Masteries · Jason GlowneyArithmoí Book 1

Masteries

1.5.1 Tangent Space Angles and Path-Connectedness in the Symmetric Cone Group

In the last chap­ter, we de­rived the sym­met­ric conic group S3ℂΔ\ S_{3\mathbb{C}}^{\Delta} and con­sid­ered some of its sub­groups. The S3ℂΔS_{3\mathbb{C}}^{\Delta} group con­tains many dif­fer­ent geo­met­ric spaces that are path-con­nect­ed on its topo­log­i­cal sur­face of tan­gent spaces, mean­ing we can move freely from one tan­gent space to an­oth­er on the sur­face of the sphere. To demon­strate path-con­nect­ed­ness, we use the ex­am­ple of moving from the from the 𝔗(X1){\mathfrak{T}(X}_{1}) gen­er­a­tor's tan­gent space ∈U(3)\in U(3) to all el­e­ments of the SU(2)SU(2) sub­group in the pos­i­tive X1X_{1}-plane. This is ac­com­plished by using the el­e­ments ∈S3ℂconic\in S_{3\mathbb{C}}^{conic} to form matrix prod­ucts with 𝔗(X1){\mathfrak{T}(X}_{1}),

𝔗(X1)𝓊1→→(i0000i0i0)(−i00010001)=(10000i0i0)=𝓊1,{\mathfrak{T}(X}_{1})\overrightarrow{\mathcal{u}_{1}} \rightarrow \begin{pmatrix} i & 0 & 0 \\ 0 & 0 & i \\ 0 & i & 0 \end{pmatrix}\begin{pmatrix} - i & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{pmatrix} = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 0 & i \\ 0 & i & 0 \end{pmatrix} = \mathcal{u}_{1},
𝔗(X1)𝓊2→→(i0000i0i0)(−i000−i000i)=(10000−1010)=𝓊2,{\mathfrak{T}(X}_{1})\overrightarrow{\mathcal{u}_{2}} \rightarrow \begin{pmatrix} i & 0 & 0 \\ 0 & 0 & i \\ 0 & i & 0 \end{pmatrix}\begin{pmatrix} - i & 0 & 0 \\ 0 & - i & 0 \\ 0 & 0 & i \end{pmatrix} = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 0 & - 1 \\ 0 & 1 & 0 \end{pmatrix} = \mathcal{u}_{2},
𝔗(X1)𝓊3→→(i0000i0i0)(−i0000−1010)=(1000i000−i)=𝓊3,{\mathfrak{T}(X}_{1})\overrightarrow{\mathcal{u}_{3}} \rightarrow \begin{pmatrix} i & 0 & 0 \\ 0 & 0 & i \\ 0 & i & 0 \end{pmatrix}\begin{pmatrix} - i & 0 & 0 \\ 0 & 0 & - 1 \\ 0 & 1 & 0 \end{pmatrix} = \begin{pmatrix} 1 & 0 & 0 \\ 0 & i & 0 \\ 0 & 0 & - i \end{pmatrix} = \mathcal{u}_{3},
𝔗(X1)𝓊ϵ→→(i0000i0i0)(−i0000−i0−i0)=(100010001)=ϵ.\begin{array}{r} {\mathfrak{T}(X}_{1})\overrightarrow{\mathcal{u}_{\epsilon}} \rightarrow \begin{pmatrix} i & 0 & 0 \\ 0 & 0 & i \\ 0 & i & 0 \end{pmatrix}\begin{pmatrix} - i & 0 & 0 \\ 0 & 0 & - i \\ 0 & - i & 0 \end{pmatrix} = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{pmatrix} = \epsilon. \end{array}
(1.5.1)

The 𝓊i→\overrightarrow{\mathcal{u}_{i}} el­e­ments acting to trans­form the 𝔗(X1){\mathfrak{T}(X}_{1}) tan­gent space are char­ac­ter­ized by their axis number de­ter­mi­nants. Having de­fined the sym­me­try group, makes path-con­nect­ed­ness of all the el­e­ments in the tan­gent space pos­si­ble. An­oth­er ex­am­ple serves to demon­strate this, where we use an el­e­ment from the X3,kX_{3,k} sub­group with a cone number de­ter­mi­nant to easily arrive at 𝓊2∈SU(2)\mathcal{u}_{2} \in SU(2), by the prod­uct

𝔗(X3)𝓊2→→(0(−1)340(−1)140000(−1)14)(00(−1)34−(−1)14000−(−1)340)=(10000−1010)=𝓊2.\begin{array}{r} {\mathfrak{T}(X}_{3})\overrightarrow{\mathcal{u}_{2}} \rightarrow \begin{pmatrix} 0 & ( - 1)^{\frac{3}{4}} & 0 \\ ( - 1)^{\frac{1}{4}} & 0 & 0 \\ 0 & 0 & ( - 1)^{\frac{1}{4}} \end{pmatrix}\begin{pmatrix} 0 & 0 & ( - 1)^{\frac{3}{4}} \\ {- ( - 1)}^{\frac{1}{4}} & 0 & 0 \\ 0 & {- ( - 1)}^{\frac{3}{4}} & 0 \end{pmatrix} = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 0 & - 1 \\ 0 & 1 & 0 \end{pmatrix} = \mathcal{u}_{2}. \end{array}
(1.5.2)

This is a process that works by taking ad­van­tage of the fact that every el­e­ment in the sym­met­ric group has an in­verse, per the de­f­i­n­i­tion of a group, and these trans­for­ma­tion re­la­tions can be for­mal­ized as the fol­low­ing trans­form

𝔗(A)B→=C.\begin{array}{r} \mathfrak{T}(A)\overrightarrow{B} = C. \end{array}
(1.5.3)

In the ex­pres­sion above, the matrix 𝔗(A)\mathfrak{T}(A) rep­re­sents the start­ing tan­gent space vector matrix, B→\overrightarrow{B} is the path-con­nect­ing tan­gent vector matrix, and CC is the des­ti­na­tion tan­gent space vector matrix en­abled by the trans­form. Using the matrix prop­er­ties of the in­verse of 𝔗(A)\mathfrak{T}(A), it is simple to find our path-con­nect­ing matrix B→\overrightarrow{B}, since it will be equal to the prod­uct of the in­verse of our start­ing tan­gent space and the des­ti­na­tion tan­gent space

𝔗(A)−1𝔗(A)B→=𝔗(A)−1C→B→=𝔗(A)−1C.\begin{array}{r} \mathfrak{T}(A)^{- 1}\mathfrak{T}(A)\overrightarrow{B}= \mathfrak{T}(A)^{- 1}C \rightarrow \overrightarrow{B}= \mathfrak{T}(A)^{- 1}C. \end{array}
(1.5.4)

The path-con­nect­ed­ness of the S3ℂconicS_{3\mathbb{C}}^{conic} group el­e­ments is so­lid­i­fied by the fol­low­ing the­o­rem.

The­o­rem (1.5.5) – Any el­e­ment ∈AΔ,\in A^{\Delta}, rep­re­sent­ing the set of all per­mu­ta­tions of the sym­met­ric conic group S3ℂΔS_{3\mathbb{C}}^{\Delta}, is path-con­nect­ed to every other el­e­ment by way of an­oth­er el­e­ment ∈AΔ\in A^{\Delta} (AiΔ∘AjΔ→AkΔ)\left( A_{i}^{\Delta} \circ A_{j}^{\Delta} \rightarrow A_{k}^{\Delta} \right).

Proof – S3ℂΔS_{3\mathbb{C}}^{\Delta} is a group under com­po­si­tion where AiΔA_{i}^{\Delta} and AjΔA_{j}^{\Delta} are bi­jec­tive and the com­po­si­tion, AiΔ∘AjΔ→AkΔA_{i}^{\Delta} \circ A_{j}^{\Delta} \rightarrow A_{k}^{\Delta} is thus bi­jec­tive. For every per­mu­ta­tion AiΔA_{i}^{\Delta} there exists a bi­jec­tive func­tion AiΔ−1{A_{i}^{\Delta}}^{- 1}, for which AiΔ−1∘AiΔ→ϵ{A_{i}^{\Delta}}^{- 1} \circ A_{i}^{\Delta} \rightarrow \epsilon. Since S3ℂΔS_{3\mathbb{C}}^{\Delta} is a sym­met­ric group, its bi­jec­tive set of per­mu­ta­tion el­e­ments AΔA^{\Delta} con­tains all pos­si­ble com­bi­na­tions of the set of de­fined cone and axis num­bers, {±1,±i,±(−1)(14),±(−1)(34)}\left\{ \pm 1, \pm i, \pm ( - 1)^{\left( \frac{1}{4} \right)}, \pm ( - 1)^{\left( \frac{3}{4} \right)} \right\}. Given that the in­verse of our start­ing tan­gent space exists AiΔ−1,{A_{i}^{\Delta}}^{- 1}, bi­jec­tiv­i­ty is sat­is­fied, im­ply­ing the el­e­ment AjΔA_{j}^{\Delta} , which path-con­nects two el­e­ments AiΔ,AkΔA_{i}^{\Delta},A_{k}^{\Delta} in the S3ℂΔS_{3\mathbb{C}}^{\Delta} tan­gent space, is also path-con­nect­ed and equal to

AjΔ =AiΔ−1∘AkΔ .A_{j}^{\Delta}\ = {A_{i}^{\Delta}}^{- 1} \circ A_{k}^{\Delta}\ .
□\square