Masteries · Jason GlowneyArithmoí Book 1

Masteries

1.6.2 Infinite Differentiation and the Matrix Logarithm

The matrix ex­po­nen­tial map­ping takes a Lie al­ge­bra to yield its Lie group form, for which, the matrix log­a­rithm can be con­sid­ered the in­verse of the matrix ex­po­nen­tial map­ping and is anal­o­gous to how in­te­gra­tion and dif­fer­en­ti­a­tion are in­verse­ly re­lat­ed. Pre­vi­ous­ly in the book, we touched upon the sim­i­lar­i­ties of in­fi­nite in­te­gra­tion with ex­po­nen­ti­a­tion, and the same like­ness holds for in­fi­nite dif­fer­en­ti­a­tion and the log­a­rithm func­tion. We are al­ready fa­mil­iar with the Lie al­ge­bra's rep­re­sen­ta­tion as the de­riv­a­tive of a matrix group in the neigh­bor­hood of the origin, where for some matrix group G(X)G(X), with its de­riv­a­tive cen­tered at the ar­gu­ment x=0x = 0, yields the Lie al­ge­bra of G(X)G(X)

∂∂x G(X)|x=0=𝔤.\begin{array}{r} \frac{\partial}{\partial x}\left. \ G(X) \right|_{x = 0}= \mathfrak{g}. \end{array}
(1.6.2)

Re­call­ing the in­fi­nite in­te­gra­tion de­f­i­n­i­tion in Chap­ter 1, which, for a com­plex-valued vari­able xjx_{j} is

fℂ−∞(𝒸ixj)=limk→∞⁡(D(x)−k[ixj(𝒸k)]) {∀ 𝒸∈ℝ, ∀ ixj∈ℂn }=𝒸eixj,\begin{array}{r} f_{\mathbb{C}}^{- \infty}\left( \mathcal{c}ix_{j} \right) = \lim_{k \rightarrow \infty}\left( D_{(x)}^{- k}\left\lbrack {{ix}_{j}}{}_{\left( \mathcal{c}_{k} \right)} \right\rbrack \right)\ \left\{ \forall\ \mathcal{c}\in \mathbb{R},\ \forall\ {ix}_{j} \in \mathbb{C}^{n}\ \right\} = {\mathcal{c}e}^{ix_{j}}, \end{array}
(1.6.3)

for 𝒸\mathcal{c}, the scalar con­stant of in­te­gra­tion. We offer the ex­am­ple of the in­fi­nite in­te­gra­tion func­tion fℂ−∞(𝒸ixj)f_{\mathbb{C}}^{- \infty}\left( \mathcal{c}ix_{j} \right), for xj=(−1)14(x)∈ℂx_{j} = ( - 1)^{\frac{1}{4}}(x)\in \mathbb{C}, 𝒸=1\mathcal{c} = 1, which takes on the form of the in­fi­nite series

fℂ−∞((−1)14(x))=…+((−1)14(x))55!+((−1)14(x))44!+((−1)14(x))33!+((−1)14(x))22!+((−1)14(x))11!+((−1)14(x))00!,\begin{array}{r} f_{\mathbb{C}}^{- \infty}\left( ( - 1)^{\frac{1}{4}}(x) \right) = \ldots + \frac{\left( ( - 1)^{\frac{1}{4}}(x) \right)^{5}}{5!} + \frac{\left( ( - 1)^{\frac{1}{4}}(x) \right)^{4}}{4!} + \frac{\left( ( - 1)^{\frac{1}{4}}(x) \right)^{3}}{3!} \\ + \frac{\left( ( - 1)^{\frac{1}{4}}(x) \right)^{2}}{2!} + \frac{\left( ( - 1)^{\frac{1}{4}}(x) \right)^{1}}{1!} + \frac{\left( ( - 1)^{\frac{1}{4}}(x) \right)^{0}}{0!}, \end{array}
(1.6.4)

and this sum­ma­tion re­lates to the Lie al­ge­bra, as

∑n=0∞((−1)14(x))nn!=exp:𝔤→G ∀ 𝔤={(−1)14(x)}.\begin{array}{r} \sum_{n = 0}^{\infty}\frac{\left( ( - 1)^{\frac{1}{4}}(x) \right)^{n}}{n!} = exp:\mathfrak{g} \rightarrow G\ \forall\ \mathfrak{g} =\left\{ ( - 1)^{\frac{1}{4}}(x) \right\}. \end{array}
(1.6.5)

The con­nec­tion be­tween the de­riv­a­tive, for its ar­gu­ment cen­tered at x=0x = 0, and the in­fi­nite in­te­gra­tion func­tion above, is lo­cat­ed at the in­fi­nite series' first power,

∂∂x G((−1)14(x))|(−1)14(x)=0=((−1)14(1))11!=(−1)14=𝔤.\begin{array}{r} \frac{\partial}{\partial x}\left. \ G\left( ( - 1)^{\frac{1}{4}}(x) \right) \right|_{( - 1)^{\frac{1}{4}}(x) = 0} = \frac{\left( ( - 1)^{\frac{1}{4}}(1) \right)^{1}}{1!} = ( - 1)^{\frac{1}{4}}= \mathfrak{g}. \end{array}
(1.6.6)

To define in­fi­nite dif­fer­en­ti­a­tion, we choose a vari­able θrm=rθ(m)\theta_{r}^{m} = {r\theta}^{(m)}, for θ(m)\theta^{(m)}, a uni­tary mm-di­men­sion­al square matrix rep­re­sent­ing a Lie al­ge­bra el­e­ment ∈ℂm\in \mathbb{C}^{m}, for |θ(m)|=ϵ\left| \theta^{(m)} \right| = \epsilon, with matrix en­tries on the bound­ary, rep­re­sent­ing the sphere of tan­gent spaces for rr, a radial mod­u­lus ∈ℝ\in \mathbb{R}.

It should be noted that the choice of vari­able θrm=rθ(m)\theta_{r}^{m} = {r\theta}^{(m)}, is com­posed of the angle vari­able θ(m)\theta^{(m)}, from the ex­po­nen­tial map­ping eiθ(m)e^{i\theta_{(m)}}, and a radial com­po­nent rr, con­sis­tent with the polar form's mod­u­lus. Since there are two in­de­pen­dent vari­ables in the equiv­a­lence rθ(m)=reiθ(m){r\theta}^{(m)} = re^{i\theta_{(m)}}, there are more than one way to ap­proach its cal­cu­lus, in terms of in­te­gra­tion and dif­fer­en­ti­a­tion. So, we might con­sid­er in­te­grals and de­riv­a­tives with re­spect to θrm\theta_{r}^{m}, and or with re­spect to rr and θ(m)\theta_{(m)} in­di­vid­u­al­ly. This is anal­o­gous to taking a com­plex number z=(a+ib)z = (a + ib), to then con­sid­er its polar form z=reiθz = re^{i\theta}, as

z=|z|eitan−1⁡(ba).\begin{array}{r} z = |z|e^{i\tan^{- 1}\left( \frac{b}{a} \right)}. \end{array}
(1.6.7)

For rr, de­fined as

r=|z|=(a+ib)(a−ib)=a2+b2,\begin{array}{r} r = |z| = \sqrt{(a + ib)(a - ib)} = \sqrt{a^{2} + b^{2}}, \end{array}
(1.6.8)

and θ\theta, as

θ=tan−1⁡(ba),\begin{array}{r} \theta = \tan^{- 1}\left( \frac{b}{a} \right), \end{array}
(1.6.9)

this gives us z=reiθz = re^{i\theta}, which is anal­o­gous to our vari­able ex­pres­sion θrm=reiθ(m)\theta_{r}^{m} = re^{i\theta_{(m)}}. Taking the de­riv­a­tive with re­spect to θrm\theta_{r}^{m}, as ∂θrm\partial\theta_{r}^{m}, it would then be the same dif­fer­en­ti­a­tion ap­proach as con­sid­er­ing ∂z(z)\partial z(z). For ex­am­ple, con­cern­ing the dif­fer­en­tial, for ∂θrm(θrm55!)\partial\theta_{r}^{m}\left( \frac{{\theta_{r}^{m}}^{5}}{5!} \right), we would find

∂∂θrm(θrm55!)=5×θrm45!=θrm44!.\begin{array}{r} \frac{\partial}{\partial\theta_{r}^{m}}\left( \frac{{\theta_{r}^{m}}^{5}}{5!} \right) = \frac{5 \times {\theta_{r}^{m}}^{4}}{5!} = \frac{{\theta_{r}^{m}}^{4}}{4!}. \end{array}
(1.6.10)

As is the case for z=reiθz = re^{i\theta}, taking de­riv­a­tives with re­spect to the in­di­vid­ual in­de­pen­dent vari­ables r,θ(m)r,\theta_{(m)}, for the func­tion, reiθ(m)re^{i\theta_{(m)}}, gives us dif­fer­ent re­sults

∂∂r((reiθ(m))55!)=∂∂r(r5e5iθ(m)5!)=r4e5iθ(m)4!,\frac{\partial}{\partial r}\left( \frac{\left( re^{i\theta_{(m)}} \right)^{5}}{5!} \right) = \frac{\partial}{\partial r}\left( \frac{{r^{5}e}^{5i\theta_{(m)}}}{5!} \right) = \frac{{r^{4}e}^{5i\theta_{(m)}}}{4!},
∂∂θ(m)((reiθ(m))55!)=∂∂𝒶m(r5e5iθ(m)5!)=ir5e5iθ(m)4!.\begin{array}{r} \frac{\partial}{\partial\theta_{(m)}}\left( \frac{\left( re^{i\theta_{(m)}} \right)^{5}}{5!} \right) = \frac{\partial}{\partial\mathcal{a}^{m}}\left( \frac{{r^{5}e}^{5i\theta_{(m)}}}{5!} \right) = \frac{{{ir}^{5}e}^{5i\theta_{(m)}}}{4!}. \end{array}
(1.6.11)

The same holds true con­cern­ing in­te­grals, as it ap­plies to what vari­able we are in­te­grat­ing with re­spect to, which is ev­i­denced by in­te­gra­tion with re­spect to θrm\theta_{r}^{m}, θ(m), and r\theta_{(m)},\ \text{and}\ r:

∫reiθ(m) dθrm=(reiθ(m))22,\begin{array}{r} \int_{}^{}{{re}^{i\theta_{(m)}}\ d\theta_{r}^{m} = \frac{\left( {re}^{i\theta_{(m)}} \right)^{2}}{2}}, \end{array}
(1.6.12)
∫reiθ(m) dθ(m)=−ireiθ(m),\begin{array}{r} \int_{}^{}{{re}^{i\theta_{(m)}}\ d\theta_{(m)} = {- ire}^{i\theta_{(m)}}}, \end{array}
(1.6.13)
∫reiθ(m) dr=r2eiθ(m)2,\begin{array}{r} \int_{}^{}{{re}^{i\theta_{(m)}}\ dr = \frac{{r^{2}e}^{i\theta_{(m)}}}{2}}, \end{array}
(1.6.14)

in which, no con­stants of in­te­gra­tion have been as­sumed,

fℂ−∞(𝒸ixj)=limk→∞⁡(D(x)−k[ixj(𝒸k)]) {∀ 𝒸∈ℝ, ∀ ixj∈ℂn }=𝒸eixj.f_{\mathbb{C}}^{- \infty}\left( \mathcal{c}ix_{j} \right) = \lim_{k \rightarrow \infty}\left( D_{(x)}^{- k}\left\lbrack {{ix}_{j}}{}_{\left( \mathcal{c}_{k} \right)} \right\rbrack \right)\ \left\{ \forall\ \mathcal{c}\in \mathbb{R},\ \forall\ {ix}_{j} \in \mathbb{C}^{n}\ \right\} = {\mathcal{c}e}^{ix_{j}}.

De­f­i­n­i­tion (1.6.15) – For the matrix group eθrme^{\theta_{r}^{m}}, for θrm∈ℂ\theta_{r}^{m}\in \mathbb{C}, a Lie al­ge­bra el­e­ment of an mm-di­men­sion­al vector space, and for rr, a scalar con­stant,, the In­fi­nite Dif­fer­en­tial Func­tion 𝐟ℂ𝐧(𝐞𝛉𝐫𝐦)\mathbf{f}_{\mathbb{C}}^{\mathbf{n}}\left( \mathbf{e}^{\mathbf{\theta}_{\mathbf{r}}^{\mathbf{m}}} \right), starts at the in­fin­i­ty-point of the in­fi­nite in­te­gra­tion func­tion, and is de­fined

fℂ∞(eθrm)=limk→∞−2⁡(D(θrm)k[fℂ−∞(eθrm)])=( ∂n∂(θrm)n…|n:∞→2−ϵ) {∀ r,θ∈ℝ }=θrm=reiθ,\begin{array}{r} f_{\mathbb{C}}^{\infty}\left( e^{\theta_{r}^{m}} \right) = \lim_{k \rightarrow \infty - 2}\left( D_{\left( \theta_{r}^{m} \right)}^{k}\left\lbrack f_{\mathbb{C}}^{- \infty}\left( e^{\theta_{r}^{m}} \right) \right\rbrack \right) = \left( \left. \ \dddot{\frac{\partial^{n}}{\partial\left( \theta_{r}^{m} \right)^{n}}} \right|_{n:\infty \rightarrow 2} - \epsilon \right)\ \left\{ \forall\ r,\theta\in \mathbb{R}\ \right\} = \theta_{r}^{m} = re^{i\theta}, \end{array}

for fℂn(θrm)= fℂ−n(θrm)−1{f_{\mathbb{C}}^{n}\left( \theta_{r}^{m} \right) = \ f}_{\mathbb{C}}^{- n}\left( \theta_{r}^{m} \right)^{- 1}, the in­verse of the in­fi­nite in­te­gra­tion func­tion, and for the func­tion

( ∂n∂(θrm)n…|n:∞→2−ϵ),\left( \left. \ \dddot{\frac{\partial^{n}}{\partial\left( \theta_{r}^{m} \right)^{n}}} \right|_{n:\infty \rightarrow 2} - \epsilon \right),

with el­lipses above ∂n\partial^{n}, defin­ing a re­peat­ing dif­fer­en­ti­a­tion process, for nn start­ing at ∞\infty and ending at 2.2.

The­o­rem (1.6.16) – Taking a matrix group gen­er­a­tor G(θrm)G\left( \theta_{r}^{m} \right), the result of the matrix ex­po­nen­tial map­ping of a Lie al­ge­bra el­e­ment θrm∈𝔤,\theta_{r}^{m}\in \mathfrak{g}, the func­tion fℂn(eθrm)f_{\mathbb{C}}^{n}\left( e^{\theta_{r}^{m}} \right) is equiv­a­lent to the matrix log­a­rithm map­ping ln:Gx→𝔤∈ℂln:G_{x}\rightarrow \mathfrak{g}\in \mathbb{C}, onto a con­tin­u­ous man­i­fold, that is the sphere of tan­gent spaces ∀ G(θrm)=eθrm\forall\ G\left( \theta_{r}^{m} \right) = e^{\theta_{r}^{m}}.

Proof – As we have al­ready proven in The­o­rem (1.5.31), the matrix log­a­rithm of* eX is equal to Xe^{X}\ is\ equal\ to\ X*, or ln⁡(eX)=X\ln\left( e^{X} \right) = X. We state that ∀\forall G(θrm)G\left( \theta_{r}^{m} \right), with θrm∈𝔤\theta_{r}^{m}\in \mathfrak{g}, that the matrix log­a­rithm maps G(θrm)G\left( \theta_{r}^{m} \right) onto θrm\theta_{r}^{m}

 ∀ G(θrm)=eθrm,   ln⁡:G(θrm)→θrm.\begin{array}{r} \ \forall\ G\left( \theta_{r}^{m} \right) = e^{\theta_{r}^{m}},\ \ \ \ln{:G\left( \theta_{r}^{m} \right)} \rightarrow \theta_{r}^{m}. \end{array}

Since we have de­fined the in­fin­i­ty-point of the in­fi­nite in­te­gra­tion func­tion as the start­ing point of our in­fi­nite dif­fer­en­ti­a­tion, we know that for

fℂ−n(θrm)=(θrm)∞∞!+(θrm)∞−1(∞−1)!+…+(θrm)33!+(θrm)22!+(θrm)11!+(θrm)00!=eθrm,f_{\mathbb{C}}^{- n}\left( \theta_{r}^{m} \right) = \frac{\left( \theta_{r}^{m} \right)^{\infty}}{\infty!} + \frac{\left( \theta_{r}^{m} \right)^{\infty - 1}}{(\infty - 1)!} + \ldots + \frac{\left( \theta_{r}^{m} \right)^{3}}{3!} + \frac{\left( \theta_{r}^{m} \right)^{2}}{2!} + \frac{\left( \theta_{r}^{m} \right)^{1}}{1!} + \frac{\left( \theta_{r}^{m} \right)^{0}}{0!} = e^{\theta_{r}^{m}},

as nn goes from ∞→1\infty \rightarrow 1, values for (θrm)nn!\frac{\left( \theta_{r}^{m} \right)^{n}}{n!}, remain syn­chro­nous, where

((θrm)∞∞!→(θrm)11!)=(r∞(eiθ)∞∞!→r1(eiθ)11!),\left( \frac{\left( \theta_{r}^{m} \right)^{\infty}}{\infty!} \rightarrow \frac{\left( \theta_{r}^{m} \right)^{1}}{1!} \right) = \left( \frac{{r^{\infty}\left( e^{i\theta} \right)}^{\infty}}{\infty!} \rightarrow \frac{{r^{1}\left( e^{i\theta} \right)}^{1}}{1!} \right),

re­sult­ing in the Lie al­ge­bra matrix θrm\theta_{r}^{m}, that is at the same start­ing point on the sphere of tan­gent spaces before the in­fi­nite in­te­gra­tion process. As such, we follow the dif­fer­en­ti­a­tion process start­ing at the in­fin­i­ty-point el­e­ment of the in­fi­nite series, rep­re­sent­ing the ex­po­nen­tial series eθrme^{\theta_{r}^{m}}, to arrive at the value n=1n = 1,

fℂ∞((θrm)∞∞!)=((θrm)∞−1(∞−1)!)→((θrm)∞−2(∞−2)!)→…→((θrm)(∞−(∞−2))(∞−(∞−2))!)→(((θrm)11!)+((θrm)00!)−ϵ)=((𝛉𝐫𝐦)𝟏𝟏!),f_{\mathbb{C}}^{\infty}\left( \frac{\left( \theta_{r}^{m} \right)^{\infty}}{\infty!} \right) = \left( \frac{\left( \theta_{r}^{m} \right)^{\infty - 1}}{(\infty - 1)!} \right) \rightarrow \left( \frac{\left( \theta_{r}^{m} \right)^{\infty - 2}}{(\infty - 2)!} \right) \rightarrow \ldots \rightarrow \left( \frac{\left( \theta_{r}^{m} \right)^{\left( \infty - (\infty - 2) \right)}}{\left( \infty - (\infty - 2) \right)!} \right) \rightarrow \left( \left( \frac{\left( \theta_{r}^{m} \right)^{1}}{1!} \right) + \left( \frac{\left( \theta_{r}^{m} \right)^{0}}{0!} \right) - \epsilon \right)\mathbf{=}\left( \frac{\left( \mathbf{\theta}_{\mathbf{r}}^{\mathbf{m}} \right)^{\mathbf{1}}}{\mathbf{1}!} \right)\mathbf{,}
∴fℂ∞(eθrm)=((θrm)11!)=θrm=ln⁡(eθrm).\therefore f_{\mathbb{C}}^{\infty}\left( e^{\theta_{r}^{m}} \right) = \left( \frac{\left( \theta_{r}^{m} \right)^{1}}{1!} \right)\mathbf{=}\theta_{r}^{m} = \ln{\left( e^{\theta_{r}^{m}} \right).}
□\square

The way we should con­sid­er dif­fer­en­ti­a­tion and in­te­gra­tion is on a con­tin­u­um, where math­e­mat­i­cal­ly con­sid­er­ing the de­riv­a­tive

d2dz2(z)=0,\begin{array}{r} \frac{d^{2}}{dz^{2}}(z) = 0, \end{array}
(1.6.17)

leaves us to ponder where the non-zero value dis­ap­peared to and whether there is some rem­nant of the func­tion that per­sists. Epis­te­mo­log­i­cal­ly, the con­cern arises given a de­riv­a­tive de­fines how a func­tion changes in time, but the phe­nom­e­nol­o­gy of the uni­verse is con­sis­tent with every­thing being in motion. Some­thing may appear static at the macro­scop­ic level, but the mi­cro­scop­ic level re­mains abuzz with dy­nam­ic motion, always chang­ing in time. Any math­e­mat­ics ap­plied to a uni­ver­sal phe­nom­e­non in­clu­sive of zero de­riv­a­tives, is in­com­plete or just plain wrong. The in­fi­nite in­te­gra­tion and dif­fer­en­ti­a­tion de­f­i­n­i­tions give us a glimpse as to how to ap­proach these with math­e­mat­i­cal co­he­sive­ness; by con­sid­er­ing these func­tions as con­tin­u­ous, we would find around the origin, the series

…+r3e3iθ(m)3!+r2e2iθ(m)2!+reiθ(m)1!+r0e0×iθ(m)0!+(−reiθ(m))11!+(−reiθ(m))22!+(−reiθ(m))33!+…,\begin{array}{r} \ldots + \frac{{r^{3}e}^{3i\theta_{(m)}}}{3!} + \frac{{r^{2}e}^{2i\theta_{(m)}}}{2!} + \frac{{re}^{i\theta_{(m)}}}{1!} + \frac{{r^{0}e}^{0 \times i\theta_{(m)}}}{0!} + \frac{\left( - {re}^{i\theta_{(m)}} \right)^{1}}{1!} + \frac{\left( - {re}^{i\theta_{(m)}} \right)^{2}}{2!} + \frac{\left( - {re}^{i\theta_{(m)}} \right)^{3}}{3!} + \ldots, \end{array}
(1.6.18)

rep­re­sent­ing a con­tin­u­um in both the left and right di­rec­tions. This con­tin­u­um re­sults from taking the first in­te­gral to the left of the iden­ti­ty, being pos­i­tive in its angle ar­gu­ment iθ(m)i\theta_{(m)}

+θrm=(a(m)+ib(m))=a(m)2+b(m)2(eitan−1(b(m)a(m)))=reiθ(m)1!,\begin{array}{r} {+ \theta}_{r}^{m} = \left( a_{(m)} + ib_{(m)} \right) = \sqrt{a_{(m)}^{2} + b_{(m)}^{2}}\left( e^{itan^{- 1}\left( \frac{b_{(m)}}{a_{(m)}} \right)} \right) = \frac{{re}^{i\theta_{(m)}}}{1!}, \end{array}
(1.6.19)

and the first in­te­gral to the right, being neg­a­tive in its angle ar­gu­ment iθ(m)i\theta_{(m)}

−θrm=−(a(m)+ib(m))=−a(m)2+b(m)2(eitan−1(b(m)a(m)))=−reiθ(m)1!.\begin{array}{r} {- \theta}_{r}^{m} = - \left( a_{(m)} + ib_{(m)} \right) = - \sqrt{a_{(m)}^{2} + b_{(m)}^{2}}\left( e^{itan^{- 1}\left( \frac{b_{(m)}}{a_{(m)}} \right)} \right) = \frac{- {re}^{i\theta_{(m)}}}{1!}. \end{array}
(1.6.20)

In­te­grat­ing both of these terms on the tan­gent space with re­spect to +θrm{+ \theta}_{r}^{m} and −θrm{- \theta}_{r}^{m}, re­sults in a con­tin­u­ous series in both di­rec­tions, and when taken to in­fin­i­ty con­verges to ereiθ(m)e^{re^{i\theta_{(m)}}}, for the left-sided sum, and con­verges to e−reiθ(m),e^{{- re}^{i\theta_{(m)}}},as the right-sided sum, and both func­tions share the iden­ti­ty r0e0×iθ(m)0!=1\frac{{r^{0}e}^{0 \times i\theta_{(m)}}}{0!} = 1. The prod­uct of the left-hand and right-hand ex­po­nen­tials equals the iden­ti­ty el­e­ment

ereiθ(m)×e−reiθ(m)=ϵ,\begin{array}{r} e^{{re}^{i\theta_{(m)}}} \times e^{- re^{i\theta_{(m)}}} = \epsilon, \end{array}
(1.6.21)

mean­ing that they are in­verse­ly cor­re­lat­ed. This in­verse prod­uct is the net-zero point, and rep­re­sents the iden­ti­ty ϵ=e0\epsilon = e^{0}.

Given that, θrm=\theta_{r}^{m} = reiθ(m){re}^{i\theta_{(m)}}, we can also con­sid­er taking the de­riv­a­tive with re­spect to the tan­gent space vari­able θ(m)\theta_{(m)}, for the con­tin­u­ous func­tion eiθ(m)e^{i\theta_{(m)}}. Start­ing with the first de­riv­a­tive with re­spect to θ(m)\theta_{(m)}, for the in­fi­nite series ereiθ(m)e^{re^{i\theta_{(m)}}}, and for (reiθ(m))00!=ϵ\frac{\left( {re}^{i\theta_{(m)}} \right)^{0}}{0!} = \epsilon, we find

ddθ(m)(…+r3(eiθ(m))33!+r2(eiθ(m))22!+r1(eiθ(m))11!+ϵ)=…+ir3e3iθ(m)2!+ir2e2iθ(m)1!+ir1eiθ(m)1!+0,\begin{array}{r} \frac{d}{d\theta_{(m)}}\left( \ldots + \frac{{r^{3}\left( e^{i\theta_{(m)}} \right)}^{3}}{3!} + \frac{{r^{2}\left( e^{i\theta_{(m)}} \right)}^{2}}{2!} + \frac{{r^{1}\left( e^{i\theta_{(m)}} \right)}^{1}}{1!} + \epsilon \right) \\ = \ldots + \frac{ir^{3}e^{3i\theta_{(m)}}}{2!} + \frac{{ir^{2}e}^{2i\theta_{(m)}}}{1!} + \frac{{ir^{1}e}^{i\theta_{(m)}}}{1!} + 0, \end{array}
(1.6.22)

in which the iden­ti­ty van­ish­es. If we pro­ceed with the next de­riv­a­tive

d2dθ(m)2(…+r3(eiθ(m))33!+r2(eiθ(m))22!+r1(eiθ(m))11!+ϵ)\frac{d^{2}}{d\theta_{(m)}^{2}}\left( \ldots + \frac{{r^{3}\left( e^{i\theta_{(m)}} \right)}^{3}}{3!} + \frac{{r^{2}\left( e^{i\theta_{(m)}} \right)}^{2}}{2!} + \frac{{r^{1}\left( e^{i\theta_{(m)}} \right)}^{1}}{1!} + \epsilon \right)
=…−3r3e3iθ(m)2!−2r2e2iθ(m)1!−r1eiθ(m)1!,\begin{array}{r} = \ldots - \frac{3r^{3}e^{3i\theta_{(m)}}}{2!} - \frac{{2r^{2}e}^{2i\theta_{(m)}}}{1!} - \frac{{r^{1}e}^{i\theta_{(m)}}}{1!}, \end{array}
(1.6.23)

we find the con­ti­nu­ity of the func­tion eiθ(m)e^{i\theta_{(m)}}, leaves the el­e­ments intact, and ro­tates the series by an­oth­er iπ2\frac{i\pi}{2} ra­di­ans, while scal­ing the el­e­ments by re­spec­tive mag­ni­tudes stem­ming from the power rule of dif­fer­en­ti­a­tion.

Nor­mal­ly taking the de­riv­a­tive of (θrm)00!\frac{\left( \theta_{r}^{m} \right)^{0}}{0!}, in­ter­prets a result equal to zero

ddθrm((θrm)00!)=0,\begin{array}{r} \frac{d}{d\theta_{r}^{m}}\left( \frac{\left( \theta_{r}^{m} \right)^{0}}{0!} \right) = 0, \end{array}
(1.6.24)

which in the case of the equiv­a­lence θrm=reiθ(m)\theta_{r}^{m} = {re}^{i\theta_{(m)}}, this rep­re­sents the point where the radial ex­ten­sion for rr, ceases to exist beyond the bound­ary of the in­fi­nite sphere of tan­gent spaces. It is at this bound­ary that we find our­selves at the iden­ti­ty el­e­ments of the in­fi­nite sym­me­try group, de­fined in the last chap­ter, for S3ℂϵ∈S3ℂ∞S_{3\mathbb{C}}^{\epsilon} \in S_{3\mathbb{C}}^{\infty}, which are part of the Lie al­ge­bra sub­group set 𝔰3ℂϵ∈𝔰3ℂ∞\mathfrak{s}_{3\mathbb{C}}^{\epsilon} \in \mathfrak{s}_{3\mathbb{C}}^{\infty}. The most im­por­tant math­e­mat­i­cal con­cept is that the sin­gu­lar­i­ty per­sists de­spite the ex­tend­ed ex­po­nen­tial form ceas­ing to exist. In­stead, if we define the de­riv­a­tive of a con­stant value as some­thing that exists in the sin­gu­lar­i­ty, away from the ini­tial ex­tend­ed space where the rr vari­able acts in, we can con­sid­er in­verse el­e­ments of the power rule for de­riv­a­tives. Start­ing at (θrm)00!\frac{\left( \theta_{r}^{m} \right)^{0}}{0!}, we can con­tin­ue for nn, as it goes from 0→−∞0 \rightarrow - \infty

dnd(θrm)n((θrm)00!)=(0!θrm−1!(θrm)2+2!(θrm)3−3!(θrm)4+4!(θrm)5−…).\begin{array}{r} \frac{d^{n}}{d\left( \theta_{r}^{m} \right)^{n}}\left( \frac{\left( \theta_{r}^{m} \right)^{0}}{0!} \right) = \left( \frac{0!}{\theta_{r}^{m}} - \frac{1!}{\left( \theta_{r}^{m} \right)^{2}} + \frac{2!}{\left( \theta_{r}^{m} \right)^{3}} - \frac{3!}{\left( \theta_{r}^{m} \right)^{4}} + \frac{4!}{\left( \theta_{r}^{m} \right)^{5}} - \ldots \right). \end{array}
(1.6.25)

which rep­re­sents the in­fi­nite series,

∑n=1∞(−1)n−1Γ(n)(θrm)n,   (n∈ℤ+),\begin{array}{r} \sum_{n = 1}^{\infty}\frac{( - 1)^{n - 1}\Gamma(n)}{\left( \theta_{r}^{m} \right)^{n}},\ \ \ \left( n \in \mathbb{Z}^{+} \right), \end{array}
(1.6.26)

for Γ(n)=(n−1)!\Gamma(n) = (n - 1)!, the gamma func­tion. The ratio test for the series above di­verges

limn→∞⁡|((−1)nΓ(n+1)(θrm)n+1)((−1)n−1Γ(n)(θrm)n)|=limn→∞⁡(nreiθ(m))=∞,\begin{array}{r} \lim_{n \rightarrow \infty}{\left| \frac{\left( \frac{( - 1)^{n}\Gamma(n + 1)}{\left( \theta_{r}^{m} \right)^{n + 1}} \right)}{\left( \frac{( - 1)^{n - 1}\Gamma(n)}{\left( \theta_{r}^{m} \right)^{n}} \right)} \right| = \lim_{n \rightarrow \infty}\left( \frac{n}{re^{i\theta_{(m)}}} \right)} = \infty, \end{array}
(1.6.27)

in­creas­ing un­bound­ed as n→∞n \rightarrow \infty, due to the pres­ence of the fac­to­r­i­al func­tion in the series nu­mer­a­tor. If we con­sid­er the fol­low­ing el­e­ment-by-el­e­ment prod­uct of the in­fi­nite de­riv­a­tive series with the ex­po­nen­tial series start­ing at n=1n = 1

∑n=1∞((−1)n−1Γ(n)(θrm)n×(θrm)nn!)=∑n=1∞(−1)n−1n=1−12+13−14+…=ln⁡(2),\begin{array}{r} \sum_{n = 1}^{\infty}{\left( \frac{( - 1)^{n - 1}\Gamma(n)}{\left( \theta_{r}^{m} \right)^{n}} \times \frac{\left( \theta_{r}^{m} \right)^{n}}{n!} \right) =}\sum_{n = 1}^{\infty}\frac{( - 1)^{n - 1}}{n} = 1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \ldots = \ln(2), \end{array}
(1.6.28)

we find the al­ter­nat­ing har­mon­ic series for a result, which con­verges to ln⁡(2).\ln(2).It should be noted that the ex­po­nen­tial series

∑n=1∞((θrm)nn!)=eθrm−ϵ,\begin{array}{r} \sum_{n = 1}^{\infty}{\left( \frac{\left( \theta_{r}^{m} \right)^{n}}{n!} \right) = e^{\theta_{r}^{m}} - \epsilon,} \end{array}
(1.6.29)

rep­re­sents the series of the matrix ex­po­nen­tial eθrme^{\theta_{r}^{m}}, minus the iden­ti­ty ϵ\epsilon. So, the ap­pear­ance of the al­ter­nat­ing har­mon­ic series clues us in that the log­a­rithm func­tion is close­ly re­lat­ed, and it re­veals itself when we con­sid­er the "zero-point", as equal to (0!θrm)\left( \frac{0!}{\theta_{r}^{m}} \right), from the series above. If we re­verse di­rec­tions and take the in­te­gral of (0!θrm)\left( \frac{0!}{\theta_{r}^{m}} \right), we find our log­a­rithm func­tion

∫0!θrmdθrm=∫1θrm1tdt=ln⁡(θrm).\begin{array}{r} \int_{}^{}\frac{0!}{\theta_{r}^{m}}d\theta_{r}^{m} = \int_{1}^{\theta_{r}^{m}}{\frac{1}{t}dt =}\ln\left( \theta_{r}^{m} \right). \end{array}
(1.6.30)

As we have de­fined, θrm=reiθ(m)\theta_{r}^{m} = {re}^{i\theta_{(m)}}, and its log­a­rithm will be equal to

ln⁡(θrm)=ln⁡(reiθ(m))=ln⁡(eiθ(m))+ln⁡(r)=iθ(m)+ln⁡(r).\begin{array}{r} \ln\left( \theta_{r}^{m} \right) = \ln\left( {re}^{i\theta_{(m)}} \right) = \ln{\left( e^{i\theta_{(m)}} \right) + \ln(r) = i\theta_{(m)}} + \ln(r). \end{array}
(1.6.31)

This rep­re­sents a pro­found result, given it is equiv­a­lent to the log­a­rith­mic sub­tan­gent space from De­f­i­n­i­tion (1.5.121)

𝒯(𝔗(S3ℂ∞))=ln⁡(𝔗(S3ℂ∞))=𝒯ln⁡(𝔰3ℂ∞),\begin{array}{r} \mathcal{T}\left( \mathfrak{T}\left( S_{3\mathbb{C}}^{\infty} \right) \right) = \ln{\left( \mathfrak{T}\left( S_{3\mathbb{C}}^{\infty} \right) \right) = \mathcal{T}_{\ln}\left( \mathfrak{s}_{3\mathbb{C}}^{\infty} \right)}, \end{array}
(1.6.32)

for 𝒯ln⁡(𝔰3ℂ∞)\mathcal{T}_{\ln}\left( \mathfrak{s}_{3\mathbb{C}}^{\infty} \right), de­fined as the in­fi­nite log­a­rith­mic sub­tan­gent space. The equiv­a­lence is better ap­pre­ci­at­ed by the fol­low­ing

𝒯(𝔗(S3ℂ∞))=𝒯(𝔗(ereiθ(m)))=ln⁡(ln⁡(ereiθ(m)))=ln⁡(reiθ(m))=ln⁡(r)+ln⁡(eiθ(m))=ln⁡(r)+iθ(m)\begin{array}{r} \mathcal{T}\left( \mathfrak{T}\left( S_{3\mathbb{C}}^{\infty} \right) \right)= \mathcal{T}\left( \mathfrak{T}\left( e^{{re}^{i\theta_{(m)}}} \right) \right) = \ln\left( \ln\left( e^{{re}^{i\theta_{(m)}}} \right) \right){= \ln}\left( {re}^{i\theta_{(m)}} \right) \\ = \ln{(r) +}\ln\left( e^{i\theta_{(m)}} \right) = \ln(r) + i\theta_{(m)} \end{array}
(1.6.33)

for iθ(m)i\theta_{(m)}, the m×mm \times m set of angle ar­gu­ments, which de­fines the sub­tan­gent space.

To step up from the sub­tan­gent space into the tan­gent space, re­quires taking the matrix ex­po­nen­tial of the sub­tan­gent space al­ge­bra. The sub­tan­gent space rep­re­sents the angle space of the in­fi­nite sym­me­try group S3ℂ∞S_{3\mathbb{C}}^{\infty}, and con­cep­tu­al­ly like im­pulse forms, trans­form­ing through ex­po­nen­ti­a­tion, to define the struc­ture of the group's tan­gent space on the sphere of tan­gent spaces. The im­por­tant notion is that the sub­tan­gent space lays hidden in the "zero-point" and is be­neath the sphere of tan­gent spaces' sur­face.

Given, r∈ℝr\in \mathbb{R}, the func­tion ln⁡(r)\ln(r) will have pos­i­tive values for r>1r > 1, while taking on neg­a­tive values for r<1r < 1, and rapid­ly goes to neg­a­tive in­fin­i­ty for the rr-in­ter­val, from 1→01 \rightarrow 0(Figure 1.6.5).

Figure
Figure 1.6.5 – Plot of ln⁡(r)\ln(r), for r=[−2π,2π]r = \lbrack - 2\pi,2\pi\rbrack.

Con­cep­tu­al­ly, and in terms of the sin­gu­lar­i­ty, the result, ln⁡(r)=0\ln(r) = 0, rep­re­sents the crit­i­cal point or the "zero-point" lo­ca­tion, at which, moving fur­ther toward the origin for values of rr, from the zero so­lu­tion, ln⁡(1)\ln(1), re­sults in a tran­si­tion from pos­i­tive to neg­a­tive values on the real number con­tin­u­um. For nat­ur­al log­a­rithm re­sults less than zero, ln⁡(r)<0\ln(r) < 0, it trav­els off to neg­a­tive in­fin­i­ty for the limit as r→0r \rightarrow 0, while for values ln⁡(r)>0\ln(r) > 0, it will ap­proach pos­i­tive in­fin­i­ty albeit at a much slower rate, for the limit as r→∞.r \rightarrow \infty.When we con­sid­er the value 𝒸\mathcal{c}, as our con­stant of in­te­gra­tion, for the zero in­te­gral

∫0 dθrm=𝒸,\begin{array}{r} \int_{}^{}{0\ d\theta_{r}^{m}= \mathcal{c}}, \end{array}
(1.6.34)

this is the same choice of in­te­gra­tion con­stant from the in­fi­nite in­te­gra­tion func­tion. Fur­ther, by choos­ing 𝒸=ln⁡(e)=1\mathcal{c} =\ln(e) = 1, we find the fa­mil­iar result

fℂ−∞(𝒸θrm)=limk→∞⁡(D(θrm)−k[𝒸θrm]) {𝒸=ln⁡(e), ∀ θrm∈ℂm }=eθrm.\begin{array}{r} f_{\mathbb{C}}^{- \infty}\left( \mathcal{c}\theta_{r}^{m} \right) = \lim_{k \rightarrow \infty}\left( D_{\left( \theta_{r}^{m} \right)}^{- k}\left\lbrack \mathcal{c}\theta_{r}^{m} \right\rbrack \right)\ \left\{ \mathcal{c} =\ln(e),\ \forall\ \theta_{r}^{m} \in \mathbb{C}^{m}\ \right\} = e^{\theta_{r}^{m}}. \end{array}
(1.6.35)

We can define the in­fi­nite dif­fer­en­tial func­tion fℂ∞(𝒸eθrm)f_{\mathbb{C}}^{\infty}\left( \mathcal{c}e^{\theta_{r}^{m}} \right), as the de­riv­a­tive of the in­fi­nite in­te­gra­tion func­tion at the point θrm=0\theta_{r}^{m} = 0, which is in­ti­mate­ly linked to how the de­riv­a­tive of a Lie group, cen­tered at θ=0\theta = 0, yields the Lie al­ge­bra by way of the tan­gent space, and we can char­ac­ter­ize this in terms of the in­fi­nite dif­fer­en­tial func­tion, as

fℂ∞(𝒸eθrm)= D(θrm)k[fℂ−∞(𝒸θrm)]|θrm=0 .\begin{array}{r} f_{\mathbb{C}}^{\infty}\left( \mathcal{c}e^{\theta_{r}^{m}} \right) = \left. \ D_{\left( \theta_{r}^{m} \right)}^{k}\left\lbrack f_{\mathbb{C}}^{- \infty}\left( \mathcal{c}\theta_{r}^{m} \right) \right\rbrack \right|_{\theta_{r}^{m} = 0}\ . \end{array}
(1.6.36)

We have seen that the in­fi­nite dif­fer­en­tial func­tion can pro­ceed for both pos­i­tive θrm,\theta_{r}^{m},and neg­a­tive θrm,(θrm)−1\theta_{r}^{m},\left( \theta_{r}^{m} \right)^{- 1}, and math­e­mat­i­cal­ly that in­fi­nite dif­fer­en­ti­a­tion in the neg­a­tive di­rec­tion is the in­verse func­tion of in­fi­nite dif­fer­en­ti­a­tion in the pos­i­tive di­rec­tion. Re­gard­ing the func­tion fℂ∞(𝒸eθrm)f_{\mathbb{C}}^{\infty}\left( \mathcal{c}e^{\theta_{r}^{m}} \right), it is re­lat­ed to its in­verse by

fℂ∞(𝒸eθrm)=fℂ∞(𝒸−1e−θrm)−1,\begin{array}{r} f_{\mathbb{C}}^{\infty}\left( \mathcal{c}e^{\theta_{r}^{m}} \right) = f_{\mathbb{C}}^{\infty}\left( \mathcal{c}^{- 1}e^{- \theta_{r}^{m}} \right)^{- 1}, \end{array}
(1.6.37)

and the prod­uct of the func­tion and its in­verse yields the iden­ti­ty

fℂ∞(𝒸eθrm)×fℂ∞(𝒸−1e−θrm)=ϵ.\begin{array}{r} f_{\mathbb{C}}^{\infty}\left( \mathcal{c}e^{\theta_{r}^{m}} \right) \times f_{\mathbb{C}}^{\infty}\left( \mathcal{c}^{- 1}e^{- \theta_{r}^{m}} \right) = \epsilon. \end{array}
(1.6.38)

To show this in­verse re­la­tion­ship, we offer the ex­am­ple for θrm=\theta_{r}^{m} = r(−1)14r( - 1)^{\frac{1}{4}}, rep­re­sent­ing the pos­i­tive di­rec­tion, and −θrm=- \theta_{r}^{m} = −r(−1)14- r( - 1)^{\frac{1}{4}}, as the neg­a­tive di­rec­tion, where­by ap­ply­ing the in­fi­nite in­te­gra­tion func­tions for both, yields

fℂ−∞(r(−1)14)=1+(r(−1)14)11!+(r(−1)14)22!+(r(−1)14)33!+…=er(−1)14,\begin{array}{r} f_{\mathbb{C}}^{- \infty}\left( r( - 1)^{\frac{1}{4}} \right) = 1 + \frac{\left( r( - 1)^{\frac{1}{4}} \right)^{1}}{1!} + \frac{\left( r( - 1)^{\frac{1}{4}} \right)^{2}}{2!} + \frac{\left( r( - 1)^{\frac{1}{4}} \right)^{3}}{3!} + \ldots = e^{r( - 1)^{\frac{1}{4}}}, \end{array}
(1.6.39)
fℂ−∞(r(−1)14)−1=1+(−r(−1)14)11!+(−r(−1)14)22!+(−r(−1)14)33!+…=e−r(−1)14,\begin{array}{r} f_{\mathbb{C}}^{- \infty}\left( r( - 1)^{\frac{1}{4}} \right)^{- 1} = 1 + \frac{\left( - r( - 1)^{\frac{1}{4}} \right)^{1}}{1!} + \frac{\left( - r( - 1)^{\frac{1}{4}} \right)^{2}}{2!} + \frac{\left( - r( - 1)^{\frac{1}{4}} \right)^{3}}{3!} + \ldots = e^{- r( - 1)^{\frac{1}{4}}}, \end{array}
(1.6.40)

and by the prop­er­ties of the ex­po­nen­tial map­ping and ro­ta­tion di­rec­tion, we find these are in­verse­ly re­lat­ed to one an­oth­er

fℂn(r(−1)14)fℂn(r(−1)14)−1=(er(−1)14)(e−r(−1)14)=e0=1.\begin{array}{r} f_{\mathbb{C}}^{n}\left( r( - 1)^{\frac{1}{4}} \right)f_{\mathbb{C}}^{n}\left( r( - 1)^{\frac{1}{4}} \right)^{- 1} = \left( e^{r( - 1)^{\frac{1}{4}}} \right)\left( e^{- r( - 1)^{\frac{1}{4}}} \right) = e^{0} = 1. \end{array}
(1.6.41)

Cal­cu­lat­ing the in­fi­nite dif­fer­en­tial of the func­tions fℂn(r(−1)14),fℂn(r(−1)14)−1f_{\mathbb{C}}^{n}\left( r( - 1)^{\frac{1}{4}} \right),{f_{\mathbb{C}}^{n}\left( r( - 1)^{\frac{1}{4}} \right)}^{- 1}, cen­tered at r=0r = 0, we find

fℂn(r(−1)14)=∂∂r fℂ−n(r(−1)14)|r=0=∂∂r er(−1)14|r=0=(−1)14e0=(−1)14,\begin{array}{r} f_{\mathbb{C}}^{n}\left( r( - 1)^{\frac{1}{4}} \right) = \frac{\partial}{\partial r}\left. \ f_{\mathbb{C}}^{- n}\left( r( - 1)^{\frac{1}{4}} \right) \right|_{r = 0} = \frac{\partial}{\partial r}\left. \ e^{r( - 1)^{\frac{1}{4}}} \right|_{r = 0} = ( - 1)^{\frac{1}{4}}e^{0} = ( - 1)^{\frac{1}{4}}, \end{array}
(1.6.42)
fℂn(e−r(−1)14)=∂∂r fℂ−n(r(−1)14)−1|r=0=∂∂r e−r(−1)14|r=0=−(−1)14e0=−(−1)14,\begin{array}{r} f_{\mathbb{C}}^{n}\left( e^{- r( - 1)^{\frac{1}{4}}} \right) = \frac{\partial}{\partial r}\left. \ f_{\mathbb{C}}^{- n}\left( r( - 1)^{\frac{1}{4}} \right)^{- 1} \right|_{r = 0} = \frac{\partial}{\partial r}\left. \ e^{- r( - 1)^{\frac{1}{4}}} \right|_{r = 0} = {- ( - 1)}^{\frac{1}{4}}e^{0} = {- ( - 1)}^{\frac{1}{4}}, \end{array}
(1.6.43)

where the re­sults rep­re­sent the angle ar­gu­ments.

When con­sid­er­ing the con­tent of this sec­tion and how it re­lates to the in­fi­nite sym­me­try group S3ℂ∞S_{3\mathbb{C}}^{\infty}, dif­fer­en­ti­a­tion and the log­a­rithm func­tion are in­ti­mate­ly re­lat­ed, much the same as the ex­po­nen­tial func­tion is with in­te­gra­tion. There is much more to the "zero-point" that meets the eye ini­tial­ly, once con­sid­ered in the con­text of the sub­tan­gent space.