Masteries · Jason GlowneyArithmoí Book 1

Masteries

1.1.17 The Symmetric/Dihedral Isomorphism

We recall that the S3S_{3} and di­he­dral group D3D_{3} are iso­mor­phic by the De­f­i­n­i­tion (1.1.80), since these are the only group orders (n=3 )(n = 3\ ), in which the con­di­tion n!=2nn! = 2n is met.

De­f­i­n­i­tion (1.1.84) - For two groups GG and G′G^{'} with de­fined binary op­er­a­tions ∘\circ* and* ∗* re­spec­tive­ly, an Iso­mor­phism be­tween these groups exists if the map­ping φ:G→G′\varphi:G \rightarrow G', is a bi­jec­tion from G→G′G \rightarrow G', and if φ(x∘y)=φ(x)∗φ(y)\varphi(x \circ y) = \varphi(x)*\varphi(y), for all x,y∈G.x,y \in G. Two iso­mor­phic groups are de­not­ed as G≅G′.G \cong G^{'}.

As the double-row per­mu­ta­tions of S3S_{3} are in a one-to-one cor­re­spon­dence (bi­jec­tive) with the per­mu­ta­tion ma­tri­ces of D3D_{3}, the binary op­er­a­tion of mul­ti­pli­ca­tion is the same for both groups, im­ply­ing S3≅D3.S_{3} \cong D_{3}.We show the bi­jec­tion be­tween the el­e­ments of each group below.

ϵ=(123123)≅(100010001),  x=(123132)≅(100001010),\epsilon = \begin{pmatrix} 1 & 2 & 3 \\ 1 & 2 & 3 \end{pmatrix} \cong \begin{pmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{pmatrix},\ \ x = \begin{pmatrix} 1 & 2 & 3 \\ 1 & 3 & 2 \end{pmatrix} \cong \begin{pmatrix} 1 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 1 & 0 \end{pmatrix},
y=(123231)≅(010001100),  y2=(123312)≅(001100010),y = \begin{pmatrix} 1 & 2 & 3 \\ 2 & 3 & 1 \end{pmatrix} \cong \begin{pmatrix} 0 & 1 & 0 \\ 0 & 0 & 1 \\ 1 & 0 & 0 \end{pmatrix},\ \ y^{2} = \begin{pmatrix} 1 & 2 & 3 \\ 3 & 1 & 2 \end{pmatrix} \cong \begin{pmatrix} 0 & 0 & 1 \\ 1 & 0 & 0 \\ 0 & 1 & 0 \end{pmatrix},
 xy=(123213)≅(010100001),  xy2=(123321)≅(001010100).\begin{array}{r} \ xy = \begin{pmatrix} 1 & 2 & 3 \\ 2 & 1 & 3 \end{pmatrix} \cong \begin{pmatrix} 0 & 1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 1 \end{pmatrix},\ \ xy^{2} = \begin{pmatrix} 1 & 2 & 3 \\ 3 & 2 & 1 \end{pmatrix} \cong \begin{pmatrix} 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \end{pmatrix}. \end{array}
(1.1.85)