 0 0 0 0 z 2 0 z 3 0 ) = ( a 1 0 0 0 0 a 2 0 a 3 0 ) , \begin{array}{r}
Z_{j}^{\left\lbrack {Re(D}_{3\mathbb{z}}\left( X_{1} \right)) \right\rbrack} = Re\begin{pmatrix}
z_{1} & 0 & 0 \\
0 & 0 & z_{2} \\
0 & z_{3} & 0
\end{pmatrix} = \begin{pmatrix}
a_{1} & 0 & 0 \\
0 & 0 & a_{2} \\
0 & a_{3} & 0
\end{pmatrix},
\end{array} (1.6.252)
Z j [ i × I m ( D 3 𝕫 ( X 1 ) ) ] = i × I m ( z 1 0 0 0 0 z 2 0 z 3 0 ) = ( i b 1 0 0 0 0 i b 2 0 i b 3 0 ) , \begin{array}{r}
Z_{j}^{\left\lbrack {i \times Im(D}_{3\mathbb{z}}\left( X_{1} \right)) \right\rbrack} = i \times Im\begin{pmatrix}
z_{1} & 0 & 0 \\
0 & 0 & z_{2} \\
0 & z_{3} & 0
\end{pmatrix} = \begin{pmatrix}
{ib}_{1} & 0 & 0 \\
0 & 0 & {ib}_{2} \\
0 & {ib}_{3} & 0
\end{pmatrix},
\end{array} (1.6.253)
and in the polar form, as
θ r j [ D 3 𝕫 ( X 1 ) ] = ( r 1 e i θ 1 0 0 0 0 r 2 e i θ 2 0 r 3 e i θ 3 0 ) , \begin{array}{r}
\theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} = \begin{pmatrix}
r_{1}e^{i\theta_{1}} & 0 & 0 \\
0 & 0 & r_{2}e^{i\theta_{2}} \\
0 & r_{3}e^{i\theta_{3}} & 0
\end{pmatrix},
\end{array} (1.6.254)
which can be decomposed into the product of its radial modulus matrix and spherical matrix group
θ r j [ D 3 𝕫 ( X 1 ) ] = ( r 1 0 0 0 r 2 0 0 0 r 3 ) ( e i θ 1 0 0 0 0 e i θ 2 0 e i θ 3 0 ) . \begin{array}{r}
\theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} = \begin{pmatrix}
r_{1} & 0 & 0 \\
0 & r_{2} & 0 \\
0 & 0 & r_{3}
\end{pmatrix}\begin{pmatrix}
e^{i\theta_{1}} & 0 & 0 \\
0 & 0 & e^{i\theta_{2}} \\
0 & e^{i\theta_{3}} & 0
\end{pmatrix}.
\end{array} (1.6.255)
Note, the product result will change if the spherical group is right multiplied by the modulus matrix
( e i θ 1 0 0 0 0 e i θ 2 0 e i θ 3 0 ) ( r 1 0 0 0 r 2 0 0 0 r 3 ) = ( r 1 e i θ 1 0 0 0 0 r 3 e i θ 2 0 r 2 e i θ 3 0 ) , \begin{array}{r}
\begin{pmatrix}
e^{i\theta_{1}} & 0 & 0 \\
0 & 0 & e^{i\theta_{2}} \\
0 & e^{i\theta_{3}} & 0
\end{pmatrix}\begin{pmatrix}
r_{1} & 0 & 0 \\
0 & r_{2} & 0 \\
0 & 0 & r_{3}
\end{pmatrix} = \begin{pmatrix}
r_{1}e^{i\theta_{1}} & 0 & 0 \\
0 & 0 & r_{3}e^{i\theta_{2}} \\
0 & r_{2}e^{i\theta_{3}} & 0
\end{pmatrix},
\end{array} (1.6.256)
where the moduli variables have swapped positions in the bottom-right 2 × 2 2 \times 2 submatrix.
The tangent space group θ r j [ D 3 𝕫 ( X 1 ) ] \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} is the result of the exponential mapping of its subtangent form ln ( θ r j [ D 3 𝕫 ( X 1 ) ] ) \ln\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) , and therefore, the subtangent form for Z j [ D 3 𝕫 ( X 1 ) ] Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} is found by the matrix logarithm
ln ( Z j [ D 3 𝕫 ( X 1 ) ] ) = ( ln ( z 1 ) 0 0 0 ln ( z 2 z 3 ) + ln ( − z 2 z 3 ) 2 z 2 z 2 z 3 ( ln ( z 2 z 3 ) − ln ( − z 2 z 3 ) 2 ) 0 z 3 z 2 z 3 ( ln ( z 2 z 3 ) − ln ( − z 2 z 3 ) 2 ) ( ln ( z 2 z 3 ) + ln ( − z 2 z 3 ) ) 2 ) . \begin{array}{r}
\ln{\left( Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = \begin{pmatrix}
\ln\left( z_{1} \right) & 0 & 0 \\
0 & \frac{\ln{\left( \sqrt{z_{2}z_{3}} \right) + \ln\left( - \sqrt{z_{2}z_{3}} \right)}}{2} & \frac{z_{2}}{\sqrt{z_{2}z_{3}}}\left( \frac{\ln{\left( \sqrt{z_{2}z_{3}} \right) - \ln\left( - \sqrt{z_{2}z_{3}} \right)}}{2} \right) \\
0 & \frac{z_{3}}{\sqrt{z_{2}z_{3}}}\left( \frac{\ln{\left( \sqrt{z_{2}z_{3}} \right) - \ln\left( - \sqrt{z_{2}z_{3}} \right)}}{2} \right) & \frac{\left( \ln{\left( \sqrt{z_{2}z_{3}} \right) + \ln\left( - \sqrt{z_{2}z_{3}} \right)} \right)}{2}
\end{pmatrix}}.
\end{array} (1.6.257)
The matrix exponential mapping of the Lie algebra Z j [ D 3 𝕫 ( X 1 ) ] Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} involves the two-fold exponential mapping of the subtangent space G ( Z j [ D 3 𝕫 ( X 1 ) ] ) = exp ( exp ( ln ( Z j [ D 3 𝕫 ( X 1 ) ] ) ) ) G\left( Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = \exp\left( \exp\left( \ln\left( Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) \right) \right) , and is equal to the following form
G ( Z j [ D 3 𝕫 ( X 1 ) ] ) = ( e z 1 0 0 0 cosh ( z 2 z 3 ) z 2 z 2 z 3 sinh ( z 2 z 3 ) 0 z 3 z 2 z 3 sinh ( z 2 z 3 ) cosh ( z 2 z 3 ) ) . \begin{array}{r}
G\left( Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = \begin{pmatrix}
e^{z_{1}} & 0 & 0 \\
0 & \cosh\left( \sqrt{z_{2}z_{3}} \right) & \frac{z_{2}}{\sqrt{{z_{2}z}_{3}}}\sinh\left( \sqrt{z_{2}z_{3}} \right) \\
0 & \frac{z_{3}}{\sqrt{{z_{2}z}_{3}}}\sinh\left( \sqrt{z_{2}z_{3}} \right) & \cosh\left( \sqrt{z_{2}z_{3}} \right)
\end{pmatrix}.
\end{array} (1.6.258)
Conversely, the subtangent space is the result of the two-fold logarithm mapping of the Lie group ln ( ln ( G ( Z j [ D 3 𝕫 ( X 1 ) ] ) ) ) \ln(\ln\left( G\left( Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) \right)) . To express the Lie group G ( Z j [ D 3 𝕫 ( X 1 ) ] ) G\left( Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) in polar form, we algebraically manipulate the variable z 2 z 3 \sqrt{z_{2}z_{3}} to its polar equivalent, as follows
z 2 z 3 = r 2 e i θ 2 × r 3 e i θ 3 \sqrt{z_{2}z_{3}} = \sqrt{r_{2}e^{i\theta_{2}}{\times r}_{3}e^{i\theta_{3}}}
= ( e ln ( r 2 ) + i θ 2 × e ln ( r 3 ) + i θ 3 ) 1 2 = ( e ln ( r 2 r 3 ) + i ( θ 2 + θ 3 ) ) 1 2 = \left( e^{\ln\left( r_{2} \right) + i\theta_{2}}{\times e}^{\ln\left( r_{3} \right) + i\theta_{3}} \right)^{\frac{1}{2}} = \left( e^{\ln\left( r_{2}r_{3} \right) + i\left( \theta_{2} + \theta_{3} \right)} \right)^{\frac{1}{2}}
= e 1 2 ( ln ( r 2 r 3 ) + i ( θ 2 + θ 3 ) ) = r 2 r 3 e i ( θ 2 2 + θ 3 2 ) . \begin{array}{r}
= e^{\frac{1}{2}\left( \ln\left( r_{2}r_{3} \right) + i\left( \theta_{2} + \theta_{3} \right) \right)} = \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)}.
\end{array} (1.6.259)
Next, using the constant z 3 z 2 z 3 \frac{z_{3}}{\sqrt{{z_{2}z}_{3}}} as an example
z 3 z 2 z 3 = r 3 e i θ 3 r 2 r 3 e i ( θ 2 2 + θ 3 2 ) = r 3 r 2 r 3 ( e i θ 3 × e − i ( θ 2 2 + θ 3 2 ) ) = r 3 r 2 r 3 ( e i ( θ 3 2 − θ 2 2 ) ) , \begin{array}{r}
\frac{z_{3}}{\sqrt{{z_{2}z}_{3}}} = \frac{r_{3}e^{i\theta_{3}}}{\sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)}} = \frac{r_{3}}{\sqrt{r_{2}r_{3}}}\left( e^{i\theta_{3}} \times e^{- i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) = \frac{r_{3}}{\sqrt{r_{2}r_{3}}}\left( e^{i\left( \frac{\theta_{3}}{2} - \frac{\theta_{2}}{2} \right)} \right),
\end{array} (1.6.260)
and for r 3 , r 2 ∈ ℝ + r_{3},r_{2} \in \mathbb{R}^{+} , z 3 z 2 z 3 \frac{z_{3}}{\sqrt{{z_{2}z}_{3}}} has the equivalent polar form
r 3 r 2 r 3 ( e i ( θ 3 2 − θ 2 2 ) ) = r 3 r 2 ( e i ( θ 3 2 − θ 2 2 ) ) . \begin{array}{r}
\frac{r_{3}}{\sqrt{r_{2}r_{3}}}\left( e^{i\left( \frac{\theta_{3}}{2} - \frac{\theta_{2}}{2} \right)} \right) = \sqrt{\frac{r_{3}}{r_{2}}}\left( e^{i\left( \frac{\theta_{3}}{2} - \frac{\theta_{2}}{2} \right)} \right).
\end{array} (1.6.261)
Given θ r j [ D 3 𝕫 ( X 1 ) ] = Z j [ D 3 𝕫 ( X 1 ) ] \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} = Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} , their exponential mappings are also equivalent, G ( Z j [ D 3 𝕫 ( X 1 ) ] ) = G ( θ r j [ D 3 𝕫 ( X 1 ) ] ) , G\left( Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right), and the polar form of the Lie group G ( θ r j [ D 3 𝕫 ( X 1 ) ] ) G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) is
G ( θ r j [ D 3 𝕫 ( X 1 ) ] ) = ( e r 1 e i θ 1 0 0 0 cosh ( r 2 r 3 e i ( θ 2 + θ 3 ) / 2 ) r 2 r 3 ( e i ( θ 2 2 − θ 3 2 ) ) sinh ( r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) 0 r 3 r 2 ( e i ( θ 3 2 − θ 2 2 ) ) sinh ( r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) cosh ( r 2 r 3 e i ( θ 2 + θ 3 ) / 2 ) ) . \begin{array}{r}
G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = \begin{pmatrix}
e^{r_{1}e^{i\theta_{1}}} & 0 & 0 \\
0 & \cosh\left( \sqrt{r_{2}r_{3}}e^{i\left( \theta_{2} + \theta_{3} \right)/2} \right) & \sqrt{\frac{r_{2}}{r_{3}}}\left( e^{i\left( \frac{\theta_{2}}{2} - \frac{\theta_{3}}{2} \right)} \right)\sinh\left( \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) \\
0 & \sqrt{\frac{r_{3}}{r_{2}}}\left( e^{i\left( \frac{\theta_{3}}{2} - \frac{\theta_{2}}{2} \right)} \right)\sinh\left( \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) & \cosh\left( \sqrt{r_{2}r_{3}}e^{i\left( \theta_{2} + \theta_{3} \right)/2} \right)
\end{pmatrix}.
\end{array} (1.6.262)
The matrix above represents the exponential mapping of the θ r j [ D 3 𝕫 ( X 1 ) ] \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} tangent space, and given that the matrix determinant relates to the volume of a region, we calculate the determinant of the G( θ r j [ D 3 𝕫 ( X 1 ) ] ) \left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) group
det ( G ( θ r j [ D 3 𝕫 ( X 1 ) ] ) ) = e r 1 e i θ 1 ( ( cosh ( r 2 r 3 e i ( θ 2 + θ 3 ) 2 ) ) 2 − ( r 3 r 2 ( e i ( θ 3 2 − θ 2 2 ) ) sinh ( r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) × r 2 r 3 ( e i ( θ 2 2 − θ 3 2 ) ) sinh ( r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) ) ) \det\left( G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) \right) = e^{r_{1}e^{i\theta_{1}}}\left( \begin{array}{r}
\left( \cosh\left( \sqrt{r_{2}r_{3}}e^{\frac{i\left( \theta_{2} + \theta_{3} \right)}{2}} \right) \right)^{2} \\
- \ \left( \sqrt{\frac{r_{3}}{r_{2}}}\left( e^{i\left( \frac{\theta_{3}}{2} - \frac{\theta_{2}}{2} \right)} \right)\sinh\left( \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) \times \sqrt{\frac{r_{2}}{r_{3}}}\left( e^{i\left( \frac{\theta_{2}}{2} - \frac{\theta_{3}}{2} \right)} \right)\sinh\left( \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) \right)
\end{array} \right)
= e r 1 e i θ 1 ( ( cosh ( r 2 r 3 e i ( θ 2 + θ 3 ) 2 ) ) 2 − ( sinh ( r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) ) 2 ) = e r 1 e i θ 1 ( 1 ) = e r 1 e i θ 1 , \begin{array}{r}
= e^{r_{1}e^{i\theta_{1}}}\left( \begin{array}{r}
\left( \cosh\left( \sqrt{r_{2}r_{3}}e^{\frac{i\left( \theta_{2} + \theta_{3} \right)}{2}} \right) \right)^{2} - \left( \sinh\left( \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) \right)
\end{array}^{2} \right) = e^{r_{1}e^{i\theta_{1}}}(1) = e^{r_{1}e^{i\theta_{1}}},
\end{array} (1.6.263)
where the determinate equals the axis value e r 1 e i θ 1 , e^{r_{1}e^{i\theta_{1}}}, which is equivalent to e z 1 e^{z_{1}} , given that r 1 e i θ 1 = z 1 {r_{1}e^{i\theta_{1}} = z}_{1} . When r 1 = 1 r_{1} = 1 , the determinant will be equal to e e i θ 1 e^{e^{i\theta_{1}}} , which indicates the determinant will vary depending on the angle value θ 1 \theta_{1} . So, real-valued peaks are equal to the constant e e , occurring when θ 1 = 2 π k \theta_{1} = 2\pi k , for k ∈ ℤ k\in \mathbb{Z} . In turn, real-valued troughs occur at e − 1 ≈ 0.3679 e^{- 1} \approx 0.3679 , when θ 1 = π k \theta_{1} = \pi k , for k ∈ ℤ k\in \mathbb{Z} . In a beautiful and analogous manner, imaginary-valued peaks locate at e i ≈ ( 0.5403 + 0.8415 i ) e^{i} \approx (0.5403 + 0.8415i) , occurring when θ 1 = ( π 2 + 2 π k ) \theta_{1} = \left( \frac{\pi}{2} + 2\pi k \right) , for k ∈ ℤ k\in \mathbb{Z} , with troughs at e − t ≈ ( 0.5403 − 0.8415 i ) e^{- t} \approx (0.5403 - 0.8415i) , when θ 1 = ( 3 π 2 + 2 π k ) \theta_{1} = \left( \frac{3\pi}{2} + 2\pi k \right) , for k ∈ ℤ k\in \mathbb{Z} . To better visualize this, we plot the determinant waveforms for G ( θ 1 [ D 3 𝕫 ( X 1 ) ] ) G\left( \theta_{1}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) in Figure 1.6.24 .
Figure 1.6.24 – Plot of det ( G ( θ 1 [ D 3 𝕫 ( X 1 ) ] ) ) = e e i θ 1 . \det\left( G\left( \theta_{1}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) \right) = e^{e^{i\theta_{1}}}.
It is important to notice that the peaks and troughs for the real and imaginary waveforms are equal to the identity when considered as products, since e 1 e − 1 = ϵ e^{1}e^{- 1} = \epsilon and e i e − i = ϵ e^{i}e^{- i} = \epsilon , and the frequency of the imaginary waveform is double that of the real waveform, given the cosine function is an even function, while the sine function is odd. To delineate between the real and imaginary components of G ( θ r j [ D 3 𝕫 ( X 1 ) ] ) G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) , we can use the following hyperbolic identities
sinh ( r e i θ ) = cos ( r s i n ( θ ) ) sinh ( r c o s ( θ ) ) + i s i n ( r s i n ( θ ) ) cosh ( r c o s ( θ ) ) , \begin{array}{r}
{\sinh\left( re^{i\theta} \right) =}{\cos{\left( rsin(\theta) \right)\sinh{\left( rcos(\theta) \right) + isin\left( rsin(\theta) \right)\cosh\left( rcos(\theta) \right)}}},
\end{array} (1.6.264)
cosh ( r e i θ ) = cos ( r s i n ( θ ) ) cosh ( r c o s ( θ ) ) + i s i n ( r s i n ( θ ) ) sinh ( r c o s ( θ ) ) , \begin{array}{r}
\cosh\left( re^{i\theta} \right) = \cos{\left( rsin(\theta) \right)\cosh{\left( rcos(\theta) \right) + isin\left( rsin(\theta) \right)\sinh\left( rcos(\theta) \right)}},
\end{array} (1.6.265)
and substitute r = r 2 r 3 r = \sqrt{r_{2}r_{3}} , e i θ = e i ( θ 2 + θ 3 ) / 2 , e^{i\theta} = e^{i\left( \theta_{2} + \theta_{3} \right)/2}, to express the matrix group in the matrix figure below.
( e r 1 e i θ 1 0 0 0 ( cos ( r 2 r 3 sin ( θ 2 2 + θ 3 2 ) ) cosh ( r 2 r 3 cos ( θ 2 2 + θ 3 2 ) ) + i s i n ( r 2 r 3 sin ( θ 2 2 + θ 3 2 ) ) sinh ( r 2 r 3 cos ( θ 2 2 + θ 3 2 ) ) ) r 2 r 3 ( e i ( θ 2 2 − θ 3 2 ) ) ( cos ( r 2 r 3 sin ( θ 2 2 + θ 3 2 ) ) sinh ( r 2 r 3 cos ( θ 2 2 + θ 3 2 ) ) + i s i n ( r 2 r 3 sin ( θ 2 2 + θ 3 2 ) ) cosh ( r 2 r 3 cos ( θ 2 2 + θ 3 2 ) ) ) 0 r 3 r 2 ( e i ( θ 3 2 − θ 2 2 ) ) ( cos ( r 2 r 3 sin ( θ 2 2 + θ 3 2 ) ) sinh ( r 2 r 3 cos ( θ 2 2 + θ 3 2 ) ) + i s i n ( r 2 r 3 sin ( θ 2 2 + θ 3 2 ) ) cosh ( r 2 r 3 cos ( θ 2 2 + θ 3 2 ) ) ) ( cos ( r 2 r 3 sin ( θ 2 2 + θ 3 2 ) ) cosh ( r 2 r 3 cos ( θ 2 2 + θ 3 2 ) ) + i s i n ( r 2 r 3 sin ( θ 2 2 + θ 3 2 ) ) sinh ( r 2 r 3 cos ( θ 2 2 + θ 3 2 ) ) ) ) \begin{array}{r}
\begin{pmatrix}
e^{r_{1}e^{i\theta_{1}}} & 0 & 0 \\
0 & \left( \begin{array}{r}
{\cos\left( \sqrt{r_{2}r_{3}}\sin\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)\cosh}\left( \sqrt{r_{2}r_{3}}\cos\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right) \\
+ \ isin\left( \sqrt{r_{2}r_{3}}\sin\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)\sinh\left( \sqrt{r_{2}r_{3}}\cos\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)
\end{array} \right) & \sqrt{\frac{r_{2}}{r_{3}}}\left( e^{i\left( \frac{\theta_{2}}{2} - \frac{\theta_{3}}{2} \right)} \right)\left( \begin{array}{r}
{\cos\left( \sqrt{r_{2}r_{3}}\sin\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)\sinh}\left( \sqrt{r_{2}r_{3}}\cos\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right) \\
+ \ isin\left( \sqrt{r_{2}r_{3}}\sin\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)\cosh\left( \sqrt{r_{2}r_{3}}\cos\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)
\end{array} \right) \\
0 & \sqrt{\frac{r_{3}}{r_{2}}}\left( e^{i\left( \frac{\theta_{3}}{2} - \frac{\theta_{2}}{2} \right)} \right)\left( \begin{array}{r}
{\cos\left( \sqrt{r_{2}r_{3}}\sin\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)\sinh}\left( \sqrt{r_{2}r_{3}}\cos\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right) \\
+ \ isin\left( \sqrt{r_{2}r_{3}}\sin\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)\cosh\left( \sqrt{r_{2}r_{3}}\cos\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)
\end{array} \right) & \left( \begin{array}{r}
{\cos\left( \sqrt{r_{2}r_{3}}\sin\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)\cosh}\left( \sqrt{r_{2}r_{3}}\cos\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right) \\
+ \ isin\left( \sqrt{r_{2}r_{3}}\sin\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)\sinh\left( \sqrt{r_{2}r_{3}}\cos\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)
\end{array} \right)
\end{pmatrix}
\end{array} Figure 1.6.25 – The Matrix Group, G ( θ r j [ D 3 𝕫 ( X 1 ) ] ) G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) .
In the G ( θ r j [ D 3 𝕫 ( X 1 ) ] ) G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) matrix above, it becomes apparent that the group is a mix of hyperbolic and circle trigonometric functions, and the group can be considered as a product of two distinct matrix group types, the exponential complex circular form
G ( θ r j [ D 3 𝕫 ( I m ( X 1 ) ) ] ) = ( e i b 1 0 0 0 r 2 r 3 cos ( r 2 r 3 sin ( θ 2 2 + θ 3 2 ) ) e i ( θ 2 2 − θ 3 2 ) i s i n ( r 2 r 3 sin ( θ 2 2 + θ 3 2 ) ) 0 e i ( θ 3 2 − θ 2 2 ) i s i n ( r 2 r 3 sin ( θ 2 2 + θ 3 2 ) ) r 3 r 2 cos ( r 2 r 3 sin ( θ 2 2 + θ 3 2 ) ) ) , \begin{array}{r}
G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( {Im\ (X}_{1}) \right) \right\rbrack} \right) = \begin{pmatrix}
e^{ib_{1}} & 0 & 0 \\
0 & \sqrt{\frac{r_{2}}{r_{3}}}\cos\left( \sqrt{r_{2}r_{3}}\sin\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right) & e^{i\left( \frac{\theta_{2}}{2} - \frac{\theta_{3}}{2} \right)}isin\left( \sqrt{r_{2}r_{3}}\sin\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right) \\
0 & e^{i\left( \frac{\theta_{3}}{2} - \frac{\theta_{2}}{2} \right)}isin\left( \sqrt{r_{2}r_{3}}\sin\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right) & {\sqrt{\frac{r_{3}}{r_{2}}}\cos}\left( \sqrt{r_{2}r_{3}}\sin\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)
\end{pmatrix},
\end{array} (1.6.266)
and the hyperbolic exponential form
G ( θ r j [ D 3 𝕫 ( R e ( X 1 ) ) ] ) = ( e a 1 0 0 0 r 3 r 2 cosh ( r 2 r 3 cos ( θ 2 2 + θ 3 2 ) ) e i ( θ 2 2 − θ 3 2 ) ( sinh ( r 2 r 3 cos ( θ 2 2 + θ 3 2 ) ) ) 0 e i ( θ 3 2 − θ 2 2 ) ( sinh ( r 2 r 3 cos ( θ 2 2 + θ 3 2 ) ) ) r 2 r 3 cosh ( r 2 r 3 cos ( θ 2 2 + θ 3 2 ) ) ) , \begin{array}{r}
G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( {Re\ (X}_{1}) \right) \right\rbrack} \right) = \begin{pmatrix}
e^{a_{1}} & 0 & 0 \\
0 & \sqrt{\frac{r_{3}}{r_{2}}}\cosh\left( \sqrt{r_{2}r_{3}}\cos\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right) & e^{i\left( \frac{\theta_{2}}{2} - \frac{\theta_{3}}{2} \right)}\left( \sinh\left( \sqrt{r_{2}r_{3}}\cos\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right) \right) \\
0 & e^{i\left( \frac{\theta_{3}}{2} - \frac{\theta_{2}}{2} \right)}\left( \sinh\left( \sqrt{r_{2}r_{3}}\cos\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right) \right) & \sqrt{\frac{r_{2}}{r_{3}}}\cosh\left( \sqrt{r_{2}r_{3}}\cos\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right) \right)
\end{pmatrix},
\end{array} (1.6.267)
whose matrix product is equal to G ( θ r j 3 , X 1 ) G\left( \theta_{r_{j}}^{3,X_{1}} \right)
G ( θ r j [ D 3 𝕫 ( X 1 ) ] ) = G ( θ r j [ D 3 𝕫 ( I m X 1 ) ] ) × G ( θ r j [ D 3 𝕫 ( R e X 1 ) ] ) . \begin{array}{r}
G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( {\ X}_{1} \right) \right\rbrack} \right) = G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( {Im\ X}_{1} \right) \right\rbrack} \right) \times G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( {Re\ X}_{1} \right) \right\rbrack} \right).
\end{array} (1.6.268)
When the angle variables are equal, θ 2 = θ 3 = θ \theta_{2} = \theta_{3} = \theta , the matrix groups are assured to fall into the distinct imaginary and real valued forms of the complex sphere and the hyperbola
G ( θ r j [ D 3 𝕫 ( I m ( X 1 ) ) ] ) = ( e i b 1 0 0 0 r 2 r 3 cos ( r 2 r 3 sin ( θ ) ) i s i n ( r 2 r 3 sin ( θ ) ) 0 i s i n ( r 2 r 3 sin ( θ ) ) r 3 r 2 cos ( r 2 r 3 sin ( θ ) ) ) , \begin{array}{r}
G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( {Im\ (X}_{1}) \right) \right\rbrack} \right) = \begin{pmatrix}
e^{ib_{1}} & 0 & 0 \\
0 & \sqrt{\frac{r_{2}}{r_{3}}}\cos\left( \sqrt{r_{2}r_{3}}\sin(\theta) \right) & isin\left( \sqrt{r_{2}r_{3}}\sin(\theta) \right) \\
0 & isin\left( \sqrt{r_{2}r_{3}}\sin(\theta) \right) & {\sqrt{\frac{r_{3}}{r_{2}}}\cos}\left( \sqrt{r_{2}r_{3}}\sin(\theta) \right)
\end{pmatrix},
\end{array} (1.6.269)
G ( θ r j [ D 3 𝕫 ( R e ( X 1 ) ) ] ) = ( e a 1 0 0 0 r 3 r 2 cosh ( r 2 r 3 cos ( θ ) ) ( sinh ( r 2 r 3 cos ( θ ) ) ) 0 ( sinh ( r 2 r 3 cos ( θ ) ) ) r 2 r 3 cosh ( r 2 r 3 cos ( θ ) ) ) . \begin{array}{r}
G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( {Re\ (X}_{1}) \right) \right\rbrack} \right) = \begin{pmatrix}
e^{a_{1}} & 0 & 0 \\
0 & \sqrt{\frac{r_{3}}{r_{2}}}\cosh\left( \sqrt{r_{2}r_{3}}\cos(\theta) \right) & \left( \sinh\left( \sqrt{r_{2}r_{3}}\cos(\theta) \right) \right) \\
0 & \left( \sinh\left( \sqrt{r_{2}r_{3}}\cos(\theta) \right) \right) & \sqrt{\frac{r_{2}}{r_{3}}}\cosh\left( \sqrt{r_{2}r_{3}}\cos(\theta) \right)
\end{pmatrix}.
\end{array} (1.6.270)
In these forms, the c o s , c o s h cos,\ cosh entries are on the main diagonals of the matrix groups, while the s i n , s i n h sin,sinh functions locate on the off diagonals of the bottom-right 2 × 2 2 \times 2 submatrices.
We return to G ( θ r j [ D 3 𝕫 ( X 1 ) ] ) G\left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( {\ X}_{1} \right) \right\rbrack} \right) , setting, r j = 1 r_{j} = 1 , a 1 = 0 a_{1} = 0 , and for z 1 = ( a 1 + i b ) , z_{1} = \left( a_{1} + ib \right), the group becomes
G ( θ 1 [ D 3 𝕫 ( I m ( X 1 ) ) ] ) = ( e e i θ 1 0 0 0 cosh ( e i ( θ 2 + θ 3 ) 2 ) ( e i ( θ 2 2 − θ 3 2 ) ) sinh ( e i ( θ 2 2 + θ 3 2 ) ) 0 ( e i ( θ 3 2 − θ 2 2 ) ) sinh ( e i ( θ 2 2 + θ 3 2 ) ) cosh ( e i ( θ 2 + θ 3 ) 2 ) ) , \begin{array}{r}
G\left( \theta_{1}^{\left\lbrack D_{3\mathbb{z}}\left( {\ Im\ (X}_{1}) \right) \right\rbrack} \right) = \begin{pmatrix}
e^{e^{i\theta_{1}}} & 0 & 0 \\
0 & \cosh\left( e^{\frac{i\left( \theta_{2} + \theta_{3} \right)}{2}} \right) & \left( e^{i\left( \frac{\theta_{2}}{2}\ - \ \frac{\theta_{3}}{2} \right)} \right)\sinh\left( e^{i\left( \frac{\theta_{2}}{2}\ + \ \frac{\theta_{3}}{2} \right)} \right) \\
0 & \left( e^{i\left( \frac{\theta_{3}}{2}\ - \ \frac{\theta_{2}}{2} \right)} \right)\sinh\left( e^{i\left( \frac{\theta_{2}}{2}\ + \ \frac{\theta_{3}}{2} \right)} \right) & \cosh\left( e^{\frac{i\left( \theta_{2} + \theta_{3} \right)}{2}} \right)
\end{pmatrix},
\end{array} (1.6.271)
and plot each function type in the rotator submatrix in Figure 1.6.26 , to better visualize their waveforms.
Figure 1.6.26 – The waveforms of the functions cos ( sin ( θ ) ) \cos\left( \sin(\theta) \right) , blue, and i s i n ( sin ( θ ) ) {isin}\left( \sin(\theta) \right) , red.
The plotted waveforms above reveal the real-valued function, cos ( sin ( θ ) ) \cos\left( \sin(\theta) \right) , oscillates between troughs for θ \theta values
cos ( sin ( π 2 + 2 π k ) ) ≈ 0.5043 , \begin{array}{r}
\cos{\left( \sin\left( \frac{\pi}{2} + 2\pi k \right) \right) \approx 0.5043},
\end{array} (1.6.272)
and peaks
cos ( sin ( 2 π k ) ) = 1 , \begin{array}{r}
\cos\left( \sin(2\pi k) \right) = 1,
\end{array} (1.6.273)
for k ∈ ℤ + k \in \mathbb{Z}^{+} . The function i s i n ( sin ( θ ) ) {isin}\left( \sin(\theta) \right) , oscillates in the plane between troughs for θ \theta values
i s i n ( sin ( 3 π 2 + 2 π k ) ) ≈ − 0.8415 , \begin{array}{r}
{isin}\left( \sin\left( \frac{3\pi}{2} + 2\pi k \right) \right) \approx - 0.8415,
\end{array} (1.6.274)
and peaks
i s i n ( sin ( π 2 + 2 π k ) ) ≈ 0.8415. \begin{array}{r}
{isin}\left( \sin\left( \frac{\pi}{2} + 2\pi k \right) \right) \approx 0.8415.
\end{array} (1.6.275)
Noteworthy in the plots, the waveform frequency for cos ( sin ( θ ) ) \cos\left( \sin(\theta) \right) dictates two peaks on each interval, θ = ( 0,2 π ] \theta = (0,2\pi\rbrack , while the i s i n ( sin ( θ ) ) {isin}\left( \sin(\theta) \right) waveform's frequency is half of that, evidenced by its one peak on the same interval θ = ( 0,2 π ] \theta = (0,2\pi\rbrack .
Figure 1.6.27 – Waveforms of the cosh ( cos ( θ ) ) \cosh\left( \cos(\theta) \right) and sinh ( cos ( θ ) ) \sinh\left( \cos(\theta) \right) functions.
For the case of the hyperbolic group form plot, Figure 1.6.27 , we can see the real-valued function cosh ( cos ( θ ) ) , \cosh\left( \cos(\theta) \right), oscillates between troughs values of 1 1 , for θ \theta , equal to
cosh ( cos ( π 2 + π k ) ) = 1 , ( k ∈ ℤ + ) , \begin{array}{r}
\cosh\left( \cos\left( \frac{\pi}{2} + \pi k \right) \right) = 1,\ \ \ \left( k \in \mathbb{Z}^{+} \right),
\end{array} (1.6.276)
and peaks for arguments equal to cos ( θ ) = ± 1 \cos{(\theta) = \pm 1}
cosh ( cos ( π k ) ) ≈ 1.5431 , ( k ∈ ℤ + ) , \begin{array}{r}
\cosh\left( \cos(\pi k) \right) \approx 1.5431,\ \ \ \left( k \in \mathbb{Z}^{+} \right),
\end{array} (1.6.277)
The function sinh ( cos ( θ ) ) \sinh\left( \cos(\theta) \right) , also oscillates at half the frequency of the cosh ( cos ( θ ) ) \cosh\left( \cos(\theta) \right) function, with troughs occurring at θ \theta values
sinh ( cos ( π + 2 π k ) ) ≈ − 1.1752 , ( k ∈ ℤ + ) \begin{array}{r}
\sinh\left( \cos(\pi + 2\pi k) \right) \approx - 1.1752,\ \ \ \left( k \in \mathbb{Z}^{+} \right)
\end{array} (1.6.278)
and peaks
sinh ( cos ( 2 π k ) ) ≈ 1.1752 , ( k ∈ ℤ + ) . \begin{array}{r}
\sinh\left( \cos(2\pi k) \right) \approx 1.1752,\ \ \ \left( k \in \mathbb{Z}^{+} \right).
\end{array} (1.6.279)
When considering the mathematical unit singularity, with an ontological unit radial distance from its center to its boundary, we find the complex circular functions cos ( sin ( θ ) ) \cos\left( \sin(\theta) \right) , i s i n ( sin ( θ ) ) {isin}\left( \sin(\theta) \right) have waveforms beneath the boundary's surface in complex space. For the hyperbolic function forms, we find that the function cosh ( cos ( θ ) ) \cosh\left( \cos(\theta) \right) lays entirely above the boundary, except for just touching its surface at its troughs, while the majority of the sinh ( cos ( θ ) ) \sinh\left( \cos(\theta) \right) function's waveform is inside the boundary, except in the neighborhood of the caps of its peaks and troughs, respectively, starting at c o s − 1 ( sinh − 1 ( 1 ) ) {cos^{- 1}}\left( \sinh^{- 1}(1) \right) and c o s − 1 ( sinh − 1 ( − 1 ) ) {cos^{- 1}}\left( \sinh^{- 1}( - 1) \right) .
Our treatment of the Lie algebra θ r j [ D 3 𝕫 ( X 1 ) ] \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} , which lays on the singularity's boundary, has not yet included a variable for its exponential mapping form. To remedy this, we define the variable t j ∈ ℝ t_{j}\in \mathbb{R} , and the Lie algebra t j θ r j [ D 3 𝕫 ( X 1 ) ] t_{j}\theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} , as
t j θ r j [ D 3 𝕫 ( X 1 ) ] = ( t 1 r 1 e i θ 1 0 0 0 0 t 2 r 2 e i θ 2 0 t 3 r 3 e i θ 3 0 ) , \begin{array}{r}
t_{j}\theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} = \begin{pmatrix}
t_{1}r_{1}e^{i\theta_{1}} & 0 & 0 \\
0 & 0 & {t_{2}r}_{2}e^{i\theta_{2}} \\
0 & {t_{3}r}_{3}e^{i\theta_{3}} & 0
\end{pmatrix},
\end{array} (1.6.280)
with the complex form t j Z j [ D 3 𝕫 ( X 1 ) ] t_{j}Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack}
t j Z j [ D 3 𝕫 ( X 1 ) ] = ( t 1 z 1 0 0 0 0 t 2 z 2 0 t 3 z 3 0 ) , \begin{array}{r}
t_{j}Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} = \begin{pmatrix}
t_{1}z_{1} & 0 & 0 \\
0 & 0 & t_{2}z_{2} \\
0 & t_{3}z_{3} & 0
\end{pmatrix},
\end{array} (1.6.281)
and the matrix exponential mapping transforms these Lie algebras to the forms
G ( t j θ r j [ D 3 𝕫 ( X 1 ) ] ) = ( e r 1 e i θ 1 0 0 0 cosh ( t 2 r 2 t 3 r 3 e i ( θ 2 + θ 3 ) 2 ) t 2 r 2 t 3 r 3 ( e i ( θ 2 2 − θ 3 2 ) ) sinh ( t 2 r 2 t 3 r 3 e i ( θ 2 2 + θ 3 2 ) ) 0 t 3 r 3 t 2 r 2 ( e i ( θ 3 2 − θ 2 2 ) ) sinh ( r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) cosh ( t 2 r 2 t 3 r 3 e i ( θ 2 + θ 3 ) 2 ) ) , \begin{array}{r}
G\left( t_{j}\theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = \begin{pmatrix}
e^{r_{1}e^{i\theta_{1}}} & 0 & 0 \\
0 & \cosh\left( \sqrt{t_{2}r_{2}{t_{3}r}_{3}}e^{\frac{i\left( \theta_{2} + \theta_{3} \right)}{2}} \right) & \sqrt{\frac{{t_{2}r}_{2}}{t_{3}r_{3}}}\left( e^{i\left( \frac{\theta_{2}}{2} - \frac{\theta_{3}}{2} \right)} \right)\sinh\left( \sqrt{t_{2}r_{2}{t_{3}r}_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) \\
0 & \sqrt{\frac{{t_{3}r}_{3}}{t_{2}r_{2}}}\left( e^{i\left( \frac{\theta_{3}}{2} - \frac{\theta_{2}}{2} \right)} \right)\sinh\left( \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) & \cosh\left( \sqrt{t_{2}r_{2}{t_{3}r}_{3}}e^{\frac{i\left( \theta_{2} + \theta_{3} \right)}{2}} \right)
\end{pmatrix},
\end{array} (1.6.282)
G ( t j Z j [ D 3 𝕫 ( X 1 ) ] ) = ( e t 1 z 1 0 0 0 cosh ( t 2 t 3 z 2 z 3 ) t 2 z 2 t 2 t 3 z 2 z 3 sinh ( t 2 t 3 z 2 z 3 ) 0 t 3 z 3 t 2 t 3 z 2 z 3 sinh ( t 2 t 3 z 2 z 3 ) cosh ( t 2 t 3 z 2 z 3 ) ) . \begin{array}{r}
G\left( t_{j}Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = \begin{pmatrix}
e^{t_{1}z_{1}} & 0 & 0 \\
0 & \cosh\left( \sqrt{t_{2}t_{3}z_{2}z_{3}} \right) & \frac{t_{2}z_{2}}{\sqrt{t_{2}t_{3}z_{2}z_{3}}}\sinh\left( \sqrt{t_{2}t_{3}z_{2}z_{3}} \right) \\
0 & \frac{t_{3}z_{3}}{\sqrt{t_{2}t_{3}z_{2}z_{3}}}\sinh\left( \sqrt{t_{2}t_{3}z_{2}z_{3}} \right) & \cosh\left( \sqrt{t_{2}t_{3}z_{2}z_{3}} \right)
\end{pmatrix}.
\end{array} (1.6.283)
The two variables in the matrix groups above should be viewed as the means for which the subtangent space ( ln ( θ r [ m ] ) ) \left( \ln\left( \theta_{r}^{\lbrack m\rbrack} \right) \right) interacts with the sphere of tangent spaces ( t θ r [ m ] ) \left( t\theta_{r}^{\lbrack m\rbrack} \right) , and in turn, shows how the sphere of tangent spaces interacts with the exponentially extended group spaces ( G ( t θ r [ m ] ) ) \left( G\left( t\theta_{r}^{\lbrack m\rbrack} \right) \right) . To better understand the reasoning behind this assertion, we return to the subtangent space example ln ( Z j [ D 3 𝕫 ( X 1 ) ] ) \ln\left( Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right)
ln ( Z j [ D 3 𝕫 ( X 1 ) ] ) = ( ln ( z 1 ) 0 0 0 ln ( z 2 z 3 ) + ln ( − z 2 z 3 ) 2 z 2 z 2 z 3 ( ln ( z 2 z 3 ) − ln ( − z 2 z 3 ) 2 ) 0 z 3 z 2 z 3 ( ln ( z 2 z 3 ) − ln ( − z 2 z 3 ) 2 ) ( ln ( z 2 z 3 ) + ln ( − z 2 z 3 ) ) 2 ) , \begin{array}{r}
\ln{\left( Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = \begin{pmatrix}
\ln\left( z_{1} \right) & 0 & 0 \\
0 & \frac{\ln{\left( \sqrt{z_{2}z_{3}} \right) + \ln\left( - \sqrt{z_{2}z_{3}} \right)}}{2} & \frac{z_{2}}{\sqrt{z_{2}z_{3}}}\left( \frac{\ln{\left( \sqrt{z_{2}z_{3}} \right) - \ln\left( - \sqrt{z_{2}z_{3}} \right)}}{2} \right) \\
0 & \frac{z_{3}}{\sqrt{z_{2}z_{3}}}\left( \frac{\ln{\left( \sqrt{z_{2}z_{3}} \right) - \ln\left( - \sqrt{z_{2}z_{3}} \right)}}{2} \right) & \frac{\left( \ln{\left( \sqrt{z_{2}z_{3}} \right) + \ln\left( - \sqrt{z_{2}z_{3}} \right)} \right)}{2}
\end{pmatrix}},
\end{array} (1.6.284)
which using polar form variables, is
( ln ( r 1 e i θ 1 ) 0 0 0 ln ( r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) + ln ( − r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) 2 r 2 e i ( θ 2 2 − θ 3 2 ) r 2 r 3 ( ln ( r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) − ln ( − r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) 2 ) 0 r 3 e i ( θ 3 2 − θ 2 2 ) r 2 r 3 ( ln ( r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) − ln ( − r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) 2 ) ln ( r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) + ln ( − r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) 2 ) . \begin{array}{r}
\begin{pmatrix}
\ln\left( r_{1}e^{i\theta_{1}} \right) & 0 & 0 \\
0 & \frac{\ln{\left( \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) + \ln\left( - \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right)}}{2} & \frac{r_{2}e^{i\left( \frac{\theta_{2}}{2} - \frac{\theta_{3}}{2} \right)}}{\sqrt{r_{2}r_{3}}}\left( \frac{\ln{\left( \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) - \ln\left( - \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right)}}{2} \right) \\
0 & \frac{r_{3}e^{i\left( \frac{\theta_{3}}{2} - \frac{\theta_{2}}{2} \right)}}{\sqrt{r_{2}r_{3}}}\left( \frac{\ln{\left( \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) - \ln\left( - \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right)}}{2} \right) & \frac{\ln{\left( \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) + \ln\left( - \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right)}}{2}
\end{pmatrix}.
\end{array} (1.6.285)
Evaluating the logarithm for each entry, the subtangent space is equivalent to
ln ( Z j [ D 3 𝕫 ( X 1 ) ] ) = ( ln ( r 1 ) + i θ 1 0 0 0 ln ( r 2 r 3 ) + i ( θ 2 + θ 3 ) + i π 2 r 2 r 3 ( e i ( θ 2 2 − θ 3 2 ) ) ( i π 2 ) 0 r 3 r 2 ( e i ( θ 3 2 − θ 2 2 ) ) ( i π 2 ) ln ( r 2 r 3 ) + i ( θ 2 + θ 3 ) + i π 2 ) , \begin{array}{r}
\ln\left( Z_{j}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = \begin{pmatrix}
\ln\left( r_{1} \right) + i\theta_{1} & 0 & 0 \\
0 & \frac{\ln{\left( r_{2}r_{3} \right) + i\left( \theta_{2} + \theta_{3} \right) + i\pi}}{2} & \sqrt{\frac{r_{2}}{r_{3}}}\left( e^{i\left( \frac{\theta_{2}}{2} - \frac{\theta_{3}}{2} \right)} \right)\left( \frac{i\pi}{2} \right) \\
0 & \sqrt{\frac{r_{3}}{r_{2}}}\left( e^{i\left( \frac{\theta_{3}}{2} - \frac{\theta_{2}}{2} \right)} \right)\left( \frac{i\pi}{2} \right) & \frac{\ln{\left( r_{2}r_{3} \right) + i\left( \theta_{2} + \theta_{3} \right) + i\pi}}{2}
\end{pmatrix},
\end{array} (1.6.286)
a result, with complex matrix entries, expressed in their real and imaginary portions as follows
𝓏 1 = ( 𝒶 1 + i 𝒷 1 ) = ( ln ( r 1 ) + i θ 1 ) , \begin{array}{r}
\mathcal{z}_{1} = \left( \mathcal{a}_{1} + i\mathcal{b}_{1} \right) = \left( \ln\left( r_{1} \right) + i\theta_{1} \right),
\end{array} (1.6.287)
𝓏 2 = ( 𝒶 2 + i 𝒷 2 ) = ( ( i π 2 × r 2 r 3 ) cos ( θ 2 − θ 3 2 ) + i ( i π 2 × r 2 r 3 ) sin ( θ 2 − θ 3 2 ) ) \mathcal{z}_{2} = \left( \mathcal{a}_{2} + i\mathcal{b}_{2} \right) = \left( \left( \frac{i\pi}{2} \times \sqrt{\frac{r_{2}}{r_{3}}} \right)\cos\left( \frac{\theta_{2} - \theta_{3}}{2} \right) + i\left( \frac{i\pi}{2} \times \sqrt{\frac{r_{2}}{r_{3}}} \right)\sin\left( \frac{\theta_{2} - \theta_{3}}{2} \right) \right)
= ( ( π 2 × r 2 r 3 ) cos ( θ 2 − θ 3 + π 2 ) + i ( π 2 × r 2 r 3 ) sin ( θ 2 − θ 3 + π 2 ) ) , \begin{array}{r}
= \left( \left( \frac{\pi}{2} \times \sqrt{\frac{r_{2}}{r_{3}}} \right)\cos\left( \frac{\theta_{2} - \theta_{3} + \pi}{2} \right) + i\left( \frac{\pi}{2} \times \sqrt{\frac{r_{2}}{r_{3}}} \right)\sin\left( \frac{\theta_{2} - \theta_{3} + \pi}{2} \right) \right),
\end{array} (1.6.288)
𝓏 3 = ( 𝒶 3 + i 𝒷 3 ) = ( ( i π 2 × r 3 r 2 ) cos ( θ 3 − θ 2 2 ) + i ( i π 2 × r 3 r 2 ) sin ( θ 3 − θ 2 2 ) ) \mathcal{z}_{3} = \left( \mathcal{a}_{3} + i\mathcal{b}_{3} \right) = \left( \left( \frac{i\pi}{2} \times \sqrt{\frac{r_{3}}{r_{2}}} \right)\cos\left( \frac{\theta_{3} - \theta_{2}}{2} \right) + i\left( \frac{i\pi}{2} \times \sqrt{\frac{r_{3}}{r_{2}}} \right)\sin\left( \frac{\theta_{3} - \theta_{2}}{2} \right) \right)
= ( ( π 2 × r 3 r 2 ) cos ( θ 3 − θ 2 + π 2 ) + i ( π 2 × r 3 r 2 ) sin ( θ 3 − θ 2 + π 2 ) ) , \begin{array}{r}
= \left( \left( \frac{\pi}{2} \times \sqrt{\frac{r_{3}}{r_{2}}} \right)\cos\left( \frac{\theta_{3} - \theta_{2} + \pi}{2} \right) + i\left( \frac{\pi}{2} \times \sqrt{\frac{r_{3}}{r_{2}}} \right)\sin\left( \frac{\theta_{3} - \theta_{2} + \pi}{2} \right) \right),
\end{array} (1.6.289)
and in conjunction, the two lower entries of the main diagonal
𝓏 d = 𝓏 d = ( 𝒶 d + i 𝒷 d ) = ( ln ( r 2 r 3 ) 2 + i ( θ 2 + θ 3 + π 2 ) ) . \begin{array}{r}
\mathcal{z}_{d} = \mathcal{z}_{d} = \left( \mathcal{a}_{d} + i\mathcal{b}_{d} \right) = \left( \frac{\ln\left( r_{2}r_{3} \right)}{2} + i\left( \frac{\theta_{2} + \theta_{3} + \pi}{2} \right) \right).
\end{array} (1.6.290)
With these functions in the 𝓏 j \mathcal{z}_{j} form, it enables the expression of the subtangent space ln ( ( X 1 ( z j ) ) ) \ln\left( \left( X_{1}\left( z_{j} \right) \right) \right) , in its polar form
( 𝓇 1 e i Θ 1 0 0 0 𝓇 d e i Θ d 𝓇 2 e i Θ 2 0 𝓇 3 e i Θ 3 𝓇 d e i Θ d ) , \begin{array}{r}
\begin{pmatrix}
\mathcal{r}_{1}e^{i\Theta_{1}} & 0 & 0 \\
0 & \mathcal{r}_{d}e^{i\Theta_{d}} & \mathcal{r}_{2}e^{i\Theta_{2}} \\
0 & \mathcal{r}_{3}e^{i\Theta_{3}} & \mathcal{r}_{d}e^{i\Theta_{d}}
\end{pmatrix},
\end{array} (1.6.291)
where each entry represents the following
𝓇 1 e i Θ 1 = 𝓏 1 = ln 2 ( r 1 ) + θ 1 2 × e i t a n − 1 ( θ 1 ln ( r 1 ) ) , \begin{array}{r}
\mathcal{r}_{1}e^{i\Theta_{1}} = \mathcal{z}_{1} = \sqrt{\ln^{2}{\left( r_{1} \right) + \theta_{1}^{2}}} \times e^{itan^{- 1}\left( \frac{\theta_{1}}{\ln\left( r_{1} \right)} \right)},
\end{array} (1.6.292)
𝓇 2 e i Θ 2 = 𝓏 2 = π 2 r 2 r 3 × e i t a n − 1 ( cot ( θ 2 − θ 3 2 ) ) , \begin{array}{r}
\mathcal{r}_{2}e^{i\Theta_{2}} = \mathcal{z}_{2} = \frac{\pi}{2}\sqrt{\frac{r_{2}}{r_{3}}} \times e^{itan^{- 1}\left( \cot\left( \frac{\theta_{2} - \theta_{3}}{2} \right) \right)},
\end{array} (1.6.293)
𝓇 3 e i Θ 3 = 𝓏 3 = π 2 r 3 r 2 × e i t a n − 1 ( cot ( θ 3 − θ 2 2 ) ) , \begin{array}{r}
\mathcal{r}_{3}e^{i\Theta_{3}} = \mathcal{z}_{3} = \frac{\pi}{2}\sqrt{\frac{r_{3}}{r_{2}}} \times e^{itan^{- 1}\left( \cot\left( \frac{\theta_{3} - \theta_{2}}{2} \right) \right)},
\end{array} (1.6.294)
𝓇 d e i Θ d = 𝓏 d = ln 2 ( r 2 r 3 ) 4 + ( θ 2 + θ 3 + π ) 2 4 × e i t a n − 1 ( θ 2 + θ 3 + π ln ( r 2 r 3 ) ) , \begin{array}{r}
\mathcal{r}_{d}e^{i\Theta_{d}} = \mathcal{z}_{d} = \sqrt{\frac{\ln^{2}\left( r_{2}r_{3} \right)}{4} + \frac{\left( \theta_{2} + \theta_{3} + \pi \right)^{2}}{4}} \times e^{itan^{- 1}\left( \frac{\theta_{2} + \theta_{3} + \pi}{\ln\left( r_{2}r_{3} \right)} \right)},
\end{array} (1.6.295)
for 𝓇 j \mathcal{r}_{j} , the radial moduli, Θ j \Theta_{j} the angular space variables, and these are analogous to the variables r j r_{j} , θ j \theta_{j} . An exponentiated and extended space of the form e r e i θ e^{re^{i\theta}} , therefore, has the r r -variable used in the typical physics treatments of Lie theory, where rotations and or boosts can be performed in the space, but the θ \theta -variable represents the angle space, and the geometry of the space hinges on its given value. The movement in the angle space related to θ \theta , occurs on the sphere of tangent spaces, and this represents a crucial concept. To help ensure the reader grasps this intuition, we consider the matrix G ( t j θ r j 3 , X 1 ) G\left( t_{j}\theta_{r_{j}}^{3,X_{1}} \right) , as
( e t 1 r 1 e i θ 1 0 0 0 cosh ( t 2 r 2 t 3 r 3 e i ( θ 2 + θ 3 ) 2 ) t 2 r 2 t 3 r 3 ( e i ( θ 2 2 − θ 3 2 ) ) sinh ( t 2 r 2 t 3 r 3 e i ( θ 2 2 + θ 3 2 ) ) 0 t 3 r 3 t 2 r 2 ( e i ( θ 3 2 − θ 2 2 ) ) sinh ( r 2 r 3 e i ( θ 2 2 + θ 3 2 ) ) cosh ( t 2 r 2 t 3 r 3 e i ( θ 2 + θ 3 ) 2 ) ) , \begin{array}{r}
\begin{pmatrix}
e^{t_{1}r_{1}e^{i\theta_{1}}} & 0 & 0 \\
0 & \cosh\left( \sqrt{t_{2}r_{2}{t_{3}r}_{3}}e^{\frac{i\left( \theta_{2} + \theta_{3} \right)}{2}} \right) & \sqrt{\frac{{t_{2}r}_{2}}{t_{3}r_{3}}}\left( e^{i\left( \frac{\theta_{2}}{2} - \frac{\theta_{3}}{2} \right)} \right)\sinh\left( \sqrt{t_{2}r_{2}{t_{3}r}_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) \\
0 & \sqrt{\frac{{t_{3}r}_{3}}{t_{2}r_{2}}}\left( e^{i\left( \frac{\theta_{3}}{2} - \frac{\theta_{2}}{2} \right)} \right)\sinh\left( \sqrt{r_{2}r_{3}}e^{i\left( \frac{\theta_{2}}{2} + \frac{\theta_{3}}{2} \right)} \right) & \cosh\left( \sqrt{t_{2}r_{2}{t_{3}r}_{3}}e^{\frac{i\left( \theta_{2} + \theta_{3} \right)}{2}} \right)
\end{pmatrix},
\end{array} (1.6.296)
and consider this group for all r j = 1 , r_{j} = 1, and all θ j = π 2 \theta_{j} = \frac{\pi}{2} , finding that G ( t j θ ( π 2 ) 1 [ D 3 𝕫 ( X 1 ) ] ) G\left( t_{j}{\theta\left( \frac{\pi}{2} \right)}_{1}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) , becomes
G ( t j θ ( π 2 ) 1 [ D 3 𝕫 ( X 1 ) ] ) = ( e t 1 e i π 2 0 0 0 cosh ( t 2 t 3 e i π 2 ) t 2 t 3 sinh ( t 2 t 3 e i π 2 ) 0 t 3 t 2 sinh ( t 2 t 3 e i π 2 ) cosh ( t 2 t 3 e i π 2 ) ) . \begin{array}{r}
G\left( t_{j}{\theta\left( \frac{\pi}{2} \right)}_{1}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = \begin{pmatrix}
e^{t_{1}e^{\frac{i\pi}{2}}} & 0 & 0 \\
0 & \cosh\left( \sqrt{t_{2}t_{3}}e^{\frac{i\pi}{2}} \right) & \sqrt{\frac{t_{2}}{t_{3}}}\sinh\left( \sqrt{t_{2}t_{3}}e^{\frac{i\pi}{2}} \right) \\
0 & \sqrt{\frac{t_{3}}{t_{2}}}\sinh\left( \sqrt{t_{2}t_{3}}e^{\frac{i\pi}{2}} \right) & \cosh\left( \sqrt{t_{2}t_{3}}e^{\frac{i\pi}{2}} \right)
\end{pmatrix}.
\end{array} (1.6.297)
The example for the chosen variables, results in a e ( i π 2 ) \ e^{\left( \frac{i\pi}{2} \right)} rotation of the group in tangent space, to the equivalent matrix result
G ( t j θ ( π 2 ) 1 [ D 3 𝕫 ( X 1 ) ] ) = ( e i t 1 0 0 0 cosh ( i t 2 t 3 ) t 2 t 3 sinh ( i t 2 t 3 ) 0 t 3 t 2 sinh ( i t 2 t 3 ) cosh ( i t 2 t 3 ) ) , \begin{array}{r}
G\left( t_{j}{\theta\left( \frac{\pi}{2} \right)}_{1}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = \begin{pmatrix}
e^{it_{1}} & 0 & 0 \\
0 & \cosh\left( i\sqrt{t_{2}t_{3}} \right) & \sqrt{\frac{t_{2}}{t_{3}}}\sinh\left( i\sqrt{t_{2}t_{3}} \right) \\
0 & \sqrt{\frac{t_{3}}{t_{2}}}\sinh\left( i\sqrt{t_{2}t_{3}} \right) & \cosh\left( i\sqrt{t_{2}t_{3}} \right)
\end{pmatrix},
\end{array} (1.6.298)
and given the identities, sinh ( i θ ) = i s i n ( θ ) , cosh ( i θ ) = cos ( θ ) , \sinh{(i\theta) = isin(\theta),}\cosh{(i\theta) = \cos(\theta),} we find G ( t j θ ( π 2 ) 1 [ D 3 𝕫 ( X 1 ) ] ) G\left( t_{j}{\theta\left( \frac{\pi}{2} \right)}_{1}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) equals
G ( t j θ ( π 2 ) 1 [ D 3 𝕫 ( X 1 ) ] ) = ( e i t 1 0 0 0 cos ( t 2 t 3 ) t 2 t 3 × i s i n ( t 2 t 3 ) 0 t 3 t 2 × i s i n ( t 2 t 3 ) cos ( t 2 t 3 ) ) . \begin{array}{r}
G\left( t_{j}{\theta\left( \frac{\pi}{2} \right)}_{1}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = \begin{pmatrix}
e^{it_{1}} & 0 & 0 \\
0 & \cos\left( \sqrt{t_{2}t_{3}} \right) & \sqrt{\frac{t_{2}}{t_{3}}}{\times isin}\left( \sqrt{t_{2}t_{3}} \right) \\
0 & \sqrt{\frac{t_{3}}{t_{2}}}{\times isin}\left( \sqrt{t_{2}t_{3}} \right) & \cos\left( \sqrt{t_{2}t_{3}} \right)
\end{pmatrix}.
\end{array} (1.6.299)
By assuming the t j t_{j} variables are all equal, we find G ( t θ ( π 2 ) 1 [ D 3 𝕫 ( X 1 ) ] ) G\left( t{\theta\left( \frac{\pi}{2} \right)}_{1}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) equals the familiar U ( 3 ) U(3) group generator, G ( i X 1 ) G\left( iX_{1} \right) ,
G ( t θ ( π 2 ) 1 [ D 3 𝕫 ( X 1 ) ] ) = G ( i X 1 ) = ( e i t 0 0 0 cos ( t ) i s i n ( t ) 0 i s i n ( t ) cos ( t ) ) . \begin{array}{r}
G\left( t{\theta\left( \frac{\pi}{2} \right)}_{1}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right) = G\left( iX_{1} \right) = \begin{pmatrix}
e^{it} & 0 & 0 \\
0 & \cos(t) & {isin}(t) \\
0 & {isin}(t) & \cos(t)
\end{pmatrix}.
\end{array} (1.6.300)
Angle space rotations that occur on the singularity's boundary can be represented in multiple ways, shown first, by using the X 1 X_{1} -type matrix
θ r j [ D 3 𝕫 ( X 1 ) ] × ( θ r j [ D 3 𝕫 ( X 1 ) ] ) T × X 1 = ( 2 θ ) r 2 [ D 3 𝕫 ( X 1 ) ] \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \times \left( \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} \right)^{T} \times X_{1} = (2\theta)_{r^{2}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack}
= ( r 1 e i θ 1 0 0 0 0 r 2 e i θ 2 0 r 3 e i θ 3 0 ) ( r 1 e i θ 1 0 0 0 0 r 3 e i θ 3 0 r 2 e i θ 2 0 ) ( 1 0 0 0 0 1 0 1 0 ) = ( r 1 2 e i 2 θ 1 0 0 0 0 r 2 2 e i 2 θ 2 0 r 3 2 e i 2 θ 3 0 ) , \begin{array}{r}
= \begin{pmatrix}
r_{1}e^{i\theta_{1}} & 0 & 0 \\
0 & 0 & r_{2}e^{i\theta_{2}} \\
0 & r_{3}e^{i\theta_{3}} & 0
\end{pmatrix}\begin{pmatrix}
r_{1}e^{i\theta_{1}} & 0 & 0 \\
0 & 0 & r_{3}e^{i\theta_{3}} \\
0 & r_{2}e^{i\theta_{2}} & 0
\end{pmatrix}\begin{pmatrix}
1 & 0 & 0 \\
0 & 0 & 1 \\
0 & 1 & 0
\end{pmatrix} = \begin{pmatrix}
r_{1}^{2}e^{i{2\theta}_{1}} & 0 & 0 \\
0 & 0 & r_{2}^{2}e^{i{2\theta}_{2}} \\
0 & r_{3}^{2}e^{i2\theta_{3}} & 0
\end{pmatrix},
\end{array} (1.6.301)
which serves to rotate each polar variable in the Lie algebra θ r j [ D 3 𝕫 ( X 1 ) ] \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} . The second example is more straightforward, where we diagonalize the vector v ˆ = ( e i ρ 1 , e i ρ 2 , e i ρ 3 ) \widehat{v} = \left( e^{i\rho_{1}},e^{i\rho_{2}},e^{i\rho_{3}} \right) , for ρ j ∈ ℝ \rho_{j}\in \mathbb{R} . The product of this vector with the Lie algebra θ r j [ D 3 𝕫 ( X 1 ) ] \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} , results in solely rotating in the angle space, with the radial moduli remaining unchanged, seen as
d i a g ( v ˆ ) × θ r j [ D 3 𝕫 ( X 1 ) ] = ( ρ + θ ) r j [ D 3 𝕫 ( X 1 ) ] diag\left( \widehat{v} \right) \times \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} = (\rho + \theta)_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack}
= ( e i ρ 1 0 0 0 e i ρ 2 0 0 0 e i ρ 3 ) ( r 1 e i θ 1 0 0 0 0 r 2 e i θ 2 0 r 3 e i θ 3 0 ) = ( r 1 e i ( θ 1 + ρ 1 ) 0 0 0 0 r 2 e i ( θ 2 + ρ 2 ) 0 r 3 e i ( θ 3 + ρ 3 ) 0 ) . \begin{array}{r}
= \begin{pmatrix}
e^{i\rho_{1}} & 0 & 0 \\
0 & e^{i\rho_{2}} & 0 \\
0 & 0 & e^{i\rho_{3}}
\end{pmatrix}\begin{pmatrix}
r_{1}e^{i\theta_{1}} & 0 & 0 \\
0 & 0 & r_{2}e^{i\theta_{2}} \\
0 & r_{3}e^{i\theta_{3}} & 0
\end{pmatrix} = \begin{pmatrix}
r_{1}e^{i\left( \theta_{1} + \rho_{1} \right)} & 0 & 0 \\
0 & 0 & r_{2}e^{i\left( \theta_{2} + \rho_{2} \right)} \\
0 & r_{3}e^{i\left( \theta_{3} + \rho_{3} \right)} & 0
\end{pmatrix}.
\end{array} (1.6.302)
To gain further intuition on how a rotation in the angle space affects geometry, we set θ j = π 2 , r j = r , \theta_{j} = \frac{\pi}{2},\ r_{j} = r, and define a vector, v ˆ = ( e ( − i π 2 ) , e ( − i π 2 ) , e ( − i π 2 ) ) , \widehat{v} = \left( e^{\left( - \frac{i\pi}{2} \right)},e^{\left( - \frac{i\pi}{2} \right)},e^{\left( - \frac{i\pi}{2} \right)} \right), to evaluate
d i a g ( v ˆ ) × θ r [ i × | D 3 𝕫 ( X 1 ) | ] = ( − π 2 + π 2 ) r [ D 3 𝕫 ( X 1 ) ] = θ r [ | D 3 𝕫 ( X 1 ) | ] diag\left( \widehat{v} \right) \times \theta_{r}^{\left\lbrack {i \times |D}_{3\mathbb{z}}\left( X_{1} \right)| \right\rbrack} = \left( - \frac{\pi}{2} + \frac{\pi}{2} \right)_{r}^{\left\lbrack D_{3\mathbb{z}}\left( X_{1} \right) \right\rbrack} = \theta_{r}^{\left\lbrack {|D}_{3\mathbb{z}}\left( X_{1} \right)| \right\rbrack}
= ( e − i π 2 0 0 0 e − i π 2 0 0 0 e − i π 2 ) ( i r 0 0 0 0 i r 0 i r 0 ) = ( r 0 0 0 0 r 0 r 0 ) , \begin{array}{r}
= \begin{pmatrix}
e^{- \frac{i\pi}{2}} & 0 & 0 \\
0 & e^{- \frac{i\pi}{2}} & 0 \\
0 & 0 & e^{- \frac{i\pi}{2}}
\end{pmatrix}\begin{pmatrix}
ir & 0 & 0 \\
0 & 0 & ir \\
0 & ir & 0
\end{pmatrix} = \begin{pmatrix}
r & 0 & 0 \\
0 & 0 & r \\
0 & r & 0
\end{pmatrix},
\end{array} (1.6.303)
finding the rotation in the angle space has changed the geometry from the imaginary-valued X 1 X_{1} -type Lie algebra, i × | D 3 𝕫 | {i \times |D}_{3\mathbb{z}}| , to a real-valued X 1 X_{1} -type hyperbolic Lie algebra, | D 3 𝕫 | |D_{3\mathbb{z}}| .
The content of this chapter, and in particular this section, leads to the following definition of The Tangent Space Complex Symmetry Group .
Definition (1.6.304) – We define The Tangent Space Complex Symmetry Group 𝛉 𝐫 𝐣 [ 𝐃 𝟑 𝕫 ( 𝐗 𝐤 , 𝐘 𝐤 ) ] ∈ ℂ 3 \mathbf{\theta}_{\mathbf{r}_{\mathbf{j}}}^{\left\lbrack \mathbf{D}_{\mathbf{3}\mathbb{z}}\left( \mathbf{X}_{\mathbf{k}}\mathbf{,}\mathbf{Y}_{\mathbf{k}} \right) \right\rbrack} \in \mathbb{C}^{3} , as a group under composition, comprised of C ∞ C^{\infty} functions for its infinitesimal minimal element basis ∈ ℂ 3 , \in \mathbb{C}^{3}, yielding the infinite set θ r [ m ] ∞ {\theta_{r}^{\lbrack m\rbrack}}^{\infty} of unitary elements in tangent space, for r j r_{j} =1, and non-unit radial lengths r j ≠ 1 r_{j} \neq 1 , for the form extended or contracted in ℂ 3 \mathbb{C}^{3} -space from the unitary state
θ r j [ D 3 𝕫 ( X k , Y k ) ] = { θ r [ m ] ∞ ∈ G L ( 3 , ℂ ) | θ r [ m ] ∞ ∙ ( θ r [ m ] ∞ ) † = 𝓇 2 I } , \begin{array}{r}
\theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{k},Y_{k} \right) \right\rbrack}\ = \left\{ {\theta_{r}^{\lbrack m\rbrack}}^{\infty} \in GL\left( 3,\mathbb{C} \right)|{\theta_{r}^{\lbrack m\rbrack}}^{\infty} \bullet \left( {\theta_{r}^{\lbrack m\rbrack}}^{\infty} \right)^{\dagger} = \mathcal{r}^{2}I\ \right\},
\end{array}
containing element sets,
θ r j [ D 3 𝕫 ( X k ) ] = { ( r 1 e i θ ( 1,1 ) 0 0 0 0 r 2 e i θ ( 1,2 ) 0 r 3 e i θ ( 1,3 ) 0 ) , ( 0 0 r 1 e i θ ( 2,1 ) 0 r 2 e i θ ( 2,2 ) 0 r 3 e i θ ( 2,3 ) 0 0 ) , ( 0 r 1 e i θ ( 3,1 ) 0 r 2 e i θ ( 3,2 ) 0 0 0 0 r 3 e i θ ( 3,3 ) ) } , \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{k} \right) \right\rbrack} = \left\{ \begin{array}{r}
\begin{pmatrix}
r_{1}e^{i\theta_{(1,1)}} & 0 & 0 \\
0 & 0 & r_{2}e^{i\theta_{(1,2)}} \\
0 & r_{3}e^{i\theta_{(1,3)}} & 0
\end{pmatrix},\begin{pmatrix}
0 & 0 & r_{1}e^{i\theta_{(2,1)}} \\
0 & r_{2}e^{i\theta_{(2,2)}} & 0 \\
r_{3}e^{i\theta_{(2,3)}} & 0 & 0
\end{pmatrix}, \\
\begin{pmatrix}
0 & r_{1}e^{i\theta_{(3,1)}} & 0 \\
r_{2}e^{i\theta_{(3,2)}} & 0 & 0 \\
0 & 0 & r_{3}e^{i\theta_{(3,3)}}
\end{pmatrix}
\end{array} \right\},
θ r ( k , j ) [ D 3 𝕫 ( Y k ) ] = { ( r 1 e i θ ( 1,1 ) 0 0 0 0 r 2 e i θ ( 1,2 ) 0 r 3 e i θ ( 1,3 ) 0 ) , ( 0 0 r 1 e i θ ( 2,1 ) 0 r 2 e i θ ( 2,2 ) 0 r 3 e i θ ( 2,3 ) 0 0 ) , ( 0 r 1 e i θ ( 3,1 ) 0 r 2 e i θ ( 3,2 ) 0 0 0 0 r 3 e i θ ( 3,3 ) ) } . \theta_{r_{(k,j)}}^{\left\lbrack D_{3\mathbb{z}}\left( Y_{k} \right) \right\rbrack} = \left\{ \begin{array}{r}
\begin{pmatrix}
r_{1}e^{i\theta_{(1,1)}} & 0 & 0 \\
0 & 0 & r_{2}e^{i\theta_{(1,2)}} \\
0 & r_{3}e^{i\theta_{(1,3)}} & 0
\end{pmatrix},\begin{pmatrix}
0 & 0 & r_{1}e^{i\theta_{(2,1)}} \\
0 & r_{2}e^{i\theta_{(2,2)}} & 0 \\
r_{3}e^{i\theta_{(2,3)}} & 0 & 0
\end{pmatrix}, \\
\begin{pmatrix}
0 & r_{1}e^{i\theta_{(3,1)}} & 0 \\
r_{2}e^{i\theta_{(3,2)}} & 0 & 0 \\
0 & 0 & r_{3}e^{i\theta_{(3,3)}}
\end{pmatrix}
\end{array} \right\}.
Theorem (1.6.305) – For θ r [ m ] ∞ {\theta_{r}^{\lbrack m\rbrack}}^{\infty} as a set, the set of permutations θ r j [ D 3 𝕫 ( X k , Y k ) ] \theta_{r_{j}}^{\left\lbrack D_{3\mathbb{z}}\left( X_{k},Y_{k} \right) \right\rbrack} forms a group under composition.
Proof – Verification of group axioms
Closure: All elements ∈ θ r [ m ] ∞ \in {\theta_{r}^{\lbrack m\rbrack}}^{\infty} are bijective, and the composition of elements ϕ ∘ ψ ∈ θ r [ m ] ∞ \phi \circ \psi\ \in {\theta_{r}^{\lbrack m\rbrack}}^{\infty} is also bijective.
Associativity: Permutations are functions, and their compositions are associative.
Identity: The identity function ϵ ( Y 1 ) \epsilon_{\left( Y_{1} \right)} bijectively maps all elements in the set θ r [ m ] ∞ {\theta_{r}^{\lbrack m\rbrack}}^{\infty} to themselves ( ϵ ( Y 1 ) : θ r [ m ] ∞ → θ r [ m ] ∞ ) \left( \epsilon_{\left( Y_{1} \right)}:{\theta_{r}^{\lbrack m\rbrack}}^{\infty} \rightarrow {\theta_{r}^{\lbrack m\rbrack}}^{\infty} \right) .
Inverse: ϕ \phi is a permutation and is thus bijective, and there exists a function ϕ − 1 \phi^{- 1} that is also bijective.
□ \square